Convert timestamp like Facebook and Twitter - php

Question

I am fetching time from server like this: 25-07-2015 12:25:28
Now I want to show it like this:
a few second ago
1 minute ago
30 minutes ago
1 Hour ago
12 Hours ago
and after 24 Hours ago
show me the date of that day like :
25 August 2015

Answer 1

the following code works. But no data validation done (eg: old>new)
<?php
$olddate = "25-08-2015 15:35:28"; //date as string
$now = time(); //pick present time from server
$old = strtotime( $olddate); //create integer value of old time
$diff = $now-$old; //calculate difference
$old = new DateTime($olddate);
$old = $old->format('Y M d'); //format date to "2015 Aug 2015" format
if ($diff /60 <1) //check the difference and do echo as required
{
echo intval($diff%60)."seconds ago";
}
else if (intval($diff/60) == 1)
{
echo " 1 minute ago";
}
else if ($diff / 60 < 60)
{
echo intval($diff/60)."minutes ago";
}
else if (intval($diff / 3600) == 1)
{
echo "1 hour ago";
}
else if ($diff / 3600 <24)
{
echo intval($diff/3600) . " hours ago";
}
else if ($diff/86400 < 30)
{
echo intval($diff/86400) . " days ago";
}
else
{
echo $old; ////format date to "2015 Aug 2015" format
}
?>
Change the looping if you can. Logic remains same.

Answer 2

<?php
function timeago($timestamp){
$time_ago = strtotime($timestamp);
$current_time = time();
$time_difference = $current_time - $time_ago;
$seconds = $time_difference;
$minutes = round($seconds / 60); // value 60 is seconds
$hours = round($seconds / 3600); //value 3600 is 60 minutes * 60 sec
$days = round($seconds / 86400); //86400 = 24 * 60 * 60;
$weeks = round($seconds / 604800); // 7*24*60*60;
$months = round($seconds / 2629440); //((365+365+365+365+366)/5/12)*24*60*60
$years = round($seconds / 31553280); //(365+365+365+365+366)/5 * 24 * 60 * 60
if ($seconds <= 60){
return "Just Now";
} else if ($minutes <= 60){
if ($minutes == 1){
return "one minute ago";
} else {
return "$minutes minutes ago";
}
} else if ($hours <= 24){
if ($hours == 1){
return "an hour ago";
} else {
return "$hours hrs ago";
}
} else if ($days <= 7){
if ($days == 1){
return "yesterday";
} else {
return "$days days ago";
}
} else if ($weeks <= 4.3){
if ($weeks == 1){
return "a week ago";
} else {
return "$weeks weeks ago";
}
} else if ($months <= 12){
if ($months == 1){
return "a month ago";
} else {
return "$months months ago";
}
} else {
if ($years == 1){
return "one year ago";
} else {
return "$years years ago";
}
}
}
?>

Answer 3

Have you looked at the Date function in php?