I need to make this print a number with two decimal points, I believe I use this piece of code int $decimals = 0 but I don't know where I need to add it.
Here's the code I have:
<?php
$tempPrice = str_replace(',',"", $price); //gets rid of ","
$tempPrice = substr($tempPrice,2); //removes currency from the front
$tempPrice = floatval($tempPrice); //converts to double from string
if($tempPrice > 1000)
{
echo '£' . round(($tempPrice*0.038), 2) . ' per month';
}
else
{
echo 'Lease to buy price not available on this product';
}
?>
Thanks
You can use money_format() php function. http://php.net/money_format
for example in your case
<?php
$tempPrice = str_replace(',',"", $price); //gets rid of ","
$tempPrice = substr($tempPrice,2); //removes currency from the front
$tempPrice = floatval($tempPrice); //converts to double from string
// set international format for the en_GB locale
setlocale(LC_MONETARY, 'en_GB');
if($tempPrice > 1000)
{
echo money_format('%i', $tempPrice ) . " per month";// output->"GBP 1,234.56 per month"
}
else
{
echo 'Lease to buy price not available on this product';
}
?>
in addition you can just use php number_format() http://php.net/number_format on $tempPrice
echo "£ ". number_format($tempPrice ) . " per month";
by default number_format() english notation is used. You can set your own number of decimal points, decimal point setarator and thousands separator
echo "£ ". number_format($tempPrice, 2, ".", "," ) . " per month"; // for $tempPrice=1203.52 output will be "£ 1,203.56 per month"
Related
I'm new to php and I'm trying to use number_format :
number_format ( float $number , int $decimals = 0 , string $dec_point = "." , string $thousands_sep = "," )
As in the title, my goal is to modify decimal point and thousands separator without changing the number of decimals as below:
$Num=123456.789;
$Num2=number_format ($Num, [decimals as in $Num], ",", "'" );
My result should be:
$Num2="123'456,789";
Edit
I need a code for an unknown number of decimals
You can use NumberFormatter.
You will still need to specify a certain amount of fraction digits, but you can just use a high enough value and be fine. It's not like the number of digits is really arbitrary. It's tied to your precision ini setting.
$formatter = new NumberFormatter("en_US", NumberFormatter::DECIMAL);
$formatter->setAttribute(NumberFormatter::MAX_FRACTION_DIGITS, 42);
$formatter->setSymbol(NumberFormatter::GROUPING_SEPARATOR_SYMBOL, "'");
$formatter->setSymbol(NumberFormatter::DECIMAL_SEPARATOR_SYMBOL, ",");
echo $formatter->format(123456.7891234); // 123'456,7891234
Demo https://3v4l.org/TCAIA
You can do it such a way (firstly take a look to #Gordon answer – it's much more better):
<?php
function extendedNumberFormat($num, $decimalSeparator, $thousandSeparator) {
$asStr = strval($num);
$exploded = explode('.', $asStr);
$int = $exploded[0];
$decimal = isset($exploded[1]) ? $exploded[1] : null;
$result = number_format($int, 0, ".", $thousandSeparator);
if ($decimal !== null) {
$result .= $decimalSeparator . $decimal;
}
return $result;
}
echo extendedNumberFormat(123456.789, ',', "'") . "\n";
echo extendedNumberFormat(123456.7891, ',', "'") . "\n";
echo extendedNumberFormat(123456, ',', "'") . "\n";
//123'456,789
//123'456,7891
//123'456
I am using PHP number_format to express prices of products, using decimal point, thousands separators, etc. For example:
$price = 20.456;
print "$" . number_format($price, 2, ".", ",");
outputs $20.46.
However, I would like that, if the price is integer, for example $price = 20.00, to output $20. Is there some other function or rule to achieve this, avoiding decimal points if not necessary?
Just do a loose comparison of $price cast as integer against $price, if they match (ie. it's a whole number), you can format to 0 decimal places:
number_format($price, ((int) $price == $price ? 0 : 2), '.', ',');
You can use ternary operator fot that:
$price = 20.456;
print "$" . ($price == intval($price) ? number_format($price, 0, "", ",") : number_format($price, 2, "", ","));
Try $price = 20.456 +0 ;
$price + 0 does the trick.
echo 125.00 + 0; // 125
echo '125.00' + 0; // 125
echo 966.70 + 0; // 966.7
Internally, this is equivalent to casting to float with (float)$price or floatval( $price) but I find it simpler.
A little helper function my_format to determine if the number is an integer and then return the corresponding string.
function my_format($number)
{
if (fmod($number, 1) == 0) {
return sprintf("$%d\n", $number);
} else {
return sprintf("$%.2f\n", $number);
}
}
$price = 20.456;
echo my_format($price);
echo my_format(20);
Will output
$20.46 $20
A little solution that works for any number
$price = "20.5498";
$dec = fmod($price, 1);
if($dec > 0)
print "$" . number_format($price, 2, ".", ",");
else
print "$" . floor($price);;
You can use floor() function
$price = 20.456;
echo '$'.floor($price); // output $20
math with bitcoin is giving me problems
$value = bcmul((float)$TotalMoney, $p,8);
$value = bcdiv((float)$Value, 100,8);
returns 8.431e-05 as one of the values in the script
i've tried
$newNum = (float)$value;
$newNum = number_format((float)$value, 8);
$newNum = sprintf('%.8f',$value);
function scientific_notation($in_float_value, $in_decimal_place_count = -1)
{
// Get the exponent
$abs_float_value = abs($in_float_value);
$exponent = floor($abs_float_value == 0 ? 0 : log10($abs_float_value));
// Scale to get the mantissa
$in_float_value *= pow(10, -$exponent);
// Create the format string based
// on the requested number of decimal places.
$format = ($in_decimal_place_count >= 0) ? "." . $in_decimal_place_count : "";
//echo("Format0: $format");
// Format the exponent part using zero padding.
$formatted_exponent = "+" . sprintf("%02d", $exponent);
if($exponent < 0.0)
{
$formatted_exponent = "-" . sprintf("%02d", -$exponent);
}
$format = "%" . $format . "fe%s";
//echo("Format1: $format");
// Return the final value combining mantissa and exponent
return sprintf($format, $in_float_value, $exponent);
}
$newNum = scientific_notation($value,8);
Tried it in phpfiddle and it works. maybe the problem is storing it in a db. It's stores as 8.431e-05 in the database
what am I doing wrong?
Use the exemple below to convert Scientific Notation to float/decimal on PHP:
echo sprintf('%f', floatval('-1.0E-5'));//default 6 decimal places
echo sprintf('%.8f', floatval('-1.0E-5'));//force 8 decimal places
echo rtrim(sprintf('%f',floatval(-1.0E-5)),'0');//remove trailing zeros
When working with Bitcoin balances it is recommended to store amounts in a database in satoshis as an integer and then you can convert it back to 8 decimals when displaying it on the screen to users.
$amount = 0.0132;
$convert = $amount * 100000000;
// store in DB as the converted amount 1320000 as an integer
// when grabbing from DB convert it back
$databaseValue = 1320000;
$convertBack = $databaseValue / 100000000;
$display = number_format($convertBack, 8);
echo $display;
Im trying to get out an average value from a vote function.
<?php
$file = file("textfile.txt");
$textfil = file_get_contents("textfile.txt");
$textfill = str_split($textfil);
echo "Number of votes: " . count($textfill) . "<br>";
$sum = 0;
foreach ($textfill as $vote) {
$sum = $sum + intval($vote);
}
echo "Average: " . $sum;
?>
Simple by substitute (+) with a (/), and even tried a (%). But still getting error message.
Would appreciate alot if anyone could help me out and tell me what im doing wrong.
/thanks
Edit
Sidenote: Please read an explanation under "First answer given" further down below.
This version will take into account any blank lines in a file, if the content looks like:
1
2
3
// <- blank line
Sidenote: Please provide a sample of your text file. A comment has already been given to that effect.
PHP
<?php
// first line not required
// $file = file("textfile.txt");
$textfil = file_get_contents("textfile.txt");
$textfill = array_filter(array_map("trim", file("textfile.txt")), "strlen");
echo "Number of votes: " . count($textfill) . "<br>";
$sum = 0;
foreach ($textfill as $vote) {
$sum += intval($vote);
}
$avg = $sum / count($textfill);
echo "Average: " . $avg;
?>
First answer given
Using the following in a text file: (since no example of file content was given)
5
5
5
IMPORTANT NOTE: There should not be a carriage return after the last entry.
produced
Number of votes: 5
Average: 3
which is false, since there are 3 entries in the text file.
explode() should be used, and not str_split()
The following using the same text file produced:
Number of votes: 3
Average: 5
which is correct. In simple mathematics, averages are done by adding all numbers then dividing them by how many numbers there are.
In this case it's 3 numbers (all 5's) added equals 15, divided by 3 is 5.
Sidenote: The first line is not required $file = file("textfile2.txt");
<?php
// first line not required
// $file = file("textfile.txt");
$textfil = file_get_contents("textfile.txt");
$textfill = explode("\n", $textfil);
echo "Number of votes: " . count($textfill) . "<br>";
$sum = 0;
foreach ($textfill as $vote) {
$sum += intval($vote);
}
$avg = $sum / count($textfill);
echo "Average: " . $avg;
?>
Footnotes:
If the average comes out to 8.33333 and you would like it to be rounded off to 8, use:
echo "Average: " . floor($avg);
If the average comes out to 8.33333 and would like it to be as 9 you would use:
echo "Average: " . ceil($avg);
ceil() function
floor() function
You may be mixing in stuff that can't be divided, like text, etc. I don't know what your text file looks like. intval may be having a problem with arrays. You may try:
foreach ($textfill as $vote) {
if(is_int($vote) {
$sum += $vote;
}
}
echo "Average: " . $sum;
Lower school math says:
foreach ($textfill as $vote) {
$sum += intval($vote);
}
$avg = $sum / count($textfill);
The average value is calculated by divide the sum with the number of votes. This line will print the average value:
echo "Average: " . $sum/count($textfill);
I have this
$example = "1234567"
$subtotal = number_format($example, 2, '.', '');
the return of $subtotal is "1234567.00"
how to modify the definition of $subtotal, make it like this "1,234,567.00"
Below will output 1,234,567.00
$example = "1234567";
$subtotal = number_format($example, 2, '.', ',');
echo $subtotal;
Syntax
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
But I advise you to use money_format which will formats a number as a currency string
You have many options, but money_format can do the trick for you.
// Example:
$amount = '100000';
setlocale(LC_MONETARY, 'en_IN');
$amount = money_format('%!i', $amount);
echo $amount;
// Output:
"1,00,000.00"
Please note that money_format() is only defined if the system has strfmon capabilities. For example, Windows does not, so it is undefined in Windows.
Final edit: Here's a pure PHP Implementation that will work on any system:
$amount = '10000034000';
$amount = moneyFormatIndia( $amount );
echo number_format($amount, 2, '.', '');
function moneyFormatIndia($num){
$explrestunits = "" ;
if(strlen($num)>3){
$lastthree = substr($num, strlen($num)-3, strlen($num));
$restunits = substr($num, 0, strlen($num)-3); // extracts the last three digits
$restunits = (strlen($restunits)%2 == 1)?"0".$restunits:$restunits; // explodes the remaining digits in 2's formats, adds a zero in the beginning to maintain the 2's grouping.
$expunit = str_split($restunits, 2);
for($i=0; $i<sizeof($expunit); $i++){
// creates each of the 2's group and adds a comma to the end
if($i==0){
$explrestunits .= (int)$expunit[$i].","; // if is first value , convert into integer
}else{
$explrestunits .= $expunit[$i].",";
}
}
$thecash = $explrestunits.$lastthree;
} else {
$thecash = $num;
}
return $thecash; // writes the final format where $currency is the currency symbol.
}
Ref: http://php.net/manual/en/function.money-format.php
string money_format ( string $format , float $number )
ex:
// let's print the international format for the en_US locale
setlocale(LC_MONETARY, 'en_US');
echo money_format('%i', $number) . "\n";
// USD 1,234.56
Note: The function money_format() is only defined if the system has strfmon capabilities. For example, Windows does not, so money_format() is undefined in Windows.
Note: The LC_MONETARY category of the locale settings, affects the behavior of this function. Use setlocale() to set to the appropriate default locale before using this function.
Use number_format : http://www.php.net/manual/en/function.number-format.php
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
$number = 123457;
$format_number = number_format($number, 2, '.', ',');
// 1,234.57