PHP number format with integer format - php

Question

I am using PHP number_format to express prices of products, using decimal point, thousands separators, etc. For example:
$price = 20.456;
print "$" . number_format($price, 2, ".", ",");
outputs $20.46.
However, I would like that, if the price is integer, for example $price = 20.00, to output $20. Is there some other function or rule to achieve this, avoiding decimal points if not necessary?

Answer 1

Just do a loose comparison of $price cast as integer against $price, if they match (ie. it's a whole number), you can format to 0 decimal places:
number_format($price, ((int) $price == $price ? 0 : 2), '.', ',');

Answer 2

You can use ternary operator fot that:
$price = 20.456;
print "$" . ($price == intval($price) ? number_format($price, 0, "", ",") : number_format($price, 2, "", ","));

Answer 3

Try $price = 20.456 +0 ;
$price + 0 does the trick.
echo 125.00 + 0; // 125
echo '125.00' + 0; // 125
echo 966.70 + 0; // 966.7
Internally, this is equivalent to casting to float with (float)$price or floatval( $price) but I find it simpler.

Answer 4

A little helper function my_format to determine if the number is an integer and then return the corresponding string.
function my_format($number)
{
if (fmod($number, 1) == 0) {
return sprintf("$%d\n", $number);
} else {
return sprintf("$%.2f\n", $number);
}
}
$price = 20.456;
echo my_format($price);
echo my_format(20);
Will output
$20.46 $20

Answer 5

A little solution that works for any number
$price = "20.5498";
$dec = fmod($price, 1);
if($dec > 0)
print "$" . number_format($price, 2, ".", ",");
else
print "$" . floor($price);;

Answer 6

You can use floor() function
$price = 20.456;
echo '$'.floor($price); // output $20