extracting values from Mysql query - php

Question

i am confused about how to extract values from a query, and place them into specific variable, when i don't know before hand what the name of the value will be.
it might be easier to show you what i mean.
the images below are the returned values, grouped by heading i.e Total_responded, Percent_responded etc.
so the first row will have under the column Responce the value Poached with a Percent_responded of 16.66667.
however the next row will have under column Responce $scrambled with a Percent_responded of 83.333333
i now want to place each of these values into individual variables like:
$poached , $poachedPercentage, $scrambled, $scrambledPercentage etc
i attempted to do it below, but produced the wrong figures. this is also not a cost effective way to do it. so, i would really appricaite some advice on how to extract the values
$getPollResult = results();
while ($row = mysqli_fetch_array ($getResult , MYSQLI_ASSOC))
{
$responce = safe_output(round($row['RESPONCE']));
$percentage = safe_output(round($row['Percent_responded']));
if($responce = 'Poached')
{
$percentageOne = $percentage;
$poached = $responce;
}
if ($responce = 'Scrambled')
{
$percentageTwo = $percentage;
$scrambled = $responce;
}
// echo " $percentagePoached $percentageScrambled ";die();
}

Answer 1

Use
$responce = trim($row['RESPONCE']);
Instead Of
$responce = safe_output(round($row['RESPONCE']));
Also, Change in if condition = to ==.

Answer 2

you can use "variable variables" (PHP Docs) to achieve that:
while ($row = mysqli_fetch_array ($getResult , MYSQLI_ASSOC))
{
$responce_name = trim($row['RESPONCE']);
$percentage_name = $responce_name . "Percentage";
$percentage = safe_output(round($row['Percent_responded'])); //don't know what safe_output() does
$$percentage_name = $percentage; //notice the double "$" here
}
your PHP variables will then look like this:
$PoachedPercentage = 17;
$ScrambledPercentage = 83;
// and so on....