I have used following code for simple join in Doctriner in Codeigniter:
$query = $this->em->createQuery('SELECT u.name,u.subject,pds.subject_name FROM PdContact u,PdSubject pds WHERE pds.id=u.sub_id');
But how to do left join? When I tried to to left join it shows error.
Please suggest solution.
You can use this :
$sql = "SELECT u.name,u.subject,pds.subject_name FROM PdContact u LEFT JOIN PdSubject pds ON pds.id=u.sub_id;";
$connection = $this->em->getConnection();
$cleanreq = $connection->prepare($sql);
$cleanreq->execute();
$result = $cleanreq->fetchAll();
return $result;
For more infos on Joining you can check this doc : http://doctrine-orm.readthedocs.org/en/latest/reference/dql-doctrine-query-language.html
Related
Please help me to check my query. I have search a lot and I have'nt try to select 3 tables before.
I think I got it right but I dont know why there's nothing happen.
public function delSection($delete_id)
{
$stmt = $this->conn->prepare("SELECT * FROM tbl_section
JOIN tbl_login ON (tbl_login.sec_id = tbl_section.sec_id)
JOIN tbl_content ON (tbl_content.sec_id = tbl_section.sec_id)
WHERE tbl_section.sec_id=:del_id");
$stmt->execute(array(":del_id"=>$delete_id));
while($linkRow=$stmt->fetch(PDO::FETCH_ASSOC))
{
unlink(__DIR__."/Admin/cover_images/".$linkRow['sec_cover']);
unlink(__DIR__."/Admin/Files/".$linkRow['sec_id']."/".$linkRow['file_name']);
rmdir(__DIR__."/Admin/Files/".$linkRow['sec_id']);
}
$stmt2 = $this->conn->prepare("DELETE tbl_section, tbl_login, tbl_content FROM tbl_section
JOIN tbl_login ON (tbl_login.sec_id = tbl_section.sec_id)
JOIN tbl_content ON (tbl_content.sec_id = tbl_section.sec_id)
WHERE tbl_section.sec_id=:del_id");
$stmt2->bindparam(":del_id",$delete_id);
$stmt2->execute();
return true;
}
What I am trying to do is to select * from 3 tables and fetch their data with fk sec_id
here's the manual running of query
link:
Code:
Done With LEFT OUTER JOIN QUERY
$stmt = $this->conn->prepare("SELECT * FROM tbl_section
LEFT OUTER JOIN tbl_login ON (tbl_login.sec_id = tbl_section.sec_id)
LEFT OUTER JOIN tbl_content ON (tbl_content.sec_id = tbl_section.sec_id)
WHERE tbl_section.sec_id=:unlink_id");
Here is the query I created :
$query = "SELECT address_details.company, address_details.po_box,
address_details.town, letter_details.address_id,
letter_details.attn, letter_details.create_date,
letter_details.ref_no, letter_details.refference,
letter_details.letter_body, letter_details.print_date
FROM letter_details
join address_details ON address_details.id = letter_details.address_id
join signatories ON (letter_details.id = signatories.id)
WHERE letter_details.id='" .$_GET['id'] . "'";
Try using this query.
$query = "SELECT ad.company, ad.po_box,
ad.town, ld.address_id,
ld.attn, ld.create_date,
ld.ref_no, ld.refference,
ld.letter_body, ld.print_date
FROM letter_details ld
left join address_details ad ON (ad.id = ld.address_id)
left join signatories s ON (ld.id = s.id)
WHERE ld.id='" .$_GET['id'] . "'";
First, you should alias for better readibility,
check if you get something in $_GET[id]
echo $_GET[id];
then assign it, (or you may set it as well, if you're using a class)
$fltr = $_GET[id];
And, try to use LEFT JOIN ;
SELECT b.company, b.po_box,
b.town, a.address_id,
a.attn, a.create_date,
a.ref_no, a.refference,
a.letter_body, a.print_date
FROM letter_details AS a LEFT JOIN address_details AS b ON b.id = a.address_id
LEFT JOIN signatories AS c ON (a.id =c.id)
WHERE a.id='$fltr'
I have the following code for selecting from multiple tables where the order number matches.
$orderNumber = $_GET['orderNumber'];
$sql = $db->prepare("
SELECT
*
from `KC_Orders`
INNER JOIN
`KC_Payments`
on KC_Orders.orderNumber = KC_Payments.orderNumber
INNER JOIN
`KC_OrderStatus`
on KC_Orders.orderNumber = KC_OrderStatus.orderNumber
INNER JOIN
`KC_Statuses`
on KC_OrderStatus.statusID = KC_Statuses.statusID
WHERE
orderNumber= :orderNumber");
$sql->execute(array(':orderNumber' => $orderNumber));
$orderInfo = $sql->fetchAll();
Now when I var_dump($orderInfo); it returns: array(0) { } What is wrong? All the tables include the same $orderNumber field within it. If I take the WHERE part out it works just fine except it returns every row not just one. (obviosly).
Please help us!
You need to specify what the OrderNumber is from, and the * is from (what table). So try this new code:
$sql = $db->prepare("SELECT KC_Orders.* from `KC_Orders` INNER JOIN `KC_Payments` on KC_Payments.orderNumber = KC_Orders.orderNumber INNER JOIN `KC_OrderStatus` on KC_OrderStatus.orderNumber = KC_Order.orderNumber INNER JOIN `KC_Statuses` on KC_Statuses.statusID = KC_OrderStatus.statusID WHERE KC_Orders.orderNumber= :orderNumber");
Ordernumber in where clause should have table prefix if it exists in multiple tables
Try this
$orderNumber = (int)$_GET['orderNumber'];
Then where :ordernumber is put $orderNumber
Then execute
I'm trying to use ResultSetMappingBuilder to get data from Native query.
$sql = "SELECT e.start_date FROM se_events e
LEFT JOIN se_event_tags tg ON e.id = tg.event_id
LEFT JOIN se_event_type t ON tg.event_type_id = t.id
WHERE t.id = :id";
I have no idea how to build ResultSetMappingBuilder.
public function createResultSetMapping() {
$rsm = new \Doctrine\ORM\Query\ResultSetMappingBuilder($this->getEntityManager());
$rsm->addRootEntityFromClassMetadata('Event', 'e');
return $rsm;
}
Thanks for help in advance.
So I've used row SQL:
$sql = "SELECT e.start_date FROM se_events e
LEFT JOIN se_event_tags tg ON e.id = tg.event_id
LEFT JOIN se_event_type t ON tg.event_type_id = t.id
WHERE t.id = $id";
$stmt = $this->getEntityManager()->getConnection()->prepare($sql);
$stmt->execute();
return $stmt->fetchAll();
I want to generate xml file from several tables in a MySQL database using PHP.
$query = "
SELECT
t.value,
d.value,
ty.value,
p.id,
p.ref,
p.is_renting,
p.price,
p.adress,
p.living_space,
p.rooms
FROM
jos_jea_properties p
INNER JOIN
jos_jea_towns t
ON
t.id = d.town_id
INNER JOIN
jos_jea_departments d
ON
d.id = p.department_id
INNER JOIN
jos_jea_types ty
ON
ty.id = p.type_id";
$result = mysql_query ($query, $link) or die("Could not complete database query");
But, it show me Could not complete database query, have you any idea?
There's something wrong in your query. Use mysql_error() to get the message returned by MySQL.
$result = mysql_query ($query, $link) or die("Could not complete database query: ".mysql_error()));
However, your query gets a lot of fields named value. Use aliases instead, otherwise they're getting replaced
$query = "SELECT t.value t_value, d.value d_value, ty.value ty_value,
p.id, p.ref, p.is_renting, p.price, p.adress,
p.living_space, p.rooms FROM jos_jea_properties
p INNER JOIN jos_jea_towns t ON t.id = d.town_id
INNER JOIN jos_jea_departments d ON d.id = p.department_id
INNER JOIN jos_jea_types ty ON ty.id = p.type_id";
Have you an idea about a code php How to generate a file xml for image since mysql database using php?