i want to store array value in different variable - php

Question

I have array that contain 7 string value.
I want to store it in different variable.
but i have 10 variable so i wish that, the variable not contain any array value that's value is zero.
<?php
$str = ("my", "name" , "ajay "," and "," i "," am ", " vageration " );
?>
i want to get this string value like
$a1=
$a1=my
$a3=name
$a4=ajay
$a5=and
$a6=i
$a7=am
$a8=vageration
$a9=0
$a10=0
i don`t know how can i print this value

Answer 1

I think I wont answer to your question, but I don't really understand what you want.
If you want to dynamically assign variables in php, I could invite you to do something like that:
<?php
$str = ("my", "name" , "ajay "," and "," i "," am ", " vageration " );
for ($i = 0; $i < 10; $i++)
${'a'.$i} = (isset ($str[$i]) ? $str[$i] : 0);
?>
In your case, this will create the following variables :
<?php
$a0 = "my";
$a1 = "name";
$a2 = "ajay ";
$a3 = " and ";
$a4 = " i ";
$a5 = " am ";
$a6 = " vageration ";
$a7 = 0;
$a8 = 0;
$a9 = 0;
?>
This line (${'a'.$i} = (isset ($str[$i]) ? $str[$i] : 0) uses the ternary operator, which means that the variable ${'a'.$i} will have $str[$i]'s value if such a value exists or 0 otherwise.
Not sure it helps. I'll edit or delete my message if necessary.