Query MySQL table based on form post - php

Question

I'm working on a web form that allows the user to conduct a zip code search. My intent is to use the form post to search a MySQL table for the matching zip code then return content from an associated field in the same row.
I can get as far as... form submits and directs user to the intended form_post.php page. If I enter <?php echo $_POST["zipcode"]; ?> on the page it returns the content submitted by the user.
I followed the PHP/MySQLi examples from these pages:
http://www.w3schools.com
/php/php_mysql_connect.asp
/php/php_mysql_select.asp
/php/php_if_else.asp
I am able to connect to the database and return the 2 selected values from the table. This is my example so far:
<?php
$servername = "localhost";
$username = "db_username";
$password = "db_password";
$dbname = "db_name";
if (isset($_POST['zipcode'])) {
$zipcode = $_POST['zipcode'];
}
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT zip_code, area FROM zipcode_table WHERE zip_code = $zipcode";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Result: " . $row["zip_code"]. " " . $row["area"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
After the query returns the associated values I would like to determine if the returned value from 'area' is one of 3 values then forward the user to the appropriate url.
I was working on an if/else statement as follows then got stuck.
if($result == "A") {
header("Location: http://example.com/page-1/");
}
elseif($result == "B") {
header("Location: http://example.com/page-2/");
}
elseif($result == "C") {
header("Location: http://example.com/page-3/");
} else {
header("Location: http://example.com/");
exit();
}
Any recommendations are appreciated.

Answer 1

you are using $result in if but, you not assign it area region.So, first relpace this:
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Result: " . $row["zip_code"]. " " . $row["area"]. "<br>";
}
} else {
echo "0 results";
}
with this:
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Result: " . $row["zip_code"]. " " . $row["area"]. "<br>";
$result = $row["area"];
break;
}
} else {
echo "0 results";
$result = "";
}
then replace query:
$sql = "SELECT zip_code, area FROM zipcode_table WHERE zip_code = $zipcode";
with this:
$sql = "SELECT zip_code, area FROM zipcode_table WHERE zip_code = '$zipcode'";
then your problem will be solved.