PHP / MySql if '1' echo "Ok" else if '0' echo "No" - php

Question

Phpmyadmin:
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if (mysql_query("SELECT setup FROM users") === 1) {
echo "One";
} else if (mysql_query("SELECT setup FROM users") === 0) {
echo "Zero";
}
On register. As defined: 0.
If table shows 0, echo Zero.
Else if table shows ID 1, echo One.
How is this done?
Solution:
$setup = mysql_query("SELECT setup FROM users");
$row = mysql_fetch_assoc($setup);
if ($row['setup'] == 0) {
echo "Zero.";
} else {
echo "One!";
}

Answer 1

I think you need this
First of all use mysqli
//$connection = your mysqli connection. Dont use mysql
Then properly write query if you need admin row
$query = "SELECT `setup` FROM `users` WHERE `user_id`=1 AND `username` = 'admin'";
Then execute query
$result = mysqli_query($connection, $query);
Then search for $setup value
while($row = mysqli_fetch_assoc($result)){
$setup = $row['setup'];
}
Then echo what you need
if ($setup == 1) {
echo "One";
} else if ($setup == 0) {
echo "Zero";
}

Answer 2

See the docs. The 'Example (MySQLi Procedural)' example is similar to what you want.
Snippet:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
Changing
$sql = "SELECT id, firstname, lastname FROM MyGuests";
to
$sql = "SELECT setup FROM users";
then
if (mysqli_num_rows($result) > 0) {
to your various if checks should suffice. Not the cleanest. Seems like you could just print out the value of setup? Good luck!