Join a table only where there is a count in the subquery - php

Question

I'm making a search engine in which a page visitor can search for music artists based on 4 different attributes which the artists will have a rating of from 0- 100 and by entering the minimum value of a specified attribute, the visitor can view the list of artists with ratings greater than or equal to the desired value. After the query I have the fetch array and foreach statement already set but I am having trouble with the query.
I've tried the following query statement. It's one cohesive statement:
SELECT users.username, databaseimage.profile
// users.username is artists username
// databaseimage is table where profile pic is stored
FROM users
JOIN databaseimage ON users.id = databaseimage.user_id
JOIN attributes ON users.id = attributes.userid
// user.id, database.user_id, and attribute.userid all correspond to the id of a specified artist
// attributes is table where attributes are stored
The above gets me all the data that I need. Below is the part I need help with. I want to narrow the data down such that only the data corresponding to artists with attribute ratings (as attr) greater than $selectnumber (Number specified by the visitor) is in the the result array. This what I have tried.
WHERE attribute.userid
HAVING COUNT() IN (
SELECT userid, ($attribute DIV TotalRatingEntries) as attr
FROM attributes
WHERE attr >= '$selectnumber'
)

Answer 1

A far as I understand data structure I can propose the query below:
SELECT
users.username,
databaseimage.profile
FROM
users
JOIN databaseimage ON users.id = databaseimage.user_id
JOIN attributes ON users.id = attributes.userid
WHERE
attribute.userid IN
(
SELECT
userid
FROM
attributes
group by
userid,TotalRatingEntries
having
sum(attribute)/TotalRatingEntries >= '$selectnumber'
)
Please provide more details about these 3 tables, maybe I misunderstood something.