Convert php query result into json - php

Question

I have the following code that queries multiple tables to get information about activities. I would like to convert the query result into array and call it whenever needed.
My question is: can this query be converted into array?
<?php
function view_full_activity($activity_field){
global $connection;
$contact_id = $_REQUEST['contact_id'];
$activity_id = $_REQUEST['activity_id'];
$get = "SELECT * FROM activity_base WHERE activity_id = '$activity_id' "
or die("Error: ".mysqli_error($connection));
$query = mysqli_query($connection, $get);
//Get activity base information
while ($activity = mysqli_fetch_array($query)){
$activity_related_to_id = $activity ['activity_related_to_id'];
$activity_id = $activity['activity_id'];
$activity_type_id = $activity['activity_type_id'];
$activity_entity_type_id = $activity['activity_entity_type_id'];
$activity_title = $activity['activity_title'];
$activity_due_date = $activity['activity_due_date'];
$activity_created_by = $activity['activity_created_by'];
$activity_created_on = $activity['activity_created_on'];
$activity_status_code_id = $activity['activity_status_code_id'];
$activity_type_icon;
$activity_due_date = $activity['activity_due_date'];
$activity_create_date = date("m-d-Y", strtotime($activity['activity_created_on']));
//Reverse Date
$activity_due_date = date("m-d-Y ", strtotime($activity_due_date));
if ($activity_type_id == "1"){
$activity_type_icon = "fa fa-envelope";
}else if ($activity_type_id == "3"){
$activity_type_icon = "fa fa-suitcase";
}else if ($activity_type_id == "2"){
$activity_type_icon = "fa fa-phone";
}
if ($activity_entity_type_id == "1") {
$acitvity_url = "acct_id";
$acitivty_is_for ="accounts_base";
$page_url = "account-profile.php";
}else if ($activity_entity_type_id == "2") {
$acitvity_url = "contact_id";
$acitivty_is_for ="contacts";
$page_url = "contact-profile.php";
}else if ($activity_entity_type_id == "3") {
$acitvity_url = "contact_id";
$acitivty_is_for ="contacts";
$page_url = "contact-profile.php";
}
//Get detailed activity information
//If activity is Email
if ($activity_type_id == "1") {
$email_details = email_activity_details($activity_id);
while ( $email = mysqli_fetch_assoc($email_details)) {
$activity_details = nl2br($email['email_message']);
}
}else if ($activity_type_id == "2") {
$call_details = call_activity_details($activity_id);
while ( $call = mysqli_fetch_assoc($call_details)) {
$activity_details = $call['call_details'];
}
}else if ($activity_type_id == "3") {
$meeting_details = meeting_activity_details($activity_id);
while ( $meeting = mysqli_fetch_assoc($meeting_details)) {
$activity_details = $meeting['meeting_details'];
}
}
//Get creator user info
$user_query = get_user_info($activity_created_by);
while ($user = mysqli_fetch_array($user_query)) {
$activity_created_by = $user['user_full_name'];
}
}
}
?>

Answer 1

Sure:
Create a variable called $activity_store and use the while loop to set the data much in the same way it comes out of the database.
//Get activity base information
$activity_store = array();
while ($activity = mysqli_fetch_array($query)){
$activity_store['activity_related_to_id'] = $activity['activity_related_to_id'];
If you need to store information about each activity pulled from the database separately you could add an index and increment it
//Get activity base information
$activity_store = array();
$i = 0;
while ($activity = mysqli_fetch_array($query)){
$activity_store[$i]['activity_related_to_id'] = $activity['activity_related_to_id'];
...
$i++; //increments $i by 1
}
Just be aware that later in your code when you refer to $activity_type_id you'll now need to refer to '$activity['activity_type_id']`
In terms of returning JSON in php you can use json_encode to encode a variable into a JSON format:
$json_array = json_encode($variable);