Remove number from array with repeated digits - php

Question

I want to remove the numbers from array which have repeated digits in them.
array('4149','8397','9652','4378','3199','7999','8431','5349','7068');
to
array('8397','9652','4378','8431','5349','7068');
I have tried this thing
foreach($array as $key => $value) {
$data = str_split($value, 1);
$check = 0;
foreach($data as $row => $element) {
$check = substr_count($value, $element);
if($check != 1) {
array_diff($array, array($value));
}
}
}

Answer 1

You can filter the array using a regular expression that matches:
(.) any character
.* followed by zero or more characters
\1 followed by the first character one more time
Example code:
$array = array('4149','8397','9652','4378','3199','7999','8431','5349','7068');
$result = array_filter(
$array,
function ($number) {
return !preg_match('/(.).*\\1/', $number);
}
);
echo implode(', ', $result), PHP_EOL;
Output:
8397, 9652, 4378, 8431, 5349, 7068

Answer 2

This should work for you:
Here I first str_split() each element into a separate array with array_map(). After this I just compare the splitted array with the same array just with array_unique() digits and check if they are the same. If yes I return the implode() number otherwise false. And at the end I just filter the elements with false with array_filter() out.
So in other words I just compare these 2 arrays with they are the same:
array1:
Array
(
[0] => Array
(
[0] => 4
[1] => 1
[2] => 4
[3] => 9
)
//...
)
array2:
Array
(
[0] => Array
(
[0] => 4
[1] => 1
[3] => 9
)
//...
)
Code:
<?php
$arr = ['4149', '8397', '9652', '4378', '3199', '7999', '8431', '5349', '7068'];
$arr = array_map("str_split", $arr);
$result = array_filter(array_map(function($v1, $v2){
return ($v1 === $v2?implode("", $v1):false);
}, $arr, array_map("array_unique", $arr)));
print_r($result);
?>
output:
Array ( [1] => 8397 [2] => 9652 [3] => 4378 [6] => 8431 [7] => 5349 [8] => 7068 )