Remove unset array containing specific string - php

Question

I have the following array imported from a CSV:
Array
(
[0] => Array
(
[0] => QUARTERLY STATS;Q1/2011;Q2/2011;Q3/2011;Q4/2011;Q1/2012;Q2/2012;Q3/2012;Q4/2012;Q1/2013;Q2/2013;Q3/2013;Q4/2013;Q1/2014
)
[1] => Array
(
[0] => January;7500;8800;9500;10000;10500;11000;11500;12000;12500;13000;13420;13820;14200
)
[2] => Array
(
[0] => ;;17
[1] => 30%;8%;5
[2] => 30%;5%;4
[3] => 80%;4
[4] => 50%;4
[5] => 30%;4
[6] => 20%;4%;3
[7] => 20%;3%;2
[8] => 70%
)
[3] => Array
(
[0] => TOTAL;7500;8500;9500;11000;12500;11400;11800;13000;12500;13000;13420;13820;14200
)
[4] => Array
(
[0] => ;;17
[1] => 30%;7
[2] => 95%;5
[3] => 26%;5%;4
[4] => 76%;4
[5] => 55%;4
[6] => 35%;4
[7] => 17%;4%;3
[8] => 23%;2
[9] => 98%;2
[10] => 75%
)
So,
I would like to get rid of all arrays containing "% and TOTAL".
I thought to loop through and unset the matching case:
$remove ="TOTAL";
foreach ($csv as $key => $value){
if (in_array($remove,$value[$key])){
unset($value[$key]);
}
}
This is the error I got:
Warning: in_array() expects parameter 2 to be array, null given
My PHP Version 5.3.10
Would you do it that way or would you use the array_filter?
I am browsing since 2 hours the forum but I could not find any hint helping me out.
Cheers.

Answer 1

You can try by preg_replace for removing TOTAL & %. If you want to remove the element from array then use unset & finally use array_filter for removing null elements.
$newArr = array();
foreach($arr as $key=>$value){
foreach($value as $k=>$v){
$newArr[$key][$k] = preg_replace('/(TOTAL)|(%)/', '', $v); //for removing TOTAL & %
unset($arr[$key][$k]); //for unset the array elements that contains TOTAL & %
}
}
//Output by replacement
print '<pre>';
print_r($newArr);
print '</pre>';
//output after using unset
print '<pre>';
print_r(array_filter($arr));
print '</pre>';

Answer 2

In your case:
foreach ($csv as $subArray)
{
for ($i = 0, $len = count($subArray); $i < $len; $i++)
{
if (strpos($subArray[$i], $remove) !== false)
unset($subArray[$i])
}
}
Comments:
strict comparasion for strpos, if we use !=, then 0 position would be equals to false.
inner loop is "for-loop" bevause it's better to avoid changing content of array inside foreach.

Answer 3

$arr[][] = ("QUARTERLY STATS;Q1/2011;Q2/2011;Q3/2011;Q4/2011;Q1/2012;Q2/2012;Q3/2012;Q4/2012;Q1/2013;Q2/2013;Q3/2013;Q4/2013;Q1/2014");
$arr[][] = ("January;7500;8800;9500;10000;10500;11000;11500;12000;12500;13000;13420;13820;14200");
$arr[] = array(";;17","30%;8%;5","30%;5%;4","80%;4","50%;4","30%;4","20%;4%;3","20%;3%;2","70%");
$arr[][] = ("TOTAL;7500;8500;9500;11000;12500;11400;11800;13000;12500;13000;13420;13820;14200");
$arr[] = array("30%;7","95%;5","26%;5%;4","76%;4","55%;4","35%;4","17%;4%;3","23%;2","98%;2","75%");
$newArr = array();
foreach($arr as $key=>$value) {
foreach($value as $k=>$v) {
$newArr[$key][$k] = preg_replace('/(TOTAL)|(%)/', '', $v); //for removing TOTAL & %
unset($arr[$key][$k]); //for unset the array elements that contains TOTAL & %
}
unset($arr[$key]); // IT does not unset ARR[2] ARR[3] and ARR[4] containing TOTAL & %
}
Output by replacement
print '<pre>';
print_r($newArr);
print '</pre>';
Output after using unset
print '<pre>';
print_r(array_filter($arr));
print '</pre>';
I did create exactly the same ARRAY as imported from CSV.
unset does not unset ARRAY2,3,4 which is containing TOTAL AND %.
unset does not unset ARRAY2,3,4 which is containing TOTAL AND %.