jQuery tokeninput returns null value. when I submit the form the $_POST[] array is empty.
In the demo when I click submit button it alert :"would submit:" and the values. I did the same in mine and it alert : "would submit: undefined".
my form.html :
<html>
<head>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script>
<script type="text/javascript" src="jquery.tokeninput.js"></script>
<link rel="stylesheet" href="token-input-facebook.css" type="text/css" />
<script type="text/javascript">
$(document).ready(function() {
$("input[type=button]").click(function () {
alert("Would submit: " + $(this).siblings("input[type=text]").val());
});
});
</script>
</head>
<body>
<form action="process.php" method="post">
<label for="title" class="control-label col-sm-2">Title(s) :</label>
<input name="title" id="title" class="form-control">
<input type="button" value="Submit" />
<script type="text/javascript">
$(document).ready(function() {
$("#title").tokenInput("gethint.php", {
theme: "facebook",
hintText: "Begin typing title ...",
noResultsText: "No titlesfound",
propertyToSearch: "title",
tokenValue: "'id'",
tokenDelimiter: ","
});
});
</script>
</form>
</body>
</html>
process.php :
<?php
$titles = $_POST["title"];
?>
<html>
<body>
<?php
print_r($names);
?>
</body>
</html>
There are no input[type=text]elements in your html as specified here:
alert("Would submit: " + $(this).siblings("input[type=text]").val());
Change your html to:
<input type="text" name="title" id="title" class="form-control">
Related
When the user submits the form, the result should be displayed without page refreshing. The PHP script is also in the same HTML page.
What is wrong withe $.post jQuery?
<!--
Submit form without refreshing
-->
<html>
<head>
<title>My first PHP page</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type="text/javascript" language="javascript">
$(document).ready(function() {
$("#btn").click(function(event) {
var myname = $("#name").val();
var myage = $("#age").val();
$.post(
"23.php", $("#testform").serialize()
);
});
});
</script>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" id="testform">
<!-- $_SERVER['PHP_SELF'] array -->
Name:
<input type="text" name="name" id="name" />Age:
<input type="text" name="age" id="age" />
<input type="submit" name="submit" id="btn" />
</form>
</body>
</html>
<?php
if ( isset($_POST['submit']) ) { // was the form submitted?
echo "Welcome ". $_POST["name"] . "<br>";
echo "You are ". $_POST["age"] . "years old<br>";
}
?>
You need to use event.preventDefault in your javascript
$("#btn").click(function(event){
event.preventDefault();
var myname = $("#name").val();
var myage = $("#age").val();
$.post(
"23.php", $( "#testform" ).serialize()
);
});
Yes, you need e.preventDefault. Also, I think these var myname and myage variables are unnecessary since you're serializing the entire form in $.post.
Try this:
$(document).ready(function() {
$("#btn").click(function(e) {
e.preventDefault();
$.post(
"23.php", $("#testform").serialize()
);
});
});
Hope this helps.
Peace! xD
This is my finalized complete code after following your all suggestions. But it is still refreshing when getting results. Let's see if I have made any further error in the code. Thanks for your all helps.
UPDATE! - All these HTML and PHP scripts resides in the same file called 23.php
<!--
Submit form without refreshing
-->
<html>
<head>
<title>My first PHP page</title>
<script type = "text/javascript" src = "http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type = "text/javascript" language = "javascript">
$(document).ready(function() {
$("#btn").click(function(event){
event.preventDefault();
var myname = $("#name").val();
var myage = $("#age").val();
yourData ='myname='+myname+'&myage='+myage;
$.ajax({
type:'POST',
data:yourData,//Without serialized
url: '23.php',
success:function(data) {
if(data){
$('#testform')[0].reset();//reset the form
alert('Submitted');
}else{
return false;
}
};
});
});
});
</script>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" id="testform"> <!-- $_SERVER['PHP_SELF'] array -->
Name: <input type="text" name="name" id="name"/>
Age: <input type="text" name="age" id="age"/>
<input type="submit" name="submit" id="btn"/>
</form>
</body>
</html>
<?php
if ( isset($_POST['submit']) ) { //was the form submitted?
echo "Welcome ". $_POST["name"] . "<br>";
echo "You are ". $_POST["age"] . "years old<br>";
}
?>
I want to post simple form with ajax and update content of div (id result), but I get redirected to server.php file.
index.php:
<!DOCTYPE HTML>
<html>
<head>
<meta charset="UTF-8">
</head>
<body>
<script src="js/jquery.js"></script>
<script src="js/ajax.js" type="text/javascript"></script>
<form id="wbForm" action="server.php" method="POST">
Date1: <input type="text" name="date1" value="2000-01-21"><br>
Date2: <input type="text" name="date2" value="2000-01-02"><br>
<input type="submit" name="submit" value="Submit">
<div id="result"></div>
</form>
</body>
</html>
ajax.js:
$(document).ready(function showHint(form) {
$.ajax({
type:'POST',
url: 'server.php',
data:$('#wbForm').serialize(),
success: function(response) {
$('#wbForm').find('.result').html(response);
}});
});
server.php:
<?php
$input=$_POST;
//... compute something
echo "result";
?>
String "result" should appear in div with id=result, but I get redirected to /server.php where I can see "result", why?
HTML
<!DOCTYPE HTML>
<html>
<head>
<meta charset="UTF-8">
</head>
<body>
<script src="js/jquery.js"></script>
<script src="js/ajax.js" type="text/javascript"></script>
<form id="wbForm" action="server.php" method="POST">
Date1: <input type="text" name="date1" value="2000-01-21"><br>
Date2: <input type="text" name="date2" value="2000-01-02"><br>
<input type="submit" name="submit" value="Submit">
<div id="result"></div>
</form>
</body>
</html>
ajax.php
$(document).on("ready", function(){
//Form action
$("#wbForm").on("submit", function(event){
// Stop submit event
event.preventDefault();
$.ajax({
type:'POST',
url: 'server.php',
data:$('#wbForm').serialize(),
success: function(response) {
$('#wbForm').find('.result').html(response);
}});
});
});
server.php
<?php
$input = $_POST;
print_r( $input );
?>
Happy Codding!!
There are several issues. First, you are getting redirected to server.php when you hit submit because of your form action "server.php". If you want the AJAX call to happen when clicking the button you should put the AJAX call in a JavaScript function and call that function onclick()
The reason the jQuery .AJAX call isn't triggering success is because it's expecting JSON. Try:
<?php
header("content-type:application/json");
$input=$_POST;
//... compute something
echo json_encode("result");
?>
Hope this helps.
Folks,
I am new to js and this I am having trouble capturing and taking a screenshot of a remote website. Can someone point me in the right direction
I keep getting this error:
Uncaught TypeError: Object [object Object] has no method 'html2canvas' index.php:4201
capture index.php:4201
onclick
My code is index.php
<html>
<head>
<title>Hawk-Eye: Have a look at what others are upto</title>
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript" src="http://localhost/Hawk-eye/html2canvas.js"></script>
<script type="text/javascript" src="http://localhost/Hawk- eye/jquery.plugin.html2canvas.js"></script>
</head>
<body>
<div id="target">
<?php
$homepage= file_get_contents('http://www.yahoo.com');
echo $homepage;
?>
</div>
<form method="POST" enctype="multipart/form-data" action="save.php" id="myForm">
<input type="hidden" name="img_val" id="img_val" value="" />
</form>
<script type="text/javascript">
function capture() {
$('#target').html2canvas({
onrendered: function (canvas) {
//Set hidden field's value to image data (base-64 string)
$('#img_val').val(canvas.toDataURL("image/png"));
//Submit the form manually
document.getElementById("myForm").submit();
}
});
}
</script>
<input type="submit" value="Take Screenshot" onclick="capture();" />
</body>
</html>
Download html4canvas and import it as
<script type="text/javascript" src="html2canvas.js?rev032"></script>
I want to submit my form. In my form using first button I create a textbox through ajax and after that I use second button to submit the form normally. When I want to get the value of newly created textbox using $_POST it gives error. How can i get value of ajax created button on submission. my php code is :
<?php`enter code here`
session_start();
ob_start();
require_once "config.php";
if ($_SERVER['REQUEST_METHOD']=="POST")
{
if (isset($_POST['subtest']))
{
print $_GET['tt'];
}
}
?>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<script type="text/javascript" src="jquery-ui-1.8.21.custom/js/jquery-1.7.2.min.js"></script>
<script type="text/javascript" src="jquery-ui-1.8.21.custom/js/jquery-ui-1.8.21.custom.min.js"> </script>
<script type="text/javascript">
jQuery(document).ready(function(){
jQuery("#subt").click(function(){
jQuery("#divload").show();
jQuery.ajax({url:"adp.php", type:"post", success:function(result){
jQuery("#disp").html(result);
jQuery("#divload").hide();
}});
return false;
});
});
</script>
<script type="text/javascript">
jQuery(document).ready(function(){
jQuery("#subtest").click( function() {
alert(jQuery("#tt").val());
});
});
</script>
</head>
<body id="#bdy">
<form id="FrmMain" method="post" action="">
<div id="Shd" style="font: 10%; margin: 50px; background-repeat:repeat-y; padding- left:120px;" >
<input type="text" id="txtFrom" name="txtFrom" />
<input type="text" id="txtUpto" name="txtUpto" />
<input type="text" id="txtOpt" name="txtOpt" />
<input type="submit" id="subt" name="subt" />
<input type="submit" id="subtest" name="subtest" />
<div id="RuBox" style="font-weight:bold;"><input type="checkbox" id="chkaccept" name="chkaccept" /> I accept terms and conditions.</div>
</div>
</form>
<div style="color:#F00; font-size:18px; display:none;" id="divload">Please wait loaidng... </div>
<div id="disp"></div>
</body>
</html>
Code of my adp.php file :
<?php
sleep(5);
?>
<div style="color:#30F; font-size:36px;">
Application testing............
<input type="text" id="tt" name="tt" />
</div>
I am not getting value of textbox named "tt" in temp form
Thanks
You're pretty much not posting anything from here:
jQuery(document).ready(function(){
jQuery("#subt").click(function(){
jQuery("#divload").show();
jQuery.ajax({url:"adp.php", type:"post", success:function(result){
jQuery("#disp").html(result);
jQuery("#divload").hide();
}});
return false;
});
});
So I would assume that you only want to generate a text field dynamically. And you can do it without the use of ajax:
var form = $('#FrmMain');
$('<input>').attr({'type' : 'text', 'id' : 'tt', 'name' : 'tt'}).appendTo(form);
Plus you're also trying to print out $_GET['tt'] while the form method is POST
if (isset($_POST['subtest']))
{
print $_GET['tt'];
}
This should also be:
echo $_POST['tt'];
test.html
<html>
<!--
Please see the full php-ajax tutorial at http://www.php-learn-it.com/tutorials/starting_with_php_and_ajax.html
If you found this tutorial useful, i would apprciate a link back to this tutorial.
Visit http://www.php-learn-it.com for more php and ajax tutrials
-->
<title>php-learn-it.com - php ajax form submit</title>
<head>
<script type="text/javascript" src="prototype.js"></script>
<script>
function sendRequest() {
new Ajax.Request("test.php",
{
method: 'post',
postBody: 'name='+ $F('name'),
onComplete: showResponse
});
}
function showResponse(req){
$('show').innerHTML= req.responseText;
}
</script>
</head>
<body>
<form id="test" onSubmit="return false;">
<input type="hidden" name="name" id="name" value="value">
<input type="hidden" name="somethingElse" value="test" value="submit" onClick="sendRequest()">
</form>
Post!
<div id="show"></div>
<br/><br/>
</body>
</html>
<?php
/*
* Please see the full php-ajax tutorial at http://www.php-learn-it.com/tutorials/starting_with_php_and_ajax.html
* If you found this tutorial useful, i would apprciate a link back to this tutorial.
* Visit http://www.php-learn-it.com for more php and ajax tutrials
*/
if($_POST["name"] == "")
echo "name is empty";
else
echo "you typed ".$_POST["name"];
?>
Where is the wrong in form thanks.
A few things are wrong here:
You have an onclick on a hidden form element
The Post! anchor onclick isn't submitting anything
Suggested changes:
<head>
<script type="text/javascript" src="prototype.js"></script>
<script>
function showResponse(req){
$('show').innerHTML = req.responseText;
}
</script>
</head>
<body>
<form id="test" name="test" action="test.php">
<input type="hidden" name="name" id="name" value="cats" />
<input type="hidden" name="somethingElse" value="test" />
</form>
Post!
<div id="show"></div>
</body>
form id="test" and no name
and yet :
a href="#" onclick="myForm.submit()"
just for starters.