I am using the below code to load a div content from Rezults2.php page into my page.
$("#hotel-list").load("Rezults2.php #hotel-list> *");
How can i send the same $_GET cookies received in my page to Rezults2.php also ?
Or how can i insert the link attributes into my code
$("#hotel-list").load("Rezults2.php?var=variable&etc=etc #hotel-list> *");
You have to do Ajax Requests to achieve the required purpose for sending and getting information.
$.ajax({
type : 'GET',
url : 'page.php',
dataType : 'json',
data: {
variable : $('#id').val()
},
success: function(data){
$.each(data.variable, function() {
//do things here.... with return data
})
}
})
page.php
<?
//Code to do php things
?>
$("#hotel-list").load("Rezults2.php #hotel-list>",{'path': 'scotland'});
Rezults2.php
<div id="hotel-list">
<?php
if(!empty($_REQUEST['path'])) {
// i used $_REQUEST because it receives the data from POST or GET.
$path = $_REQUEST['path'];
echo $path;
}
?>
</div>
Use Jquery load
Related
First, precisions : I'm using MAMP and Brackets, and Chrome to test.
Here's what I have :
<ul>
<li class="brick" data-pseudo="one">Some text or elements</li>
<li class="brick" data-pseudo="two">Some text or elements</li>
<li class="brick" data-pseudo="three">Some text or elements</li>
</ul>
li.bricks are just rectangle articles "linking" to Work1, Work2 and Work3, and generated by a PHP function from an array.
I'm trying to get the "pseudo" data of the clicked .brick to put it in a PHP variable and use it to call another array in another php function, in order to generate the HTML elements of Work1, Work2,...
I found I had to use AJAX and managed to get that code :
var pseudo;
function sendPseudo(info){
$.ajax({
type: "POST",
url: "my_php_function_page.php",
ContentType: 'application/json',
data: {
'data_name': info
},
success: function (data) { //testing the success
alert(data);
},
error: function (errorThrown) {
alert('You are wrong !');
}
});
}
$('.brick').click(function(){
//some code
pseudo = $(this).data('pseudo');
sendPseudo(pseudo); //calling sendPseudo() function
});
And here's my testing PHP function :
function loadWork(){
$workToLoad = $_POST['data_name'];
echo '<p>'.$workToLoad.'</p>';
}
... I'm calling in my HTML document :
<section class="site">
<div class="left">
<?php loadWork() ?>
</div>
<div class="right">
//some other content
</div>
</section>
And so I have two problems. Firstly, when a .brick is clicked, the alert pops up but it's empty, absolutely nothing appears in it, but when I console.log the var pseudo, I see "one", "two"... And secondly, the echo in testing PHP function does not generate the paragraph with the pseudo.
Pleeeaaase, help me to find out what I'm doing wrong, it's making me go crazy !
Thank you !
I think there is some confusion in your order. loadWork(), as you say, is part of an html file gets called as soon as the browser reads the html file and it's only called once. If loadWork() hasn't been defined yet (or exists in another file as your AJAX request suggests based on it's call to my_php_function_page.php) then it won't output anything. In other words, loadWork() needs its post data to exist when the browser requests the html.
You can put the php in the same file as the html that is being called on, but it looks like you might be trying to get the results of loadWork() inserted into a div that already exists. Change your ajax function so that if(data!="") changes the inner html of your div to include the data:
function sendPseudo(info){
$.ajax({
type: "POST",
url: "my_php_function_page.php",
ContentType: 'application/json',
data: {
'data_name': info
},
success: function (data) { //testing the success
alert(data);
$('.left').html(data);
},
error: function (errorThrown) {
alert('You are wrong !');
}
});
}
I think you have missed calling your function loadWork() in my_php_function_page.php, this code may be fix your empty alert issue.
var pseudo;
function sendPseudo(info){
$.ajax({
type: "POST",
url: "my_php_function_page.php",
ContentType: 'application/json',
data: {
'data_name': info
},
data=data.trim(); // to remove the unwanted space around the string
success: function (data) { //testing the success
if(data!="")
{
alert(data);
$(".right").html(data); // This adds your AJAX success data to the class left inside your DIV
}
else
{
alert("You're wrong !");
}
},
});
}
my_php_function_page.php
function loadWork(){
$workToLoad = $_POST['data_name'];
echo '<p>'.$workToLoad.'</p>';
}
loadWork();
I'm not sure why, but sometimes data function is not working, so I always use attr('data-pseudo') in your case.
so it would be like this:
pseudo = $(this).attr('data-pseudo');
I am a newbie to php
<?php
getDBData(){
//log the call
$fetchedData = myDbCode.fetchData();
return
}
?>
<script type="text/javascript">
dbData = <?php echo json_encode(getDBData()); ?>
</script>
As observed in the log that getDBData get called only once during the page loading and later on even with dbData = <?php echo json_encode(getDBData()); ?> this code the call to getDBData() doesn't happen.
Any idea why the call to getDBData() happening only on page load and not thenafter
How to call getDBData() from javascript
You don't actually understand, how it works.
Javascript is a client-side language, which means, that it executes in web browser.
PHP is server-side which mean it executes on server.
While handling request, first PHP is executed, that the response is returned to user, and then Javacript executes.
To communicate between client and server you can use ajax requests, which are basically simple http requests but without reloading whole page.
You should use Ajax for that. I.e. you have a php file which returns the output of the function:
// data.php
<?php
function getDBData(){
//log the call
$fetchedData = myDbCode.fetchData();
return $fetchedData;
}
echo getDBData();
?>
// html file
<script type="text/javascript">
var getDBData = function(callback) {
$.ajax({
url: "data.php"
}).done(callback);
}
var dbData = <?php echo json_encode(getDBData()); ?>
getDBData(function(data) {
dbData = data;
})
</script>
The code above uses jQuery.
you can used AJAX for get server side php vaue into javascript variable read this ajax example and implement it.
// Launch AJAX request.
$.ajax(
{
// The link we are accessing.
url: jLink.attr( "href" ),
// The type of request.
type: "get",
// The type of data that is getting returned.
dataType: "html",
error: function(){
ShowStatus( "AJAX - error()" );
// Load the content in to the page.
jContent.html( "<p>Page Not Found!!</p>" );
},
beforeSend: function(){
ShowStatus( "AJAX - beforeSend()" );
},
complete: function(){
ShowStatus( "AJAX - complete()" );
},
success: function( strData ){
ShowStatus( "AJAX - success()" );
// Load the content in to the page.
jContent.html( strData );
}
}
);
// Prevent default click.
return( false );
}
);
You can do it through ajax.
Here is a link here to do it with jquery : using jquery $.ajax to call a PHP function
use jquery
$.ajax({
url: 'yourpage.php',
type: 'POST',
data:'',
success: function(resp) {
// put your response where you want to
}
});
You can't directly call PHP functions from javascript.
You have to "outsource" the getDBDate to an own .php file where you output the json_encoded string and call this file with ajax and get the output of the page.
The easiest to do AJAX requests in javascript is to use the JQuery Library: http://api.jquery.com/jQuery.ajax/
http://serverA.com/list.php:
html:
<form id="myform">
<input id="inputfield" name="view">
</form>
js:
var inputdata = $('#inputfield').val('ocean-view');
$('#myform').submit(function(e) {
e.preventDefault();
$.ajax({
type: 'GET',
url: 'http://serverB.com/detail.php',
data: inputdata,
dataType: 'jsonp'
});
});
http://serverB.com/detail.php
php:
<?php
$view = $_GET['callback'].'('.json_encode(name) .')';
?>
html:
<h4><?php echo $view; ?></h4>
what the code does is:
from serverA, assign a value "ocean-view" to an input field, submit this form to serverB, and display this value in a h4 tag.
I couldn't quite figure out how to write the server-side code to output the value, even though I have found the following posts.
this and this.
Any kind of help is appreciated.
UPDATE:
I used YQL to help to see the jsonp callback response, here is the json structure:
callback({
"query": {
"count": 1,
"created": "2013-07-29T13:01:12Z",
"lang": "en-US",
"results": {
"h3": {
"class": "mytitle",
"content": "Example"
}
}
}
});
Actually You are very close to success... just read these points.
Whenever you are making an ajax request the browser sends a hit on ajax URL with respected parameters and details. On respected URL PHP code executes. It can return data in some format. It can not return data in directly PHP variable.
Formats are:
text/html
json
xml
......
Mainly for cross domain requests we use JSONP.
And it means PHP script will return data in JSON.
So you will just echo your json_encode in directly script. That will be the response of your ajax request.
Now when you have got the data in ajax function, then jQuery uses success: function(response){ } where you response will come.
So variable response will contain JSON.
You can access JSON and put data in any tag by using jQuery selector.
$().html(response.);
These thing can be analyzed in any browser in debug console. That what is requested and what is returned.
even you can use Firebug in Mozilla to inspect ajax request.
So you will do three changes.
In Ajax function write a success function:
var inputdata = $('#inputfield').val('ocean-view');
$('#myform').submit(function(e) {
e.preventDefault();
$.ajax({
type: 'GET',
url: 'http://serverB.com/detail.php',
data: "inputdata="+inputdata,
dataType: 'jsonp',
success:function(response){
// response will be json type so access it
// print ur json in html tag like resposne is {"data":23}
$(<jquery selector>).html(reponse.data);
}
});
});
<?php
// echo this
$inputdata = $_GET['inputdata'];
// perform you logic ,
// make an array to encode it in json
echo $_GET['callback'].'('.json_encode($responseArr) .')';
?>
and remove PHP code from h4 tag.
In a form on index.php I post using AJAX to the submit.php file. Everything is working ok but I want to return in a special div in index.php with id #remaining a text like below.
How do I tell submit.php that this one message must be placed in the <div id="remaining"></div> of index.php ?
if($rem_posts<1)
{
echo "No credits, please buy credits";
}
else
{
There is no context in your question. The easiest way to load into a div is like so:
$('#remaining').load('submit.php');
You can use the $.load function.
$('#remaining').load('submit.php');
You can have the submit.php file echo a JSON response and use the $.ajax() success callback to place it in the appropriate location like this:
// PHP //
<?php
echo '{"remaining" : "No credits, please but credits", "foo" : "bar", "bar" : "foo"}';
?>
// JavaScript //
<script type="text/javascript">
$.ajax({
type: 'POST',
url: url,
dataType: 'json',
success: function(data){
$('#remaining').text(data.remaining); // Add Specific Message
$('#foo').text(data.bar); // Some Other Info
$('#bar').text(data.foo); // Additional Info
}
});
</script>
I hope it helps!
jquery
$("#go").click(function() {
$.post("i/go.php", $("#form").serialize());
var code= '';
$("section").empty().html(code);
});
go.php accepts POST data, then displays some text in <section>.
How to get <section> after sending POST data and display it on this page?
You are not handling the response at all, just sending the request:
$.post("i/go.php", $("#form").serialize(),
function(data) {
// do something with data
$("#some_div").html(data);
}
);