I am looking for a solution so that the user can select an appointment slot. I am trying to add a radio button, but not sure how to go about it.
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "hairdressingapointments";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT `ApointmentDate`, `ApointmentTime` FROM `apointments`
WHERE `ApointmentDate` between curdate() and curdate()+ interval '50' day
&& quantity=1 && staffID=901";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo " Apointment Date: " . $row["ApointmentDate"]. " Appointment Time: "
. $row["ApointmentTime"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
Related
please can someone help me with this code? It shows all the users’ info but i need it to show only the info of the logged user.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "username";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT AEG FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 3) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["AEG"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
Upon login, store the email/username/id in a $_SESSION variable;
$_SESSION['email'] = $email; // in this example I used email
Then on your file, you can access session variables using $_SESSION['variable'] and use it on your sql statement;
My modifications are the ones with comments.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "username";
/*Store session data in a variable*/
$email = $_SESSION['email'];
/**********************************/
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
/*Add where clause to your sql statement*/
$sql = "SELECT AEG FROM users WHERE email ='".$email."'";
/****************************************/
$result = $conn->query($sql);
if ($result->num_rows > 3) {
while($row = $result->fetch_assoc()) {
echo "id: " . $row["AEG"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
Try this one if you are having 4 user then it is showing only one
if($result->num_rows > 0)
{
while($row = $result->fetch_assoc())
{
echo "id: " . $row["AEG"]. "<br>";
}
}
else
{
echo "0 results";
}
What I wan't to do is create buttons that are automatically generated from the database. So when I add a new record in the database the button is created Is this possible with a loop? So yes how do I create the button.
This is what I have so far:
<?php
$servername = "localhost";
$username = "root";
$password = "Iamthebest1009";
$dbname = "dktp";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM theme";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "". $row["theme_name"]. "<br>";
}
} else {
echo "no results";
}
$conn->close();
?>
Yes it is possible. you need to echo html
<?php
$servername = "localhost";
$username = "root";
$password = "Iamthebest1009";
$dbname = "dktp";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM theme";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$your_url ="https://www.google.com";
echo "". $row["theme_name"]. "<br>";
echo '<input type="button" name="' . $row["theme_name"]. '" value="'. $row["theme_name"].'">';
}
} else {
echo "no results";
}
$conn->close();
?>
This is my query, and it is working fine, but how do I have the results returned in an HTML TABLE. for example I want the first 5 results on row 1 the next 5 on row 2 and so on. Any help would be great. Thank you!
<?php
$servername = "XXX";
$username = "XXX";
$password = "XXX";
$dbname = "XXX";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM manufacturer LIMIT 10 OFFSET 0";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo '<td><a href="index.php?route=product/manufacturer/info&
manufacturer_id='. $row["manufacturer_id"] .'"><img src="image/' .
$row["image"] .'"></a></td>';
}
} else {
echo "0 results";
}
$conn->close();
<?php
$servername = "XXX";
$username = "XXX";
$password = "XXX";
$dbname = "XXX";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn- >connect_error);
}
$sql = "SELECT * FROM manufacturer LIMIT 10 OFFSET 0";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
$i=0;
while($row = $result->fetch_assoc()) {
If($i==5){
echo "</tr>";
echo "<tr>";
$i=0;
}
echo '<td><a href="index.php? route=product/manufacturer/info&
manufacturer_id='. $row["manufacturer_id"] .'">. <img src="image/' .
$row["image"] .'"></a></td>';
$i++;
}
} else {
echo "0 results";
}
$conn->close();
I have a script where I try to get the date from my database.
The script needs to show: The date in the database is (date). Click here to continue. When I run the SQL query in phpMyAdmin, the SQL query returns the date. When I run it in my script I get no result.
Here is my script:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "set lc_time_names = 'nl_NL';";
$sql = "SELECT date_format(date, '%e %M %Y') AS date FROM table WHERE id='1'";
$result = $conn->multi_query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "The date in the database is:";
echo " " . $row['date'] . ". ";
echo "Click here to continue.";
}
} else {
echo "0";
}
?>
When I run this script I get 0. When I change echo "0"; with echo " " . $row['date'] . ". "; I get a empty page.
What am I doing wrong? How can I fix this?
I had another edit that isn't approved...does this work?
Just splitting your queries/variables into 2 separate ones--only only worry that first value may not persist for you.
Like so:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "set lc_time_names = 'nl_NL'";
$sql2 = "SELECT date_format(date, '%e %M %Y') AS date FROM table WHERE id='1'";
$resultZ = $conn->query($sql);
$result = $conn->query($sql2);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "The date in the database is:";
echo " " . $row['date'] . ". ";
echo "Click here to continue.";
}
} else {
echo "0";
}
?>
You are using mysqli_query (which executes exactly ONE query) and thus your script is only ever getting to the set variable statement and ending at the semicolon.
Follow the advice below--the 2nd example shows using multi_query and setting the variable value just like you do in phpMyAdmin.
Try with:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT date_format(date, '%e %M %Y') AS date FROM table WHERE id='1'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "The date in the database is:";
echo " " . $row['date'] . ". ";
echo "Click here to continue.";
}
} else {
echo "0";
}
?>
Or use multi_query:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "set lc_time_names = 'nl_NL'; SELECT date_format(date, '%e %M %Y') AS date FROM table WHERE id='1'";
$result = $conn->multi_query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "The date in the database is:";
echo " " . $row['date'] . ". ";
echo "Click here to continue.";
}
} else {
echo "0";
}
?>
You have formatted the sql script.. So instead of writing $row['date'] just put like this $row[0]
Hope this works for you..
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Using the code below I am trying to import users table into my php page and only want to show the last ten entries in a table, what else do I need to add to my code to achieve this
<?php
$servername = "localhost";
$username = "";
$password = "";
$dbname = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM dispenses";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Amount: " . $row["amount"];
}
} else {
echo "0 results";
}
$conn->close();
?>
$query = "SELECT * FROM 'users'";
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["id"];
}
} else {
echo "0 results";
}
$conn->close();
?>
This should help:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
http://www.w3schools.com/php/php_mysql_select.asp