Echo only current user details - php

please can someone help me with this code? It shows all the users’ info but i need it to show only the info of the logged user.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "username";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT AEG FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 3) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["AEG"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>

Upon login, store the email/username/id in a $_SESSION variable;
$_SESSION['email'] = $email; // in this example I used email
Then on your file, you can access session variables using $_SESSION['variable'] and use it on your sql statement;
My modifications are the ones with comments.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "username";
/*Store session data in a variable*/
$email = $_SESSION['email'];
/**********************************/
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
/*Add where clause to your sql statement*/
$sql = "SELECT AEG FROM users WHERE email ='".$email."'";
/****************************************/
$result = $conn->query($sql);
if ($result->num_rows > 3) {
while($row = $result->fetch_assoc()) {
echo "id: " . $row["AEG"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>

Try this one if you are having 4 user then it is showing only one
if($result->num_rows > 0)
{
while($row = $result->fetch_assoc())
{
echo "id: " . $row["AEG"]. "<br>";
}
}
else
{
echo "0 results";
}

Related

Dynamically generate buttons with loop php

What I wan't to do is create buttons that are automatically generated from the database. So when I add a new record in the database the button is created Is this possible with a loop? So yes how do I create the button.
This is what I have so far:
<?php
$servername = "localhost";
$username = "root";
$password = "Iamthebest1009";
$dbname = "dktp";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM theme";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "". $row["theme_name"]. "<br>";
}
} else {
echo "no results";
}
$conn->close();
?>
Yes it is possible. you need to echo html
<?php
$servername = "localhost";
$username = "root";
$password = "Iamthebest1009";
$dbname = "dktp";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM theme";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$your_url ="https://www.google.com";
echo "". $row["theme_name"]. "<br>";
echo '<input type="button" name="' . $row["theme_name"]. '" value="'. $row["theme_name"].'">';
}
} else {
echo "no results";
}
$conn->close();
?>

How to return the results of my query in rows

This is my query, and it is working fine, but how do I have the results returned in an HTML TABLE. for example I want the first 5 results on row 1 the next 5 on row 2 and so on. Any help would be great. Thank you!
<?php
$servername = "XXX";
$username = "XXX";
$password = "XXX";
$dbname = "XXX";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM manufacturer LIMIT 10 OFFSET 0";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo '<td><a href="index.php?route=product/manufacturer/info&
manufacturer_id='. $row["manufacturer_id"] .'"><img src="image/' .
$row["image"] .'"></a></td>';
}
} else {
echo "0 results";
}
$conn->close();
<?php
$servername = "XXX";
$username = "XXX";
$password = "XXX";
$dbname = "XXX";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn- >connect_error);
}
$sql = "SELECT * FROM manufacturer LIMIT 10 OFFSET 0";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
$i=0;
while($row = $result->fetch_assoc()) {
If($i==5){
echo "</tr>";
echo "<tr>";
$i=0;
}
echo '<td><a href="index.php? route=product/manufacturer/info&
manufacturer_id='. $row["manufacturer_id"] .'">. <img src="image/' .
$row["image"] .'"></a></td>';
$i++;
}
} else {
echo "0 results";
}
$conn->close();

PHP Loop through results

I am trying to loop through my database and check to see if the user already exists in another table. If they do then I want to increment a value, if they don't then I want to add the user.
When I run the code below it happily loops through all the results:
<?php
$servername = "p:10*********";
$username = "*******";
$password = "*******";
$dbname = "******";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM payroll WHERE user != ' ' ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo $result->num_rows;
while($row = $result->fetch_assoc()) {
$user = $row['user'];
$time = $row['time'];
$id = $row['id'];
echo $id;
echo $user;
}
} else {
echo "0 results";
}
$conn->close();
?>
However when I add in the SQL to check to see if they exist in the other table the loop no longer functions correctly and echos the same user each time.
<?php
$servername = "*******";
$username = "******";
$password = "********";
$dbname = "*****";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM payroll WHERE user != ' ' ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo $result->num_rows;
while($row = $result->fetch_assoc()) {
$user = $row['user'];
$time = $row['time'];
$id = $row['id'];
echo $id;
echo $user;
// Added existing user check:
$sql = "SELECT * FROM smsreport WHERE user = '$user'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "found";
} else {
echo "USER NOT FOUND";
}
}
} else {
echo "0 results";
}
$conn->close();
?>
In the open eye:
Rename the inside $result variable. It is over writting the first $result.
It could be the problem. Not tested though.

PHP Log in to show details

The website has a login system, however when a user logs into the website I simply want their details to appear on the next page. This is my code I so far. Problem is, I only want to display the logged in users details, not all the databases details.
<?php $servername = "localhost"; $username = "root"; $password = ""; $dbname = "loginsystem";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, firstname, lastname FROM members";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr><th>ID</th><th>Name</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>" . $row["id"]. "</td><td>" . $row["firstname"]. " " . $row["lastname"]. "</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
LOG IN SYSTEM
<?php
session_start();
if (isset($_POST['username'])) {
include_once("dbConnect.php");
// Set the posted data from the form into local variables
$usname = strip_tags($_POST['username']);
$paswd = strip_tags($_POST['password']);
$usname = mysqli_real_escape_string($dbCon, $usname);
$paswd = mysqli_real_escape_string($dbCon, $paswd);
$sql = "SELECT id, username, password FROM members WHERE username = '$usname' AND activated = '1' LIMIT 1";
$query = mysqli_query($dbCon, $sql);
$row = mysqli_fetch_row($query);
$uid = $row[0];
$dbUsname = $row[1];
$dbPassword = $row[2];
// Check if the username and the password they entered was correct
if ($usname == $dbUsname && password_verify($paswd,$dbPassword)) {
// Set session
$_SESSION['username'] = $usname;
$_SESSION['id'] = $uid;
// Now direct to users feed
header("Location: MemberDetails.php");
} else {
echo "Oops that username or password combination was incorrect.
<br /> Please try again.";
}
}
?>
Add
session_start();
to the top of the page and then on the next page as well and then you will be able to carry over those variables once they are set.
For example:
$_SESSION['user'] = $_POST['user'];
Then on the next page call:
echo $_SESSION['user'];
You first have to implement the user login part. and after that, get the specified user id or login credentials and use that in your query.
In your LOG IN SYSTEM file, put session_start(); before including the db connection.
Then in the member details page do this:
session_start(); //put this on the first line.
Then your query will now look like below:
<?php
$servername = "localhost"; $username = "root"; $password = ""; $dbname = "loginsystem";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$user_id = $_SESSION['id'];
$sql = "SELECT user_id, firstname, lastname FROM members WHERE user_id = ".$user_id;
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr><th>ID</th><th>Name</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>" . $row["id"]. "</td><td>" . $row["firstname"]. " " . $row["lastname"]. "</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
Database structure

How do I import info from a database to my website? [closed]

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Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 7 years ago.
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Using the code below I am trying to import users table into my php page and only want to show the last ten entries in a table, what else do I need to add to my code to achieve this
<?php
$servername = "localhost";
$username = "";
$password = "";
$dbname = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM dispenses";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Amount: " . $row["amount"];
}
} else {
echo "0 results";
}
$conn->close();
?>
$query = "SELECT * FROM 'users'";
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["id"];
}
} else {
echo "0 results";
}
$conn->close();
?>
This should help:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
http://www.w3schools.com/php/php_mysql_select.asp

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