In a table if I have:
FixtureID, HomeTeam, AwayTeam
Can I replace the ID that is related to HomeTeam and AwayTeam when it displays in the browser? HomeTeam and AwayTeam are both related to TeamID in the Teams table.
I want to show all fixtures and then replace both "TeamID" with "TeamName" so the name shows up instead of the ID?
So far I have:
$sql = <<<SQL
SELECT fix.*, tea.*
FROM Fixtures fix
INNER JOIN Teams tea USING (TeamID)
SQL;
Then
echo '<p>Fixtures</p>';
echo '<div>'.$row['HomeTeam'].' v '.$row['AwayTeam'].'</div>';
EDIT:
Ok so I found a post that was similar to what I need and have tried the following:
$sql = <<<SQL
SELECT fix.*, tea1.*, tea2.*
FROM Fixtures fix
INNER JOIN Teams tea1 ON fix.HomeTeam = tea1.TeamID
INNER JOIN Teams tea2 ON fix.AwayTeam = tea2.TeamID
SQL;
However it's still just showing the team ID's rather than the names from the Teams table.
Solved it myself
$sql = <<<SQL
SELECT f.*, t1.TeamName 'HomeTeam', t2.TeamName 'AwayTeam'
FROM Fixtures f
INNER JOIN Teams t1 ON f.HomeTeam = t1.TeamID
INNER JOIN Teams t2 ON f.AwayTeam = t2.TeamID
SQL;
Related
I have created an INNER JOIN query as shown below and was wondering how I can make it work? I need for the HomeTeam and AwayTeam to equal TeamID in the query. Any help would be much appreciated. Thanks
$result = mysqli_query($con,"SELECT results.*,team.TeamName
FROM results
INNER JOIN team ON team.TeamID = results.HomeTeam
INNER JOIN team on team.TeamID = results.AwayTeam");
You need to use aliases for the table that you are including twice. Otherwise mysql cannot distinguish between the two.
To be able to process the results easily, you can do the same with the names you are selecting.
Something like:
SELECT
results.*,
t1.TeamName AS TeamNameHome,
t2.TeamName AS TeamNameAway
FROM results
INNER JOIN team t1
ON t1.TeamID = results.HomeTeam
INNER JOIN team t2
ON t2.TeamID = results.AwayTeam
I have normalized tables I want to select the items that belong to the userid
I'm familiar with select syntax but I'm very weak in joins tables so I'm a bit confused on how to get the items that belong to the user should I use join ? or is there other way
this is just simple example of my tables they have more fields
..........
user
..........
userid
firstname
address
..........
items
..........
itemsid
itemName
itemDescription
..........
user_items
..........
userid(FK)
itemsid(FK)
Use two inner join
select a.*, b.*
from user_items as c
inner join user as a on a.userid = c.userid
inner join items as b on b.itemsid = c.itemsid;
Use INNER JOIN
SQL
select user.*, items.*
from user_items
inner join user on user.userid = items.userid
inner join items on items.itemsid = user_items.itemsid;
So if I read this correctly, user_items.userid = user.userid.
So you want to join, something like this.
SELECT i.itemsid, i.itemName, i.Description FROM items i JOIN users us ON ui.userid = us.userid JOIN user_items ui ON ui.itemsid = i.itemsid WHERE ui.userid = VALUE;
Replace Value with your actuall user id
I am using php and I have to get the data from multiple tables with common id, but the problem is that in few tables that common id contains multiple records,using inner join gives me separate rows of data e.g.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"2"}
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"3"}
extraId is the multiple record for the dish_id:52.
I need result like this.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId"[{"id":"2"},{"id":"3"]}}
My query is:
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status'";
please help.
Use group by and group_concat. Something like this:
Select d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type,
group_concat(e.extra_id) as extraids
from order_main m INNER JOIN
order_detail d
ON m.id = d.order_id INNER JOIN
order_extras e
ON m.id = e.order_id INNER JOIN
order_addons a
ON m.id = a.order_id
where m.franchise_id = '$storeId' and d.STATUS <> '$order_status'
group by d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type;
Your desired results do not include these columns:
e.extra_title
a.addon_id
a.addon_size
I would also suggest that you remove the join to order_addons.
Notice that table aliases make the query easier to write and to read.
You can use group bywith dish_id
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status' group by order_detail.dish_id";
I have the following query which works perfectly:
SELECT *
FROM contacts
WHERE id in (
SELECT DISTINCT contacts.id
FROM contacts
INNER JOIN contacts2tags
ON contacts.id = contacts2tags.contactid
WHERE tagid in(7,4)
)
Here contacts table contains id, first_name, last_name, ..and tags table contains id, name. contacts2tags table contains contactid and tagid which are same as contacts.id and tags.id respectively
Now, what I want is, to display only the contacts which have both a tagid 7 and a tagid 4.
I tried something like this:
SELECT *
FROM contacts
WHERE id IN
(
SELECT CT1.contactid
FROM
tags T1, contacts2tags CT1, tags T2, contacts2tags CT2
WHERE CT1.contactid = CT2.contactid
AND CT1.tagid = T1.id
AND CT2.tagid = T2.id
AND (T1.id = 7 AND T2.id = 4)
and it works too.
My problem is, I want to convert the above second query to one using inner joins.
I have an array of ids stored in $tmp in php
I want to use those ids and write the above query for them.
How do I do that? I am not comfortable with sql. Might be its a very simple thing to ask.
Thanks in advance
EDIT:
The answer below solved the problem. But the sql runs very slow for 10k records. Any suggestions to optimise it? Pasting the updated query as given in the answer.
SELECT c.id
FROM contacts c
inner join contacts2tags t on c.id = t.contactid
where t.tagid in (7,4)
group by c.id
having count(distinct t.tagid) = 2
This should work
SELECT c.id
FROM contacts c
inner join contacts2tags t on c.id = t.contactid
where t.tagid in (7,4)
group by c.id
having count(distinct t.tagid) = 2
I have 3 tables that reference each other.. Leagues, Teams, and Players.
Leagues have leagueid, leaguename, city
Teams have teamid, teamname, numberofplayers, leagueid(fk)
Players have playerid, playername, position, teamid(fk)
How can I display a table such as Players to show all of the contents and using the teamid foreign key, display their team name instead of that column?
SELECT Players.*, teamname
FROM Players JOIN Teams USING (teamid)
You just need to join on the teamid column that matches between the two tables.
You need to join both tables use INNER JOIN.
SELECT a.*, b.*
FROM Players a
INNER JOIN Teams b
ON a.teamid = b.teamid
To further gain more knowledge about joins, kindly visit the link below:
Visual Representation of SQL Joins
By using inner join
SELECT b.teamname,a.playername, a.position
FROM Players a
INNER JOIN Teams b
ON a.teamid = b.teamid
If you are specifying the league,
SELECT c.leaguename, c.city ,d.* FROM
(SELECT b.teamname,a.playername, a.position
FROM Players a
INNER JOIN Teams b
ON a.teamid = b.teamid) d
INNER JOIN Leagues c
ON d.leagueid= c.leagueid