I have created an INNER JOIN query as shown below and was wondering how I can make it work? I need for the HomeTeam and AwayTeam to equal TeamID in the query. Any help would be much appreciated. Thanks
$result = mysqli_query($con,"SELECT results.*,team.TeamName
FROM results
INNER JOIN team ON team.TeamID = results.HomeTeam
INNER JOIN team on team.TeamID = results.AwayTeam");
You need to use aliases for the table that you are including twice. Otherwise mysql cannot distinguish between the two.
To be able to process the results easily, you can do the same with the names you are selecting.
Something like:
SELECT
results.*,
t1.TeamName AS TeamNameHome,
t2.TeamName AS TeamNameAway
FROM results
INNER JOIN team t1
ON t1.TeamID = results.HomeTeam
INNER JOIN team t2
ON t2.TeamID = results.AwayTeam
Related
Basically i am working with 2 tables, one is the cars and one is comments and i am trying to get the count of approved comments for certain cars + the cars information, but i would like it to be dynamic if i put in the id of the car directly it will work but when i say where id = car id it returns nothing?
This works with "10" it will give me the information + the count of comments
SELECT t1.biler_id, t1.biler_navn, COUNT(t2.bilbixen_commentary_status)
FROM bilbixen_biler t1
INNER JOIN bilbixen_commentary t2 ON t1.biler_id = t2.bilbixen_commentary_bil
WHERE t1.biler_id = 10
The above query will return this in phpmyadmin
The below query don't work, i am trying to tell it to find everything where t1.id is equal t2.id
SELECT t1.biler_id, t1.biler_navn, COUNT(t2.bilbixen_commentary_status)
FROM bilbixen_biler t1
INNER JOIN bilbixen_commentary t2 ON t1.biler_id = t2.bilbixen_commentary_bil
WHERE t1.biler_id = t2.bilbixen_commentary_bil
The above query will give me this error in phpmyadmin
I expected it to return all the information for each car with a count of comments for each of them
Your where clause is useless and you need a group by clause since you are using the aggregate function count.
select t1.biler_id,
t1.biler_navn,
COUNT(t2.bilbixen_commentary_status)
from bilbixen_biler t1
left join bilbixen_commentary t2 on t1.biler_id = t2.bilbixen_commentary_bil
group by t1.biler_id,
t1.biler_navn
You have used the aggregate function COUNT so you have to group by t1.biler_id, t1.biler_navn fields:
SELECT t1.biler_id, t1.biler_navn, COUNT(t2.bilbixen_commentary_status)
FROM bilbixen_biler t1
INNER JOIN bilbixen_commentary t2 ON t1.biler_id = t2.bilbixen_commentary_bil
GROUP BY t1.biler_id, t1.biler_navn
Hello i'm learning sql and i have some issues with joins(which i have problems understanding them)
I have this issue
#1066 - Not unique table/alias: 'tbl_respuestas'
what the query supposed to do, is count how many people(general,ignore user) has answer 'x', in 'y' question of 'z' survey
SELECT COUNT(*) FROM tbl_respuestas
INNER JOIN tbl_encuesta_usuario ON tbl_encuesta_usuario.user_id = user.id
INNER JOIN tbl_encuesta ON tbl_encuesta.id = tbl_encuesta_usuario.tbl_encuesta_id
INNER JOIN tbl_encuesta_has_tbl_preguntas ON tbl_encuesta_has_tbl_preguntas.tbl_encuesta_id = tbl_encuesta.id
INNER JOIN tbl_preguntas ON tbl_preguntas.id = tbl_encuesta_has_tbl_preguntas.tbl_preguntas_id
INNER JOIN tbl_preguntas_has_tbl_respuestas ON tbl_preguntas_has_tbl_respuestas.tbl_preguntas_id = tbl_preguntas.id
INNER JOIN tbl_respuestas ON tbl_respuestas.id = tbl_preguntas_has_tbl_respuestas.tbl_respuestas_id
WHERE tbl_respuestas.respuesta = 2
line SELECT COUNT(*) FROM tbl_respuestas
and line INNER JOIN tbl_respuestas
does not makes sense, hence the error.
Unless it is what you want then you need to give then different name/alias like below:
SELECT COUNT(*) FROM tbl_respuestas r
INNER JOIN tbl_respuestas r2
Also as a quick note you can rewrite the entire sql like below.
It is good practice to give your tables a name for shorter referencing and makes the sql look a little cleaner.
Also if both tables you are trying to join has the same column name then you can use the keyword USING instead of having to write that long line tbl_encuesta_usuario.user_id = user.id
Please be sure to put r and r2 in its prope place
SELECT COUNT(*) FROM tbl_respuestas r
INNER JOIN tbl_encuesta_usuario u USING user_id
INNER JOIN tbl_encuesta e ON e.id = u.tbl_encuesta_id
INNER JOIN tbl_encuesta_has_tbl_preguntas hp ON hp.tbl_encuesta_id = e.id
INNER JOIN tbl_preguntas p ON p.id = hp.tbl_preguntas_id
INNER JOIN tbl_preguntas_has_tbl_respuestas hr ON hr.tbl_preguntas_id = p.id
INNER JOIN tbl_respuestas r2 ON r2.id = hr.tbl_respuestas_id
WHERE r.respuesta = 2
So I have 2 tables, Matches and Teams, what I want to do is get some values from the match and Inner join "Teams" to get the names of both teams and add them to a php array later on (getting it all in one sql)
Matches
- IDMatch
- IDLocalTeam
- IDVisitorTeam
- Time
- Half
- Stopped
Teams
- IDTeam
- name
What I have by now is
$query = "SELECT * FROM `Matches`
INNER JOIN `Teams` ON `Matches`.IDLocalTeam = `Teams`.IDTeam
UNION SELECT * FROM `Matches` INNER JOIN `Teams`
ON `Matches`.IDVisitorTeam = `Teams`.IDTeam
ORDER BY IDMatch DESC;";
If someone could help me it would be great! Thanks alot
Wouldn't it be easier to use INNER JOIN twice? It's definitely quicker way of doing joins anyway.
SELECT
*
FROM
`Matches` m
INNER JOIN `Teams` t1
ON m.IDLocalTeam = t1.IDTeam
INNER JOIN `Teams` t2
ON m.IDVisitorTeam = t2.IDTeam
ORDER BY
m.IDMatch DESC;
Also start using aliases instead of table names to identify fields in query, it will SQL much smaller.
I am using php and I have to get the data from multiple tables with common id, but the problem is that in few tables that common id contains multiple records,using inner join gives me separate rows of data e.g.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"2"}
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"3"}
extraId is the multiple record for the dish_id:52.
I need result like this.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId"[{"id":"2"},{"id":"3"]}}
My query is:
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status'";
please help.
Use group by and group_concat. Something like this:
Select d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type,
group_concat(e.extra_id) as extraids
from order_main m INNER JOIN
order_detail d
ON m.id = d.order_id INNER JOIN
order_extras e
ON m.id = e.order_id INNER JOIN
order_addons a
ON m.id = a.order_id
where m.franchise_id = '$storeId' and d.STATUS <> '$order_status'
group by d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type;
Your desired results do not include these columns:
e.extra_title
a.addon_id
a.addon_size
I would also suggest that you remove the join to order_addons.
Notice that table aliases make the query easier to write and to read.
You can use group bywith dish_id
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status' group by order_detail.dish_id";
In a table if I have:
FixtureID, HomeTeam, AwayTeam
Can I replace the ID that is related to HomeTeam and AwayTeam when it displays in the browser? HomeTeam and AwayTeam are both related to TeamID in the Teams table.
I want to show all fixtures and then replace both "TeamID" with "TeamName" so the name shows up instead of the ID?
So far I have:
$sql = <<<SQL
SELECT fix.*, tea.*
FROM Fixtures fix
INNER JOIN Teams tea USING (TeamID)
SQL;
Then
echo '<p>Fixtures</p>';
echo '<div>'.$row['HomeTeam'].' v '.$row['AwayTeam'].'</div>';
EDIT:
Ok so I found a post that was similar to what I need and have tried the following:
$sql = <<<SQL
SELECT fix.*, tea1.*, tea2.*
FROM Fixtures fix
INNER JOIN Teams tea1 ON fix.HomeTeam = tea1.TeamID
INNER JOIN Teams tea2 ON fix.AwayTeam = tea2.TeamID
SQL;
However it's still just showing the team ID's rather than the names from the Teams table.
Solved it myself
$sql = <<<SQL
SELECT f.*, t1.TeamName 'HomeTeam', t2.TeamName 'AwayTeam'
FROM Fixtures f
INNER JOIN Teams t1 ON f.HomeTeam = t1.TeamID
INNER JOIN Teams t2 ON f.AwayTeam = t2.TeamID
SQL;