uploading a image but error of undefined index [duplicate] - php

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Reference - What does this error mean in PHP?
(38 answers)
Closed 7 years ago.
I have a form in which i have to upload the image by its category and move the selected category image to specific folder but when i submit the form the following error occurs
( ! ) Notice: Undefined index: pic in C:\wamp\www\movies poster admin\insertform.php on line 26
the pic is the name of the file but don't know why it did not get the value
I know this is a very basic question but i don't know why this error is coming
$imageprice=$_POST['imageprice'];
$imagedescription=$_POST['imagedescription'];
$type=$_POST['category'];
if ($type="celeb") {
$uploadDir = 'C:/wamp/www/Movies Poster Site/celeb/'; //Image Upload Folder
$fileName = $_FILES['pic']['name'];
$tmpName = $_FILES['pic']['tmp_name'];
$fileSize = $_FILES['pic']['size'];
$fileType = $_FILES['pic']['type'];
$filePath = $uploadDir . $fileName;
$filename = $fileName;
$ext = pathinfo($filename, PATHINFO_EXTENSION);
//$date = date_create();
//$fileName= date_timestamp_get($date).".".$ext;
$filePath = $uploadDir . $fileName;
if (isset($fileName)) {
# code...
$result = move_uploaded_file($tmpName, $filePath);
}
if(!get_magic_quotes_gpc())
{
$fileName = addslashes($fileName);
$filePath = addslashes($filePath);
}
`
`$sql="INSERT INTO celeb ".
"(image_name,price,description,Type) ".
"VALUES ".
"('$filePath','$imageprice','$imagedescription','$type') ";
mysql_select_db('poster');
$retval = mysql_query( $sql, $connection );
if(! $retval )
{
die('Could not enter data: ' . mysql_error());
}
else
{
echo" <div class='end'>";
echo "Data Entered";
echo"</div>";
mysql_close($connection);
}
Here is the form
<form method="post">
<div class="insertform">
<!-- <input type="text" placeholder="image.jpg" name="imagename" id="imagename"><br>
-->
Select Image Category:<br>
<input type="radio" name="category" value="comic">Comic Posters<br>
<input type="radio" name="category" value="celeb">Celeb Posters<br>
<input type="radio" name="category" value="islamic">Islamic Posters<br>
<input type="radio" name="category" value="tv">TV Posters<br>
<input type="radio" name="category" value="motor">Motor Posters<br />
<input type="radio" name="category" value="sports">Sports Posters<br><br />
Image Name :<br>
<input style="margin-left:10px;" id="uploadImage" required="required" name="pic" type="file" size="4
000000" accept="image/gif, image/jpeg, image/x-ms-bmp, image/x-png" > <br>
Image Price :<br>
<input type="text" placeholder="Rs xxx" name="imageprice" id="price"><br>
Image Description :<br>
<input type="text" name="imagedescription" id="description" height="300px"><br /><br>
<input type="submit" name="submit" value="Submit">
</div>

Answer 1

try like this,
$fileName = $_FILES['pic']['name'][0];