Multiple image upload - php

Question

i have a problem in multiple image upload, when i upload, there's only 1 image which go to the targeted directory and database. i need two images to go directory and database...any help please?
this is my form
<form action="test.php" method="post" enctype="multipart/form-data">
Keywords: <input style="margin-left:35px;" type="text" name="keyword" /><br />
Name: <input style="margin-left:60px;" type="text" name="name" /><br />
Name2: <input style="margin-left:60px;" type="text" name="name2" /><br />
Categorie: <input style="margin-left:40px;" type="text" name="categorie" /><br />
Lieu: <input style="margin-left:70px;" type="text" name="lieu" /><br /><br />
<input type="file" name="file[]" multiple="multiple" /><input type="file" name="file_2[]" multiple="multiple"/><input type="submit" name="submit" value="Upload" />
</form>
<?php
$connect = mysql_connect("localhost", "root", "");
$select_db = mysql_select_db("yakatrouver_test", $connect);
if(#$_POST['submit']){
$keywords = $_POST['keyword'];
$name = $_POST['name'];
$name2 = $_POST['name2'];
$categorie = $_POST['categorie'];
$lieu = $_POST['lieu'];
$file = $_FILES['file'];
$file_name = $file['name'];
$file_type = $file['type'];
$file_size = $file['size'];
$file_path = $file['tmp_name'];
$file_2 = $FILES['file_2'];
$file_name_2 = $file['name'];
$file_type_2 = $file['type'];
$file_size_2 = $file['size'];
$file_path_2 = $file['tmp_name'];
if($file_name!="" && ($file_type="image/jpeg"||$file_type="image/png"||$file_type="image/gif") && $file_size<=2000000)
if(move_uploaded_file ($file_path, 'pictures_uploaded/' .$file_name))
$query = mysql_query("INSERT INTO `user_input`(keyword, name, categorie, lieu) VALUES ('$keywords', '$name', '$categorie', ' $lieu')");
$query = mysql_query("UPDATE `user_input` set image='pictures_uploaded/$file_name' WHERE `name`='$name'");
if($query == true)
{
echo "file Uploaded";
}
}
$result = mysql_query("SELECT * FROM `user_input` WHERE `image`=''") or die(mysql_error());
while($row = mysql_fetch_array($result))
?>

Answer 1

Try:-
HTML:
<input type="file" name="file[]"/>
<input type="file" name="file[]"/>
<input type="file" name="file[]"/>
PHP:
$file_count = count($_FILES['file']['name']);
for($i=0;$i<$file_count;$i++) {
$file_name = $_FILES['file']['name'][$i];
$file_type = $_FILES['file']['type'][$i];
$file_size = $_FILES['file']['size'][$i];
$file_path = $_FILES['file']['path'][$i];
if($file_name!="" && ($file_type="image/jpeg"||$file_type="image/png"||$file_type="image/gif") && $file_size<=2000000)
if(move_uploaded_file ($file_path, 'pictures_uploaded/' .$file_name))
$query = mysql_query("INSERT INTO `user_input`(keyword, name, categorie, lieu) VALUES ('$keywords', '$name', '$categorie', ' $lieu')");
$query = mysql_query("UPDATE `user_input` set image='pictures_uploaded/$file_name' WHERE `name`='$name'");
if($query == true)
{
echo "file Uploaded";
}
}
} //close the braces accordingly, some seem to be missing in your code
I think it's self-explanatory. It's just looping through your file input array, fetching each file information and processing one at at time.