display exact array elements using php - php

Question

I am able to display all the array elements using the code below but I would like to know how can I display several array elements only (for example 4th, 6th and 11th). Could you please help me.
$rates = $data->Rates->ExchangeRate;
if (is_array($rates) && count($rates) > 0) {
echo '<table><tr><th>ISO</th><th>Rate</th></tr>';
foreach ($rates as $rate) {
echo '<tr>';
echo '<td>' . $rate->ISO . '</td><td>' . $rate->Rate . '</td></tr>';
echo '</tr>';
}
echo '</table>';
}

Answer 1

Just make an array of allowable key values and everytime check if the current key is included:
$rates = $data->Rates->ExchangeRate;
$allow = array(4,6,11);
if (is_array($rates) && count($rates) > 0) {
echo '<table><tr><th>ISO</th><th>Rate</th></tr>';
foreach ($rates as $key => $rate) {
if(!in_array($key, $allow){
continue;//if not allowed, go to next iteration
}
echo '<tr>';
echo '<td>' . $rate->ISO . '</td><td>' . $rate->Rate . '</td></tr>';
echo '</tr>';
}
echo '</table>';
}

Answer 2

You could filter the array in any number of ways before iterating over it, or you could use a condition inside the loop
$rates = $data->Rates->ExchangeRate;
if (is_array($rates) && count($rates) > 0) {
echo '<table><tr><th>ISO</th><th>Rate</th></tr>';
$count = 0;
$show = array(4, 8, 11);
foreach ($rates as $rate) {
if ( in_array($count++, $show) ) {
echo '<tr>';
echo '<td>' . $rate->ISO . '</td><td>' . $rate->Rate . '</td>';
echo '</tr>';
}
}
echo '</table>';
}

Answer 3

Other answers have given solutions but i think are slower than one posted here (use an array of included indices i.e $included_indices = array(4,6,11);):
$rates = $data->Rates->ExchangeRate;
if (is_array($rates) && count($rates) > 0) {
echo '<table><tr><th>ISO</th><th>Rate</th></tr>';
foreach ($included_indices as $included_indice) {
$rate = $rates[$included_indice];
echo '<tr>';
echo '<td>' . $rate->ISO . '</td><td>' . $rate->Rate . '</td></tr>';
echo '</tr>';
}
echo '</table>';
}