PHP For Loop jQuery UI Tabs - php

I am trying to display a list of Links in a table according to Distance and Category. I would like each distance to be a Tab and have the appropriate Links in each Tab. I am trying to accomplish this with A PHP Foreach loop and jQuery-UI Tabs.
Here is the code which gets the data and displays it in the table in each Tab.
The index function in the controller for the View and the function that gets the table data:
public function index() {
$data = array();
$db_name = $this->uri->segment(2);
$this->db->db_select($db_name);
$tables = $this->db->get('tableinfo');
$data['distances'] = array();
$data['tables'] = array(
'men' => array(),
'women' => array()
);
foreach($tables->result() as $row) {
if(!in_array($row->distance, $data['distances'])) {
array_push($data['distances'], $row->distance);
}
if(substr($row->displayname, 0, 4) == "Male") {
array_push($data["tables"]['men'], $row->displayname);
} else {
array_push($data["tables"]['women'], $row->displayname);
}
}
$data['dbname'] = $db_name;
$this->parser->parse('templates/header', $data);
$this->parser->parse('select/index', $data);
$this->parser->parse('templates/footer', $data);
}
public function gettable($table) {
$db_name = "championchipco_sowetomarathon2019";
$this->db->db_select($db_name);
redirect("results/index/" . $db_name . "/" . $table);
}
And the View:
<?php
$i = 1;
echo "<div class='row'>";
echo "<div class='col' id='tabs'>";
echo "<ul>";
foreach($distances as $distance) {
echo "<li><a href='#tabs-" . $i . "'>" . $distance . "</a></li>";
}
echo "</ul>";
foreach($distances as $distance) {
echo "<div id='tabs-" . $i . "'>";
echo "<table class='table' cellspacing='10' cellpadding='10'>";
echo "<tr><th style='font-size: 20px;'>Men</th><th style='font-size: 20px;'>Women</th><th style='font-size: 20px;'></tr>";
foreach($tables['men'] as $table) {
if(substr($table, -4) == $distance) {
echo "<tr>";
echo '<td>' . $tables['men'][$i] . '</td>';
echo '<td>' . $tables['women'][$i] . '</td>';
echo "</tr>";
}
}
echo "</table>";
echo "</div>";
$i++;
}
echo "</div>";
echo "</div>";
?>
At the moment, all of the data is being displayed in every Tab, instead of only display the Links for the particular category in a different tab. I can see that the 2nd table of Men and Women is slightly to the left of the top one so I think the loop is causing something to go wrong.
I have tried re-arranging the way the loops display the data in the View but cannot seem to get only the 10KM in the 10KM Tab, 21KM in 21KM Tab, etc.

Get the data of your second foreach by Ajax it will made your need simple
I mentioned to remove below foreach
foreach($distances as $distance) {
echo "<div id='tabs-" . $i . "'>";
echo "<table class='table' cellspacing='10' cellpadding='10'>";
echo "<tr><th style='font-size: 20px;'>Men</th><th style='font-size: 20px;'>Women</th><th style='font-size: 20px;'></tr>";
foreach($tables['men'] as $table) {
if(substr($table, -4) == $distance) {
echo "<tr>";
echo '<td>' . $tables['men'][$i] . '</td>';
echo '<td>' . $tables['women'][$i] . '</td>';
echo "</tr>";
}
}
echo "</table>";
echo "</div>";
$i++;
}

Related

While Loop For Table Rows From MySQL With Colour Coded Cells Based On Score

I have a MySQL table of results of collected responses on a form that I want to output in a table.
The user rates certain variables such as Sleep from good (1) to bad (7) and each users results are on each row.
I did that successfully, but to make it more readable I want to colour code the scores based on score.
E.g., if you score 2 or below the table cell should be green, and if you score 6 or above it is coloured red.
There are 5 different variables being rated so not sure if the method I am using would work or if something more suitable.
$sql = "SELECT * FROM Responses";
$result = mysqli_query($link, $sql);
while ($row = mysqli_fetch_array($result))
{
echo '<tr>';
if($row['Sleep'] <= 2)
{
echo "<td style='background-color: green;'>" . $row['Sleep'] . "</td>";
}
elseif ($row['Sleep'] >= 6)
{
echo "<td style='background-color: red;'>" . $row['Sleep'] . "</td>";
}
else
{
echo "<td>" . $row['Sleep'] . "</td>";
}
echo '</tr>';
}
No output
Maybe so
function getColor($number)
{
if ($numner <= 2)
return 'green';
else if ($numner > 2 && $var < 6)
return 'black';
else if ($number >= 6)
return 'red';
}
$sql = "SELECT * FROM Responses";
$result = mysqli_query($link, $sql);
while ($row = mysqli_fetch_array($result))
{
echo '<tr>';
echo '<td>' . $row["Name"] . '</td>';
echo '<td style="background-color: "' . $getColor($row["Sleep"]) . '">' . $row["Sleep"] . '</td>';
}
You just put your different variables in an array
function getColor($number)
{
if ($number <= 2)
return 'green';
else if ($number > 2 && $number < 6)
return 'none';
else if ($number >= 6)
return 'red';
}
echo "<table>";
while ($row = mysqli_fetch_array($result))
{
//replace var* with your variable
$variables = array("Sleep", "var2", "var3", "var4", "var5");
echo '<tr>';
echo '<td>' . $row["Name"] . '</td>';
$i=0;
while($i<5)
{
$score=$row[$variables[$i]];
echo '<td style="background-color: ' . getColor($score). ';">' . $score . '</td>';
$i++;
}
echo '</tr>';
}
echo "</table>";

PHP array display does not display all columns

I managed to get the checkboxes to POST the data and displays each on the checkout page but the problem I have is when it gets to 4th column it stops when it hits a certain char limit also how would I turn this into a table on the checkout page.
Database snippet code:
print '<td><input type="checkbox" name="check_list[]"value='. $getColumn[0]. $getColumn[1]. $getColumn[2]. $getColumn[3]. $getColumn[4]. $getColumn[5].$getColumn[6].$getColumn[7].$getColumn[8].$getColumn[9].'</td>';
for ($column = 1; $column < pg_num_fields($res); $column++)
{
print "<td>" . $getColumn[$column] . "</td>";
}
}
print '</table>'
Checkout page
<?php
echo "<hr />\n";
$res = pg_query ($con, "select count(ref) from music");
$a = pg_fetch_row($res);
echo "<p>Total " . $a[0] . " music in database.</p>";
echo "<table border='1'>\n<thead>\n<tr>\n";
echo "<th>Artist</th><th>Composer</th><th>Genre</th><th>Title</th><th>Album</th><th>Label</th> <th>Price</th><th>Description</th>\n";
echo "</tr>\n</thead>\n<tbody>\n";
$res=pg_query($con, "SELECT * from music ORDER BY ref");
while ($a = pg_fetch_array ($res))
{
echo "<tr>";
for ($j = 0; $j < pg_num_fields($res); $j++) {
// htmlspecialchars converts things like & to HTML entity codes
echo "<td>" . htmlspecialchars($a[$j], ENT_QUOTES) . "</td>";
}
echo "</tr>\n";
}
echo "</tbody>\n</table>";
?>
I am sure, you are tried to do the following:
print '<table>';
for ($column = 1; $column < pg_num_fields($res); $column++) {
echo '<tr>';
print '<td><input type="checkbox" name="check_list[]" value="'.$getColumn[$column] .'" /></td>';
print "<td>" . $getColumn[$column] . "</td>";
echo '</tr>';
}
print '</table>';

format when column has specific name,

the roblem is where there is the punch commentator
i need when the column has INTER name or OUTER name to format the content of the $cell
with $cell=number_format($cell,2,',','.')
i'm just starting using php so don be too specific thanks
<?php
// printing table rows
$rigapadi = 1 ;
while($row = mysql_fetch_row($result))
{
echo "<tr>";
$rigapadi=$rigapadi+1;
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
if ($rigapadi % 2 == 0) {
# if column name = 'INTER' or 'OUTER' $cell = number_format($cell, 2, ',', '.');
echo "<td align=\"center\">$cell</td>";
} else {
echo "<td bgcolor=\"#E9EEF5\" align=\"center\">$cell</td>";
}
echo "</tr>\n";
}
mysql_free_result($result);
echo "</table>";
echo "<p/>";
?>
The mysql_ are obsoltes. You must not use them. And please indent your code properly when you ask for help.
<?php
$rigapadi = 1;
while($row = mysql_fetch_assoc($result)) {
echo '<tr>';
$rigapadi++;
foreach($row as $name => $cell) {
if($rigapadi % 2 === 0) {
if($name === 'INTER' || $name === 'OUTER') {
echo '<td align="center">' . number_format($cell, 2, ',', '.') . '</td>';
} else {
echo '<td align="center">' . $cell . '</td>';
}
} else {
echo '<td align="center" bgcolor="#E9EEF5">' . $cell . '</td>';
}
}
echo "</tr>\n";
}
mysql_free_result($result);
echo "</table>";
?>
Note that I use fetch_assoc to get the $name.
PS: <p/> does not exists and align and bgcolor and not valids but acceptable if this is a HTML code for an e-mail.

Tables are displayed horizontally instead of vertical [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
Improve this question
I'm trying to create an table with PHP and HTML which gets the data from a MySQL database.
The problem is that the data is displayed horizontally and not vertical.
if (isset($_POST['winneron'])) {
echo "<tr>";
while ($printuser = mysql_fetch_array($user)) {
echo "<th>". $printuser['username'] . "</th>";
}
echo "</tr>";
while ($printgames = mysql_fetch_array($games)) {
if ( $printgames ['winner'] == $printgames ['team1'] ) {
echo "<td><b>". strtoupper($printgames ['winner']) . "</b></td>";
}
else {
echo "<td>". strtoupper($printgames ['winner']) . "</td>";
}
}
}
Hope somebody can help me.
If you want your display to be vertical then you have to put each piece of information into a table row <tr><td>...</td></tr>
while ($ausgabespiele = mysql_fetch_array($spiele)) {
if ( $ausgabespiele['sieger'] == $ausgabespiele['team1'] ) {
echo "<tr><td><b>". strtoupper($ausgabespiele['sieger']) . "</b></td></tr>";
}
else {
echo "<tr><td>". strtoupper($ausgabespiele['sieger']) . "</td></tr>";
}
}
There are no <tr> and </tr> in your while ($ausgabespiele = mysql_fetch_array($spiele)) { }...
You are missing TR in while
if (isset($_POST['winneron'])) {
echo "<tr>";
while ($ausgabeuser = mysql_fetch_array($user)) {
echo "<th>". $ausgabeuser['username'] . "</th>";
}
echo "</tr>";
while ($ausgabespiele = mysql_fetch_array($spiele)) {
echo "<tr>";
if ( $ausgabespiele['sieger'] == $ausgabespiele['team1'] ) {
echo "<td><b>". strtoupper($ausgabespiele['sieger']) . "</b></td>";
}
else {
echo "<td>". strtoupper($ausgabespiele['sieger']) . "</td>";
}
echo "</tr>";
}
}
You have to add the row-tags within the while loop...
if (isset($_POST['winneron'])) {
echo "<tr>";
while ($ausgabeuser = mysql_fetch_array($user)) {
echo "<th>". $ausgabeuser['username'] . "</th>";
}
echo "</tr>";
while ($ausgabespiele = mysql_fetch_array($spiele)) {
echo "<tr>";
if ( $ausgabespiele['sieger'] == $ausgabespiele['team1'] ) {
echo "<td><b>". strtoupper($ausgabespiele['sieger']) . "</b></td>";
}
else {
echo "<td>". strtoupper($ausgabespiele['sieger']) . "</td>";
}
echo "</tr>";
}
}
You forget to create a table row insde the loop. To display vertically you need to place the table cells in rows:
while ($ausgabespiele = mysql_fetch_array($spiele)) {
echo "<tr>";
if ( $ausgabespiele['sieger'] == $ausgabespiele['team1'] ) {
echo "<td><b>". strtoupper($ausgabespiele['sieger']) . "</b></td>";
}
else {
echo "<tr><td>". strtoupper($ausgabespiele['sieger']) . "</td></tr>";
}
echo "</tr>";
}
Try this -
if (isset($_POST['winneron'])) {
$echo = "<tr>";
while ($ausgabeuser = mysql_fetch_array($user)) {
$echo .= "<th>". $ausgabeuser['username'] . "</th>";
}
$echo .= "</tr><tr>";
while ($ausgabespiele = mysql_fetch_array($spiele)) {
if ($ausgabespiele['sieger'] == $ausgabespiele['team1'])
$echo .= "<td><b>". strtoupper($ausgabespiele['sieger']) . "</b></td>";
else
$echo .= "<td>". strtoupper($ausgabespiele['sieger']) . "</td>";
}
$echo .= "</tr>";
echo $echo;
}

Data Loop gone wrong

I've got the first round of this loop displaying correctly.
What I want is 5 rows of 8 columns. What I'm getting is the first group displays correctly and the second group displays as 10 columns.
Where am I going wrong?
echo '<table align="center" width="70%"><tr>';
$count = 0;
$rowCount = 0;
while ( $row = mysql_fetch_array($result))
{
$count++;
echo "<td><a href='" . $row['URL'] . "'><img src='" . $row['IMG'] . "' width='120' h eight='160'/></a></td>";
if ($count % 8 === 0)
{
echo '</tr>';
$rowCount++;
if($rowCount % 8 === 0)
{
echo '</tr></table><br><br>Adds here<br><br><tablealign="center" width="70%"><tr>';
}else{
echo '<tr>';
}
}
}
echo ' </tr></table>';
You're trying to make it a little too complicated.
Separate out the functionality for the column counts versus the row counts:
<?php
echo '<table align="center" width="70%"><tr>';
$count = 0;
$rowCount = 0;
while($row = mysql_fetch_array($result))
{
$count++;
echo "<td><a href='" . $row['URL'] . "'><img src='" . $row['IMG'] . "' width='120' h eight='160'/></a></td>";
if($count%8===0)
{
$rowCount++;
echo '</tr>';
if($rowCount%5===0)
{
echo '</table><br/><br/>Adds Here<br/><br/><table align="center" width="70%"><tr>';
$rowCount = 0;
}
}
}
echo ' </tr></table>';

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