Sum of value using condition in mysql - php

I have a table like this. Now i want two sum(hour).. 1 for place_type '1' and another for place_type '2'. Is it possible in mysql?
Now my query is
SELECT sum(hour) as totalHour from category_data group by category_data.user_id
also tried with IF condition but not working
SELECT IF(place_type='1',sum(hour),0) home,
IF(place_type='2', sum(hour), 0) center,
from category_data group by category_data.user_id
user_id place_type hour
1 1 2
1 2 5
2 1 3
2 2 4
3 1 2
Thanks in advance

Conditional aggregation is what you need here.
select sum(case when place_type = 1 then `hour` end),
sum(case when place_type = 2 then `hour` end)
from category_data
Example fiddle

Related

select column names whose entries are value 1

I want to retrieve columns name from table whose value is 1
My query is give below...
mysqli_query($conn,"SELECT * FROM `tbl_therapist_schedule` WHERE `schedule_date`='30.11.2017'");
My table structure is give below...
slot1 slot2 slot3
1 1 0
2 1 1
1 1 2
3 1 0
my result...
slot1 slot2 slot3
I have the serious feeling that your data is not normalized. Instead of having separate columns for each slot, I would store all this data in a single column with metadata to relate each slot's state.
That being said, one way to get the output you want would be to aggregate over each slot column and check for the presence/absence of at least one 1 value. I then use GROUP_CONCAT to generate a CSV list of matching slots.
SELECT GROUP_CONCAT(slots)
FROM
(
SELECT
CASE WHEN SUM(CASE WHEN slot1 = 1 THEN 1 ELSE 0 END) > 0
THEN 'slot1' END AS slots
FROM tbl_therapist_schedule
WHERE schedule_date = '30.11.2017'
UNION ALL
SELECT
CASE WHEN SUM(CASE WHEN slot2 = 1 THEN 1 ELSE 0 END) > 0
THEN 'slot2' END
FROM tbl_therapist_schedule
WHERE schedule_date = '30.11.2017'
UNION ALL
SELECT
CASE WHEN SUM(CASE WHEN slot3 = 1 THEN 1 ELSE 0 END) > 0
THEN 'slot3' END
FROM tbl_therapist_schedule
WHERE schedule_date = '30.11.2017'
) t;
Demo

MySQL - Update Column if all rows are equal

I have N Rows with same SlNo but different RowNo as shown below
for eg:
SlNo RowNo Status
1 1 Opened
1 2 Closed
1 3 Opened
1 4 Closed
1 5 Opened
If all the Status Column Rows are Closed , I want to return 1.
else o.
Thanks in advance.
You can do it following:
SELECT STATUS FROM `table_1` where SLNO = 1 group by status
If you get only one record with value "Closed" then execute the next query
UPDATE `table_2` SET Ref_Status = 'Closed' WHERE SLNO = 1;
Update my_table set Status='Closed' where SlNo = 1
Find the count of all rows and check it with the count of Closed values.
Query
select t.`SlNo`,
case when t.`RowNo_Count` = t.`closed_count` then 1 else 0 end as `new_col`
from(
select `SlNo`,
count(`RowNo`) as `RowNo_Count`,
sum(case `Status` when 'Closed' then 1 else 0 end) as `closed_count`
from `your_table_name`
group by `SlNo`
)t;

Sql query to show count(*) of groups while keeping all rows of the group

I have a table similar the following
id user_id father_id
1 1 1
2 2 1
3 3 2
4 4 2
5 5 2
6 6 3
7 7 4
I search for a sql query (prefer Fluent or Eloquent for Laravel 4) to give me the following result:
id user_id father_id family_members
3 3 2 3
4 4 2 3
5 5 2 3
1 1 1 2
2 2 1 2
6 6 3 1
7 7 4 1
As it can be observed family_members is the count of users who have the same father_id
select id, user_id, father_id, count(*) as family_members from users group by father_id
The query above, just keeps the top row of each group, but I want to keep all the other records and not only the first one; then sorting them first according to the family_members and then according to father_id
How can I achieve it?
I donĀ“t know Fluent, nor Eloquent, nor Laravel 4, but the sql query would be like this.
SELECT yourTable.*, auxTable.family_members
FROM yourTable
LEFT JOIN
(
SELECT father_id, COUNT(id) as family_members
FROM yourTable
GROUP BY father_id
)auxTable ON yourTable.father_id = auxTable.father_id
ORDER BY family_members DESC, yourTable.father_id ASC
I solved the problem by the following Fluent query based on the answer from segio0983
$users = DB::table('users')
->leftjoin(DB::raw('(SELECT father_id, COUNT(id) as family_members
FROM users
GROUP BY father_id) auxTable '),function($join)
{
$join->on('users.father_id', '=', 'auxTable.father_id');
})
->orderBy('auxTable.family_members','desc')
->orderBy('users.father_id','asc')
->select('users.id','users.father_id','auxTable.family_members');

MySql Distinct with multiple fields

I have 4 columns a, b c, d in my table (MySQL database) . I want to select the distinct values of ALL of these 4 columns in my table . More deeply my table is given bellow..
a b c d
--------------------------
1 3 3 4
1 2 3 0
1 1 3 4
1 2 3 4
1 2 3 4
1 2 3 4
1 2 3 4
In the above table (1,2,3,4) value are repeating 4 times(look the last 4 rows of my table). I want only the distinct one , ie i want to get the bellow table after mysql query..
a b c d
---------------
1 3 3 4
1 2 3 0
1 1 3 4
1 2 3 4
I think you guys got some idea . Im not familier with MySql .
select distinct a,b,c,d from your_table
SELECT DISTINCT column_name,column_name FROM table_name;
I mean
select distinct a,b,c,d from table_name;
Here is the link of w3schools
use :
SELECT DISTINCT * FROM yourtable
try this:
SELECT DISTINCT a FROM my_table
UNION
SELECT DISTINCT b FROM my_table
UNION
SELECT DISTINCT c FROM my_table
UNION
SELECT DISTINCT d FROM my_table
update 1:
SELECT a,b,c,d
FROM my_table
GROUP BY a,b,c,d;
http://sqlfiddle.com/#!2/c49ad/11

get SUM of another row of GROUP BY'd rows

I have this table:
This selection is is duplicated many times for different var_lines (which pretty much work as one row of data, or respondent for a survey) and set_codes (different survey codes).
With this query:
SELECT
*, COUNT(*) AS total
FROM
`data`
WHERE
`var_name` = 'GND.NEWS.INT'
AND(
`set_code` = 'BAN11A-GND'
OR `set_code` = 'BAN09A-GND'
OR `set_code` = 'ALG11A-GND'
)
AND `country_id` = '5'
GROUP BY
`data_content`,
`set_code`
ORDER BY
`set_code`,
`data_content`
The query basically counts the number of answers for a specific question. Then groups them survey (set_code).
What I need is for each of the grouped data_content answers for GND.NEWS.INT to also show the SUM of all the corresponding GND_WT with the same var_line.
For example if I had this:
data_id data_content var_name var_line
1 2 GND.NEW.INT 1
2 1.4 GND_WT 1
3 2 GND.NEW.INT 2
4 1.6 GND_WT 2
5 3 GND.NEW.INT 3
6 0.6 GND_WT 3
I would get something like this:
data_id data_content var_name var_line total weight
1 2 GND.NEW.INT 1 2 3
5 3 GND.NEW.INT 3 1 0.6
Thanks for any help.
Your requirements are not exactly clear, but I think the following gives you what you want:
select d1.data_id,
d1.data_content,
d1.var_name,
d1.var_line,
t.total,
w.weight
from data d1
inner join
(
select data_content,
count(data_content) Total
from data
group by data_content
) t
on d1.data_content = t.data_content
inner join
(
select var_line,
sum(case when var_name = 'GND_WT' then data_content end) weight
from data
group by var_line
) w
on d1.var_line = w.var_line
where d1.var_name = 'GND.NEW.INT'
See SQL Fiddle with Demo
This Query can be suitable for your specific example:
select st.data_id,
st.data_content,
st.var_name,
st.var_line,
count(st.data_id) as total,
sum(st1.data_content) as weight
from data st
left join data st1 on st1.var_name = 'GND_WT' AND st1.var_line=st.var_line
where st.var_name='GND.NEW.INT'
group by st.data_content
Regards,
Luis.

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