I have 4 columns a, b c, d in my table (MySQL database) . I want to select the distinct values of ALL of these 4 columns in my table . More deeply my table is given bellow..
a b c d
--------------------------
1 3 3 4
1 2 3 0
1 1 3 4
1 2 3 4
1 2 3 4
1 2 3 4
1 2 3 4
In the above table (1,2,3,4) value are repeating 4 times(look the last 4 rows of my table). I want only the distinct one , ie i want to get the bellow table after mysql query..
a b c d
---------------
1 3 3 4
1 2 3 0
1 1 3 4
1 2 3 4
I think you guys got some idea . Im not familier with MySql .
select distinct a,b,c,d from your_table
SELECT DISTINCT column_name,column_name FROM table_name;
I mean
select distinct a,b,c,d from table_name;
Here is the link of w3schools
use :
SELECT DISTINCT * FROM yourtable
try this:
SELECT DISTINCT a FROM my_table
UNION
SELECT DISTINCT b FROM my_table
UNION
SELECT DISTINCT c FROM my_table
UNION
SELECT DISTINCT d FROM my_table
update 1:
SELECT a,b,c,d
FROM my_table
GROUP BY a,b,c,d;
http://sqlfiddle.com/#!2/c49ad/11
Related
I have a very complicated query which involves a subquery and this subquery usas an union as the table. I want to use a column from the first level (a field before the subquery) as part of the where clausule in the union. Like this:
SELECT
type,
registered_number - (
SELECT
MAX(last)
FROM (
SELECT
MAX(b) as last
FROM
x
WHERE
a = type
UNION ALL
SELECT
MAX(b) as last
FROM
y
WHERE
a = type
) as last_table
) as last
FROM `x`;
Sample data
Table X
a
b
1
25
2
26
3
27
TABLE Y
a
b
1
25
2
24
3
31
TABLE s
id
type
registered_number
1
1
7
2
2
8
3
3
9
EXPECTED RESULT
type
last
1
18
2
18
3
22
I suggest doing a union of the x and y tables first, then join s to an aggregate of the union subquery.
SELECT s.type, t.b AS last
FROM s
INNER JOIN
(
SELECT a, MAX(b) AS b
FROM
(
SELECT a, b FROM x
UNION ALL
SELECT a, b FROM y
) t
GROUP BY a
) t
ON t.a = s.type
ORDER BY s.type;
I have two table (table 1 and table 2) . I want to show all the rows from table1 by joining with table2 which have multiple rows with same table1 id (foreign key relation) and will sort the result by table2 priority column (order by desc).
Table1
Table2
Result will be
thanks in advance
Edit
Table1
id name
1 test1
2 test2
3 test5
4 test7
5 test9
6 test3
Table2
id table1_id event priority
1 2 abc 0
2 2 kbc 0
3 2 abc 2
4 2 kbc 1
5 4 fgg 2
6 4 dss 3
7 1 fgfg 2
8 5 fgfg 2
9 6 xcxc 1
10 6 fgfh 3
Result
id_table1 name event priority
4 test7 dss 3
6 test3 fgfh 3
2 test2 abc 2
1 test1 fgfg 2
5 test9 fgfg 2
3 test5 NULL NULL
In the question you mentioned you need to select the data where id from table1 is available more than once in the table2 which does not match with the result set you gave.
Considering the original requirement the following should do the trick
select
t2.table1_id as id_table1,
t1.name,
t2.priority,
t2.event
from table1 t1
join
(
select
p1.table1_id,
p1.event,
p2.priority
from table2 p1
join(
select
max(priority) as priority,
table1_id
from table2
group by table1_id having count(*) > 1
)p2
on p2.table1_id = p1.table1_id and p2.priority = p1.priority
)t2
on t1.id = t2.t1id
order by t2.priority desc
Here is a demo
The result will get the same event corresponding the max priority column
This will get the result set that you want. You mentioned that you only need the items table1 ids that reflects more than once but result query shows tableid1 "1" even though it is only present once:
SELECT DISTINCT t1.id,t1.name ,t2.event, t2.priority
FROM TABLE2 t2
right join
TABLE1 t1
on t1.id=t2.table1_id
order by t2.priority desc
Try this query:
SELECT t1.*,t2.priority FROM table1 t1
INNER JOIN table2 t2
ON t1.id=t2.id
ORDER BY t2.priority DESC
Primary key and foreign key should have the same name. The syntax should be
SELECT Table1.id_table1,Table1.name,Table2.event,Table.priority FROM
Table1 LEFT JOIN Table2 ON
Table1.id=Table2.id
ORDER BY Table2.priority DESC
Make the following changes in Table2:
Get rid of the first column or rename it
Rename second column(your foreign key) to "id".
I have a table similar the following
id user_id father_id
1 1 1
2 2 1
3 3 2
4 4 2
5 5 2
6 6 3
7 7 4
I search for a sql query (prefer Fluent or Eloquent for Laravel 4) to give me the following result:
id user_id father_id family_members
3 3 2 3
4 4 2 3
5 5 2 3
1 1 1 2
2 2 1 2
6 6 3 1
7 7 4 1
As it can be observed family_members is the count of users who have the same father_id
select id, user_id, father_id, count(*) as family_members from users group by father_id
The query above, just keeps the top row of each group, but I want to keep all the other records and not only the first one; then sorting them first according to the family_members and then according to father_id
How can I achieve it?
I don´t know Fluent, nor Eloquent, nor Laravel 4, but the sql query would be like this.
SELECT yourTable.*, auxTable.family_members
FROM yourTable
LEFT JOIN
(
SELECT father_id, COUNT(id) as family_members
FROM yourTable
GROUP BY father_id
)auxTable ON yourTable.father_id = auxTable.father_id
ORDER BY family_members DESC, yourTable.father_id ASC
I solved the problem by the following Fluent query based on the answer from segio0983
$users = DB::table('users')
->leftjoin(DB::raw('(SELECT father_id, COUNT(id) as family_members
FROM users
GROUP BY father_id) auxTable '),function($join)
{
$join->on('users.father_id', '=', 'auxTable.father_id');
})
->orderBy('auxTable.family_members','desc')
->orderBy('users.father_id','asc')
->select('users.id','users.father_id','auxTable.family_members');
I have two tables:
Table A: ID Cars Planes Num
1 3 5 2
2 8 44 1
3 7 23 6
4 6 2 7
Table B: ID Horses Dogs Cats Elefants Num
1 3 5 2 3 3
2 8 44 1 22 4
3 7 23 4 14 8
4 6 2 3 15 5
What I need to do: I need to get all results from both tables and sort them by the "Num" Column, where the "number" actually is unique for each result from both rows.
Is it even possible to "merge" those two tables and order them by "num" or should I just get each table separately ordered and do two loops checking always for the next num jumping between tables?
Thanks
you can merge them like that with UNION .
try this:
select num from(
select num from table1
union all
select num from table2
)t
order by num asc
DEMO HERE
EDIT:
select id ,Cars,Planes, Horses,Dogs,Cats,Elefants,num from(
select id ,Cars,Planes,'No horses' Horses,'No dogs' Dogs,'No cats' Cats,'No elefants' Elefants,num from table1
union all
select id,'No cars' Cars,'No planes' Planes,Horses,dogs,Cats,Elefants, num from table2
)t
order by num asc;
DEmo with other columns
SELECT NUM FROM TABLEA
UNION ALL
SELECT NUM FROM TABLEB
ORDER BY 1
I have this table
conncections
id_user connectedto
1 4
2 4
3 1
1 5
i would like to do a SELECT that gives me back all the numbers that have a relation with the number 1 and the number 1 itself. Therefore 1 4 3 5 as result.
Something like
SELECT DISTINCT id_user as related
FROM connections
WHERE connectedto = 1
UNION
SELECT DISTINCT connectedto as related
FROM connections
WHERE id_user = 1
With UNION duplicate are removed