cant pass more than a select-option - php

Question

here is a piece of a script which drive me crazy
if(isset($_POST['submit'])) {
$cnt = $_POST['cnt'];
for ($i ='0'; $i <= $cnt; $i++){
$group[$i] = $_POST['group'];
$databox[$i] = $_POST['newdata'][$i];
$cve[$i] = $_POST['cve'][$i];
$play[$i] = $_POST['play'][$i];
$cause[$i] = $_POST['cause'][$i];
}
}
=============ENTRY POINT=======================
<form method="POST" name="tt" action="#" >
<?php
for ($i = 0; $i <= $cnt; $i++){
[...]
echo "<input type='text' name ='newdata[$i]' value ='$newdata' />
<input type='text' name ='cause[$i]' value ='$newcause' />
<input type='text' name ='play[$i]' value ='$newplay' />
<input type='text' name ='cve[$i]' value = '$newcve' />
<select name='group'>
<option></option>
<option value = 'afb'>1</option>
<option value = 'alc'>2</option>
<option value = 'abd'>3</option>
[...]
<option value = 'ven'>4</option>
<option value = 'nct'>5</option>
</select>";
}
echo "<input type='hidden' name ='cnt' value= '$cnt' />
<input type='submit' name='submit' value='Go' />";
?>
</form>
My problem is that whichever option I select only the last chosen is displayed. I tried with
$group[$i] = $_POST['group'][$i];
but I get the split (a single letter) of "value"
I mean, suppose you select option 4 I get
$group[0] = v
$group[1] = e
$group[2] = n
Hope you understand what I mean

Answer 1

You're submitting your select element as a single element, not an array. Your PHP script is using the index of that single (string) element to get individual characters.
try
<select name='group[]'>