PHP, HTML multiple chexbox valuesc - php

I have got the php, html code.
And I want to post the multiple checkbox values, but this does not work dunno why, I can print count or array, it prints(0), does not matter
the array values is always empty
<form action = 'main.php?w=creatNewTemplate2' method = 'post'>
<input type = 'text' name = 'templateName' maxlength = '30'/><br />
<input type= 'checkbox' name= 'exercises[]' value='A' />A<br />
<input type= 'checkbox' name= 'exercises[]' value='B' />B<br />
<input type = 'submit' value = 'Sukurti'/>
</form>
if($w == "creatNewTemplate2")
{
$d = $_POST['exercises'];
$ddd = count($d);
print_r($_POST);
}

I think this could work for you:
if($w == "creatNewTemplate2")
{
$d = $_POST['exercises'];
$ddd = count($d);
for ($x = 0; $x < $ddd; $x++) {
echo $_POST['exercises'][$x].'<br>';
}
}
If you use same name you need to loop them

This should be work
Or you can change the two checkbox to select multiple
<form action="main.php?w=creatNewTemplate2" method="post">
<input type="text" name="templateName" maxlength="30"/><br/>
<select multiple name="exercices[]">
<option>A</option>
<option>B</option>
</select>
<input type="submit" value="Sukurti"/>
</form>
<?php
if($_GET["w"] == "creatNewTemplate2")
{
foreach ($_POST["exercises"] as $ex) {
echo $ex . '<br>';
}
}

Related

how to use the single input received multiple times in php

for example, I receive two inputs value1 and value2 and I want this input for different functions. Like addition, subtraction and multiplication.
my code
<?php
$x = $_POST['fnum'];
$y = $_POST['snum'];
if (isset($_POST['add'])) {
$sum = $x + $y;
echo "Result:<input type='text' value='$sum'/>";
}
if (isset($_POST['sub'])) {
$sub = $x - $y;
echo "Result:<input type='text' value='$sub'/>";
}
if (isset($_POST['mul'])) {
$mul = $x * $y;
echo "Result:<input type='text' value='$mul'/>";
}
<body>
<form method="post">
Enter first number <input type="text" name="fnum" />
<hr />
Enter second number <input type="text" name="snum" />
<hr />
<input type="submit" name="add" value="ADD" />
<input type="submit" name="sub" value="Subtract" />
<input type="submit" name="mul" value="Multiply" />
</form>
</body>
In this it is asking me to feed input for each operation separately
Good, Just use the posted value in your form input like -
Enter first number <input type="text" name="fnum" value="<?php echo #$_POST['fnum'];?>"/><hr/>
Enter second number <input type="text" name="snum" value="<?php echo #$_POST['snum'];?>"/><hr/>
So that user don't need to put the same value again and when press the other buttons the form will automatically submit with the previous values.
Note: Remember, you need to check all the posted value is set or not and use proper conditions of POST method. Have a look at the given example of your problem as solution, I give it here to give you a proper guide.
Example:
<?php
$x = 0;
$y = 0;
if(isset($_POST['submit'])) {
$x = $_POST['fnum'];
$y = $_POST['snum'];
$operator = "";
if($_POST['submit'] == 'ADD') {
$operator = "+";
} elseif($_POST['submit'] == 'Subtract') {
$operator = "-";
} elseif($_POST['submit'] == 'Multiply') {
$operator = "*";
}
$result = $x . $operator . $y;
}?>
Your form will be-
<form method="post">
Enter first number <input type="text" name="fnum" value="<?php echo $x;?>"/><hr/>
Enter second number <input type="text" name="snum" value="<?php echo $y;?>"/><hr/>
<input type="submit" name="submit" value="ADD"/>
<input type="submit" name="submit" value="Subtract"/>
<input type="submit" name="submit" value="Multiply"/>
</form>
Result:
<input type='text' value='<?php echo (isset($result) ? $result : "-";)?>'/>

How to save input fields of accompanying checkboxes?

I have a list a checkboxes with accompanying input text fields. If the user checks a box, the accompanying text field will be add to an array.
I am new to PHP and was wondering if anyone can help me in the right direction.
Should I use a for loop, foreach, while, unique "name" for each input, or something else?
Below is what I have so far.
<?php
if(isset($_POST['submit'])){
$array = array();
while(isset($_POST['check'])){
if(!isset($_POST[$some_text]) || empty($_POST[$some_text])){
echo "Please include your text for each checkbox you selected.";
exit();
}
$array[] = $_POST['some_text];
}
}
?>
<form>
<input type="checkbox" name="check"><input type="text name="some_text">
<input type="checkbox" name="check"><input type="text name="some_text">
<input type="checkbox" name="check"><input type="text name="some_text">
<!-- I might have around 100 of these -->
<!-- submit button here -->
</form>
You first need a way to associate your checkboxes with their corresponding text fields, and a way to tell them apart. For example:
<form>
<input type="checkbox" name="check[]" value="1"><input type="text name="text1">
<input type="checkbox" name="check[]" value="2"><input type="text name="text2">
<input type="checkbox" name="check[]" value="3"><input type="text name="text3">
</form>
Now you can loop through it as follows:
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
if (isset($_POST['check']) && is_array($_POST['check']) && !empty($_POST['check'])) {
$array = array();
foreach ($_POST['check'] as $value) {
$text_field = 'text' . $value;
if (!isset($_POST[$text_field]) || trim($_POST[$text_field]) == '') {
echo "Please include your text for each checkbox you selected.";
exit;
}
$array[] = $_POST[$text_field];
}
}
}
Try this:
$select = array();
foreach($_POST['check'] as $key => $selected){
$select[$key] = $selected;
}
Please try this:
<?php
if(isset($_POST['submit'])){
for($i=0; $i<100; $i++)
{
if($_POST['check_'.$i])
{
$array[] = $_POST['input_'.$i];
}
}
}
?>
#################### HTML
<form method="post" action="">
<?php for($i=0; $i<100; $i++) { ?>
<input type="checkbox" name="check_<?php echo $i ?>"><input type="text" name="input_<?php echo $i ?>">
<?php } ?>
<input type="submit" name="submit">
</form>

cant pass more than a select-option

here is a piece of a script which drive me crazy
if(isset($_POST['submit'])) {
$cnt = $_POST['cnt'];
for ($i ='0'; $i <= $cnt; $i++){
$group[$i] = $_POST['group'];
$databox[$i] = $_POST['newdata'][$i];
$cve[$i] = $_POST['cve'][$i];
$play[$i] = $_POST['play'][$i];
$cause[$i] = $_POST['cause'][$i];
}
}
=============ENTRY POINT=======================
<form method="POST" name="tt" action="#" >
<?php
for ($i = 0; $i <= $cnt; $i++){
[...]
echo "<input type='text' name ='newdata[$i]' value ='$newdata' />
<input type='text' name ='cause[$i]' value ='$newcause' />
<input type='text' name ='play[$i]' value ='$newplay' />
<input type='text' name ='cve[$i]' value = '$newcve' />
<select name='group'>
<option></option>
<option value = 'afb'>1</option>
<option value = 'alc'>2</option>
<option value = 'abd'>3</option>
[...]
<option value = 'ven'>4</option>
<option value = 'nct'>5</option>
</select>";
}
echo "<input type='hidden' name ='cnt' value= '$cnt' />
<input type='submit' name='submit' value='Go' />";
?>
</form>
My problem is that whichever option I select only the last chosen is displayed. I tried with
$group[$i] = $_POST['group'][$i];
but I get the split (a single letter) of "value"
I mean, suppose you select option 4 I get
$group[0] = v
$group[1] = e
$group[2] = n
Hope you understand what I mean
You're submitting your select element as a single element, not an array. Your PHP script is using the index of that single (string) element to get individual characters.
try
<select name='group[]'>

Undefined Offset when looking through an array to display values

Hey I am new to PHP and I am trying to take values from the user that were put into a form for a game. Every time the user enters text and clicks submit it should add it to the array. Every time it will show at the bottom of the page all the guesses currently in a ordered list until the user gets the right answer and wins.
<?php
$count =0;
$guesses = array();
if(isset($_POST['submit']))
{
$count = $_POST['count'];
for($r =0; $r < $count; $r++)
{
$guesses[$r] = $_POST['word'];
}
?>
<h3>Guess the word I'm thinking</h3>
<form action = "<?php echo $_SERVER['PHP_SELF'] ?>" method = "post">
<input type = "text" name = "word" value = "<?php echo $tell; ?>"/>
<input type = "hidden" name = "count" value = "<?php $count +=1;?>"/>
<input type = "submit" name ="submit" value = "Make a Guess"/>
</form>
<ol>
<?php
for($t=0; $t < $count; $t++)
{
?>
<li><?php echo $guesses[$t];?></li>
<?php
}
?>
</ol>
I keep getting a Undefined offset: 0. I did some reading and I know it has something to do with either me filling the array wrong or calling the index wrong. Hope you can help show me how to resolve this problem. Thank you.
The output would be similar to:
Your guesses:
1. blue
2. red
etc
Look if you don't want to use Session variable then you have to set the values enter by the user in the hidden input tag. Below is the code you might required to get your specific result:
<?php
$guesses="";
if(isset($_POST['submit']))
{
$guesses= $_POST['count']." ".$_POST['word'];
}
?>
<h3>Guess the word I'm thinking</h3>
<form action = "<?php echo $_SERVER['PHP_SELF'] ?>" method = "post">
<input type = "text" name = "word" value = "Word"/>
<input type = "hidden" name = "count" value = "<?php echo $guesses;?>"/>
<input type = "submit" name ="submit" value = "Make a Guess"/>
</form>
<ol>
<?php
$count = explode(" ", $guesses);
foreach($count as $val)
{
if($val!= ''){
?>
<li><?php echo $val;?></li>
<?php
}
}
?>
</ol>
EDITED:
Problem was that you foremost did not echo the $count in your form, you simply incremented it. So the post variable would be empty. Also, increment it after you add to the array instead of in the post.
<?php
if( !isset( $count ) ){
$count =0;
}
$guesses = array();
if(isset($_POST['submit'])) {
$guesses[$count] = $_POST['word'];
$count++;
}
?>
<h3>Guess the word I'm thinking</h3>
<form action = "<?php echo $_SERVER['PHP_SELF'] ?>" method = "post">
<input type = "text" name = "word" value = "<?php echo $tell; ?>"/>
<input type = "submit" name ="submit" value = "Make a Guess"/>
</form>
<ol>
<?php
for($t=0; $t < count( $guesses); $t++)
{
?>
<li><?php echo $guesses[$t];?></li>
<?php
}
?>
</ol>
Try this code:
<?php
$guesses = array();
if(isset($_POST['submit']))
{
if($_POST['guesses'] != '')
$guesses = explode('|', $_POST['guesses']);
if(trim($_POST['word']))
$guesses[] = trim($_POST['word']);
}
?>
<h3>Guess the word I'm thinking</h3>
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post">
<input type="text" name= "word" value="" />
<input type="hidden" name="guesses" value="<?php echo count($guesses)? implode('|',$guesses):''; ?>" />
<input type="submit" name="submit" value="Make a Guess" />
</form>
<ol>
<?php foreach($guesses as $guess) { ?>
<li><?php echo $guess;?></li>
<?php } ?>
</ol>

form $_POST error, dynamic fields

I have an error that I can't figure out...
Om my webpage there is a form that the user has the ability to add some new input fields to. If the user is submitting the form, then the optional fields is empty when the php-file is handing them, why?
HTML:
<form method="post" action="newRequest.php">
<input type="text" name="title" />
<input type="hidden" name="fname" value="0" />
<input type="checkbox" name="fname" value="1"/>
<input type="hidden" name="ename" value="0" />
<input type="checkbox" name="ename" value="1" />
<input type="hidden" name="seat" value="0" />
<input type="checkbox" name="seat" value="1" />
<input type="hidden" name="fields" value="0" />
<input type="text" id="fields" name="fields" />
<input type="submit" />
</form>
PHP:
if (strlen($_POST[title]) > 2) {
$toDb[title] = $_POST[title];
} else {
error('title');
}
$toDb[fname] = $_POST[fname];
$toDb[ename] = $_POST[ename];
$toDb[seat] = $_POST[seat];
if ($_POST[fields] > 0) {
$i = 0;
while ($i < $_POST[fields]) {
$toDb[optional][$i] = $_POST[optional-$i];
$i++;
}
$toDb[optional] = serialize($toDb[optional]);
} else {
$toDb[optional] = 0;
}
newEvent($toDb,$dbh);
JQuery that is adding dynamical fields:
$(document).ready(function() {
$('#fields').focusout(function(){
var fields = $('#fields').val();
var i = 0;
while(i < fields) {
$('#fields').after("Valfritt fält "+(i+1)+":<input type='text' name='optional"+i+"' />");
i++;
}
})
})
You should quote array indexes. It should be
$toDb['optional'][$i] = $_POST['optional'.$i];
You are missing commas in $_POST
$toDb['fname'] = $_POST['fname'];
$toDb['ename'] = $_POST['ename'];
$toDb['seat'] = $_POST['seat'];
Here is your modified code
if (strlen($_POST['title']) > 2) {
$toDb['title'] = $_POST['title'];
} else {
error('title');
}
$toDb['fname'] = $_POST['fname'];
$toDb['ename'] = $_POST['ename'];
$toDb['seat'] = $_POST['seat'];
if (count($_POST) > 0) {
$i = 0;
while ($i < count($_POST)) {
$toDb['optional'][$i] = $_POST['optional-'.$i];
$i++;
}
$toDb['optional'] = serialize($toDb['optional']);
} else {
$toDb['optional'] = 0;
}
newEvent($toDb,$dbh);
Also use count() to check if $_POST has values > 0.
I faced the same problem and I solved it using Javascript, like this :
add a new text field every time a button is pressed

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