Sintax error in PHP invoking an array inside a column [duplicate] - php

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 7 years ago.
Can anyone tell me where is the syntax error of the following code:
echo "<td bgcolor=.$cores[i].></td>";
$cores is an array of colors codes:
$cores = array("#FF0000","#FFBF00","#FFFF00","#04B404","#58FAF4","#0101DF","#8A0886");


try this:
echo "<td bgcolor={$cores[$i]}></td>";

Related

undefined index while update in php issue [PLEASE HELP] [duplicate]

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 4 years ago.
i had a problem in this line, because the error message tell me theres an undefined index:
$strSQL = " UPDATE place SET
rating_value = '".$_POST["rating_value"]."'
WHERE place_id = '".$_POST["place_id"]."'
";
pls help me if you have a solution. thanks

Do you check your variables before do the request like :
if( !empty($_POST["rating_value"]) && !empty($_POST["place_id"]) )
{
// your request
} else {
echo("error");
}

PHP URI values showing up as undefined [duplicate]

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
What I want to do is echo the value of $test on my page, through the uri. I know I'm doing something wrong, but I can't figure out what.
Code:
<?php echo $test?>
URL:
localhost/testMap/test.php?test=hallo

You can get the value of url with a get, and store it in the variable $test and then echo that out.
$test = $_GET['test'];

Undefined Index in PHP Code [duplicate]

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"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
I am getting an undefined index error on this line of code:
switch ($_REQUEST["___p"])
I think I would need to declare the variable. What would I change the above line to?

Either make sure exists beforehand with isset() or just ignore it:
switch (#$_REQUEST["___p"])

Notice: Undefined index: n variable integer [duplicate]

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 7 years ago.
Notice: Undefined index: n in C:\Users\Marseille\Desktop\Activation
W7\UwAmp\www\quezzer\question.php on line 5
this is a code tiped at question.php
$number = (int) $_GET['n'];
why i have this error! i have not understand!

Since this is a get variable you're using, from what I understand is that you maybe trying to run the script questions.php directly. Therefore no get variables are set, try
localhost/yourfolder/questions.php?n=5

Getting Undefined index error [duplicate]

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 8 years ago.
Im getting the following error: Notice:undefined index:done
please advise what is wrong
<?php
if($_Get['done']==1 $msg = "Account details saved";
?>

Check first if the key exists, then the comparison to 1.
if (isset($_GET['done']) && $_GET['done'] == 1) {
$msg = '...';
}

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