This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
What I want to do is echo the value of $test on my page, through the uri. I know I'm doing something wrong, but I can't figure out what.
Code:
<?php echo $test?>
URL:
localhost/testMap/test.php?test=hallo
You can get the value of url with a get, and store it in the variable $test and then echo that out.
$test = $_GET['test'];
Related
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
PHP check value against multiple values with OR-operator
(3 answers)
Closed 4 years ago.
Hi,
I have this code:
if($_GET['s']=="page1" || $_GET['s']=="page2" || $_GET['s']=="page3") {
dosomething();
}
and I get this error: : Undefined index: s in
Which I can dismiss only by adding this line:
$_GET['s']="";
but then this wont execute the code correctly since $_GET['s'] is not supposed to have any initial value. How do I fix this other than disabling the notices and errors?
Thank you.
You can check your $_GET['s']
if(isset($_GET['s'])) {
// your code goes here...
}
isset() is used to check if the index exists.
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
I am getting an undefined index error on this line of code:
switch ($_REQUEST["___p"])
I think I would need to declare the variable. What would I change the above line to?
Either make sure exists beforehand with isset() or just ignore it:
switch (#$_REQUEST["___p"])
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
I am aware that I can use sessions and GET/ POST method but I would like to achieve this using cookies. My code on page1.php is :
$_COOKIE['varname'] = $id;
and on page2.php is:
$id = $_COOKIE['varname'];
I get the following notice on my browser: Undefined index $id
What is the problem with my code?
Try using setcookie('varname', $id) then
if (isset($_COOKIE['varname']){ echo $_COOKIE['varname']; }
To set a cookie you need to use setcookie(). And it has to be done prior to any output.
setcookie("mycookie", "myvalue" , $validtime); // validtime is a integer.
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 7 years ago.
Notice: Undefined index: n in C:\Users\Marseille\Desktop\Activation
W7\UwAmp\www\quezzer\question.php on line 5
this is a code tiped at question.php
$number = (int) $_GET['n'];
why i have this error! i have not understand!
Since this is a get variable you're using, from what I understand is that you maybe trying to run the script questions.php directly. Therefore no get variables are set, try
localhost/yourfolder/questions.php?n=5
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 7 years ago.
Can anyone tell me where is the syntax error of the following code:
echo "<td bgcolor=.$cores[i].></td>";
$cores is an array of colors codes:
$cores = array("#FF0000","#FFBF00","#FFFF00","#04B404","#58FAF4","#0101DF","#8A0886");
try this:
echo "<td bgcolor={$cores[$i]}></td>";