Issues with prepared statements / bindValue - php

Question

So I have the following code, mostly adapted from examples from php.net's SQLite3 prepare statement page.
$stmt = $db->prepare("INSERT INTO users ( accesstoken, authed, ckey, staff) VALUES (':password', 'false', ':ckey' ,'true');");
$stmt->bindValue(':ckey',$_POST["ckey"]);
$hashedpw = password_hash($veri_password, PASSWORD_DEFAULT);
$stmt->bindValue(':password',$hashedpw);
$result = $stmt->execute();
I figured it would work, however when I review the database manually I see this:
:ckey, :password, false, false as the row that was inserted.
I can't seem to fix it either, I tried removing the quotes around it and threw an error instead. I swapped the quote types and either got an undefined column or some other error.
Here is a snip of the code right before that:
$stmt = $db->prepare("select * from `users` WHERE ckey = :ckey");
$stmt->bindValue(":ckey",$_POST["ckey"]);
$result = $stmt->execute();
That works just fine however it is a select query rather than a insert and it only has one value to bind. I've looked at about least 10-15 related questions and still can't solve it, one suggested using ' instead of " but that didn't solve it another suggested using ? instead of :ckey and that left me with question marks inside of my database (how fitting) and I still have not been able to resolve it.

Answer 1

The issue is with the quotes change
$stmt = $db->prepare("INSERT INTO users ( accesstoken, authed, ckey, staff) VALUES (':password', 'false', ':ckey' ,'true');");
to
$stmt = $db->prepare("INSERT INTO `users` ( accesstoken, authed, ckey, staff) VALUES (:password, 0, :ckey ,1)");
Credit to Cfreak