I am trying to add an HTML "select dropdown list" for gender. However I want the default value from the database with php framework. Can I do that?
Pseudo code:
$default_gender = getDefaultGenderValueFromDB;
<select name="genderSelected">
<option value="m"<?php echo ($default_gender == 'm')? selected:'';?>>Male</option>
<option value="f"<?php echo ($default_gender== 'f')? selected:'';?>>Female</option>
</select>
Valid code snippet:
<?php $default_gender = 'm'; ?>
<select name="genderSelected">
<option value="m" <?php echo ($default_gender == 'm')? 'selected="selected"':'';?>>Male</option>
<option value="f" <?php echo ($default_gender == 'f')? 'selected="selected"':'';?>>Female</option>
</select>
Try this:
<td>Sex: </td> <td> <select name="Sex">
<?php
$result = mysqli_query($connection, "Select sex from personaltab where empno='$emplno'");
$rows = mysqli_fetch_assoc($result);
$gender =$rows['sex'];
echo "<option if($gender == 'FEMALE') { selected='selected'} value='FEMALE'>FEMALE</option>";
echo "<option value='MALE' if($gender == 'MALE') { selected='selected' }>MALE</option>";
?>
</select> </td></tr>
dont use if else..
Related
Here is the code that i am using for drop down to select.
<select name="formreg" value="">
<option value="Registered" <?php if($f_reg == 'Registered') { ?> selected <?php echo $f_reg; } ?> >Registered</option>
<option value="NonReg" <?php if($f_reg == 'NonReg') { ?> selected <?php echo $f_reg; } ?> >NonReg</option>
</select>
<select name="regform">
<option value="Registered" <?php if (isset($register) && $register=='Registered') {?> selected='selected' <?php echo $register; }?>>Registered</option>
<option value="NonReg" <?php if (isset($nonreg) && $nonreg == 'NonReg') {?> selected='selected' <?php echo $nonreg;} ?>>NonReg</option>
</select>
At the top of script:
$f_reg = $_POST["f_reg"]; // or $f_reg = $_GET["f_reg"] if you pass parameters as the url part
then your < select > tag:
<select name="formreg">
<option value="Registered" <?php if ($f_reg == "Registered") print "selected"?>>Registered</option>
<option value="NonReg" <?php if ($f_reg == "NonReg") print "selected"?>>NonReg</option>
</select>
I need to get selected value from db into select box. please, tell me how to do it. Here is the code.
Note: 'options' value depends on the category.
<?php
$sql = "select * from mine where username = '$user' ";
$res = mysql_query($sql);
while($list = mysql_fetch_assoc($res)){
$category = $list['category'];
$username = $list['username'];
$options = $list['options'];
?>
<input type="text" name="category" value="<?php echo '$category' ?>" readonly="readonly" />
<select name="course">
<option value="0">Please Select Option</option>
<option value="PHP">PHP</option>
<option value="ASP">ASP</option>
</select>
<?php
}
?>
I think you are looking for below code changes:
<select name="course">
<option value="0">Please Select Option</option>
<option value="PHP" <?php if($options=="PHP") echo 'selected="selected"'; ?> >PHP</option>
<option value="ASP" <?php if($options=="ASP") echo 'selected="selected"'; ?> >ASP</option>
</select>
The easiest way I can think of is the following:
<?php
$selection = array('PHP', 'ASP');
echo '<select>
<option value="0">Please Select Option</option>';
foreach ($selection as $selection) {
$selected = ($options == $selection) ? "selected" : "";
echo '<option '.$selected.' value="'.$selection.'">'.$selection.'</option>';
}
echo '</select>';
The code basically places all of your options in an array which are called upon in the foreach loop. The loop checks to see if your $options variable matches the current selection it's on, if it's a match then $selected will = selected, if not then it is set as blank. Finally the option tag is returned containing the selection from the array and if that particular selection is equal to your $options variable, it's set as the selected option.
for example ..and please use mysqli() next time because mysql() is deprecated.
<?php
$select="select * from tbl_assign where id='".$_GET['uid']."'";
$q=mysql_query($select) or die($select);
$row=mysql_fetch_array($q);
?>
<select name="sclient" id="sclient" class="reginput"/>
<option value="">Select Client</option>
<?php $s="select * from tbl_new_user where type='client'";
$q=mysql_query($s) or die($s);
while($rw=mysql_fetch_array($q))
{ ?>
<option value="<?php echo $rw['login_name']; ?>"<?php if($row['clientname']==$rw['login_name']) echo 'selected="selected"'; ?>><?php echo $rw['login_name']; ?></option>
<?php } ?>
</select>
Just Add an extra hidden option and print selected value from database
<option value="<?php echo $options;?>" hidden><?php echo $options;?></option>
<option value="PHP">PHP</option>
<option value="ASP">ASP</option>
Select value from drop down.
<select class="form-control" name="category" id="sel1">
<?php foreach($data as $key =>$value) { ?>
<option value="<?php echo $data[$key]->name; ?>"<?php if($id_name[0]->p_name==$data[$key]->name) echo 'selected="selected"'; ?>><?php echo $data[$key]->name; ?></option>
<?php } ?>
</select>
THE EASIEST SOLUTION
It will add an extra in your options but your problem will be solved.
<?php
if ($editing == Yes) {
echo "<option value=\".$MyValue.\" SELECTED>".$MyValue."</option>";
}
?>
$option = $result['semester'];
<option >Select</option>
<option value="1st" <?php if($option == "1st") echo 'selected = "selected"'; ?>>1st</option>
<option value="2nd" <?php if($option == "2nd") echo 'selected = "selected"'; ?>>2nd</option>
<option value="3rd" <?php if($option == "3rd") echo 'selected = "selected"'; ?>>3rd</option>
<option value="4th" <?php if($option == "4th") echo 'selected = "selected"'; ?>>4th</option>
<option value="5th" <?php if($option == "5th") echo 'selected = "selected"'; ?>>5th</option>
<option value="6th" <?php if($option == "6th") echo 'selected = "selected"'; ?>>6th</option>
<option value="7th" <?php if($option == "7th") echo 'selected = "selected"'; ?>>7th</option>
<option value="8th" <?php if($option == "8th") echo 'selected = "selected"'; ?>>8th</option>
</select>
BEST code and simple
<select id="example-getting-started" multiple="multiple" name="category">
<?php
$query = "select * from mine";
$results = mysql_query($query);
while ($rows = mysql_fetch_assoc(#$results)){
?>
<option value="<?php echo $rows['category'];?>"><?php echo $rows['category'];?></option>
<?php
}
?>
</select>
You can also do like this ....
<?php $countryname = $all_meta_for_user['country']; ?>
<select id="mycountry" name="country" class="user">
<?php $myrows = $wpdb->get_results( "SELECT * FROM wp_countries order by country_name" );
foreach($myrows as $rows){
if( $countryname == $rows->id ){
echo "<option selected = 'selected' value='".$rows->id."'>".$rows->country_name."</option>";
} else{
echo "<option value='".$rows->id."'>".$rows->country_name."</option>";
}
}
?>
</select>
Answer is simple.
when u pass value from dropdown.
Just use as if else.
for eg:
foreach($result as $row) {
$GLOBALS['output'] .='<option value="'.$row["dropdownid"].'"'.
($GLOBALS['passselectedvalueid']==$row["dropwdownid"] ? ' Selected' : '').'
>'.$row['valueetc'].'</option>';
}
<?php
$sql = "select * from mine where username = '$user' ";
$res = mysql_query($sql);
while($list = mysql_fetch_assoc($res)){
$category = $list['category'];
$username = $list['username'];
$options = $list['options'];
?>
<input type="text" name="category" value="<?php echo '$category' ?>" readonly="readonly" />
<select name="course">
<option value="0">Please Select Option</option>
<option value="PHP" <?php echo $options == 'PHP' ? 'selected' : ''; ?> >PHP</option>
<option value="ASP" <?php echo $options == 'ASP' ? 'selected' : ''; ?> >ASP</option>
</select>
<?php
}
?>
USING PDO
<?php
$username = "root";
$password = "";
$db = "db_name";
$dns = "mysql:host=localhost;dbname=$db;charset=utf8mb4";
$conn = new PDO($dns,$username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "select * from mine where username = ? ";
$stmt1 = $conn->prepare($sql);
$stmt1->execute(array($_POST['user']));
$all = $stmt1->fetchAll(); ?>
<div class="controls">
<select data-rel="chosen" name="degree_id" id="selectError">
<?php
foreach($all as $nt) {
echo "<option value =$nt[id]>$nt[name]</option>";
}
?>
</select>
</div>
I'm using eval() PHP function like this:
My PHP code:
$selOps1 = $selOps2 = $selOps3 = '';
eval('$selOps'. $dbRow["DBitem"] . ' = "selected";');
Then in my select box I use it like this:
<select>
<option <?=$selOps1?> value="1">big</option>
<option <?=$selOps2?> value="2">Middle</option>
<option <?=$selOps3?> value="3">Small</option>
</select>
Put value from db into a variable and check like following code example
<select class="form-control" name="currency_selling" required >
<option value="">Select Currency</option>
<option value="pkr" <?=$selected_currency == 'pkr' ? ' selected="selected"' : '';?> >PKR</option>
<option value="dollar" <?=$selected_currency == 'dollar' ? ' selected="selected"' : '';?> >USD</option>
<option value="pounds" <?=$selected_currency == 'pounds' ? ' selected="selected"' : '';?> >POUNDS</option>
<option value="dirham" <?=$selected_currency == 'dirham' ? ' selected="selected"' : '';?> >DRHM</option>
</select>
This may help you.
?php
$sql = "select * from mine where username = '$user' ";
$res = mysql_query($sql);
while($list = mysql_fetch_assoc($res))
{
$category = $list['category'];
$username = $list['username'];
$options = $list['options'];
?>
<input type="text" name="category" value="<?php echo '$category' ?>" readonly="readonly" />
<select name="course">
<option value="0">Please Select Option</option>
// Assuming $list['options'] is a coma seperated options string
$arr=explode(",",$list['options']);
<?php foreach ($arr as $value) { ?>
<option value="<?php echo $value; ?>"><?php echo $value; ?></option>
<?php } >
</select>
<?php
}
?>
please, i'm somewhat new with php bear with me.
I have a selectbox...
<select name="criteria">
<option value="1">Student ID</option>
<option value="2">Firstname </option>
<option value="3">Lastname</option>
<option value="6">All</option>
</select>
<input name="searchvalue" type="text">
<input name="search" type="submit" value="Search">
When i search with a particular option, after the post request, the selected option usually defaults to Student ID. But i want it to still remain the option i searched with. Any suggestion would be appreciated.
To be honest I'd adjust your select code just a little bit to allow for a bit more dynamic editing..
<?php
$options = array('1'=>'Student ID', '2'=>'Firstname', '3'=>'Lastname', '6'=>'All');
?>
<select name="criteria">
<?php
foreach($options as $key=>$value){
$addtItem = '';
if(isset($_POST['criteria']) && $_POST['criteria']==$key){
$addtItem = 'selected="selected"';
}
echo('<option '.addtItem.' value="'.key.'">'.$value.'</option>');
}
?>
</select>
This way you can quickly add more values without a ton of repeat code..
<select name="criteria">
<option value="1" <?php if ($_POST["criteria"] == 1) echo "SELECTED"; ?>>Student ID</option>
<option value="2" <?php if ($_POST["criteria"] == 2) echo "SELECTED"; ?>>Firstname </option>
<option value="3" <?php if ($_POST["criteria"] == 3) echo "SELECTED"; ?>>Lastname</option>
<option value="6" <?php if ($_POST["criteria"] == 6) echo "SELECTED"; ?>>All</option>
</select>
Really ugly, but that works.
You need to check the $_POST array and select the corresponding select item
<?php
$criteria = isset($_POST['criteria']) ? $_POST['criteria']: 0;
?>
<select name="criteria">
<option value="1" <?php echo ($criteria == '1') ? 'selected="selected"': ''; ?>>Student ID</option>
<option value="2" <?php echo ($criteria == '2') ? 'selected="selected"': ''; ?>>Firstname </option>
<option value="3" <?php echo ($criteria == '3') ? 'selected="selected"': ''; ?>>Lastname</option>
<option value="6" <?php echo ($criteria == '6') ? 'selected="selected"': ''; ?>>All</option>
</select>
I have this form:
<form method='POST' action='update_ads.php'>
<select size='1' name='type'>
<OPTION value=''></OPTION>
<OPTION value='1'>Open</OPTION>
<OPTION value='0'>Closed</OPTION>
</select>
<input type='submit' value='Save'>
</form>
and this PHP file associated with it:
$id = $_POST['id'];
$type = addslashes($_POST['type']);
$query = mysql_query("UPDATE ads SET type='$type' where id=$id");
What can I add so that the option that the user choose before they clicked "submit" comes back when they re-open it? Thanks!
You could do it this way:
<?php
if (isset($_POST['id']) && ((int) $_POST['id'])) != 0) {
$id = $_POST['id'];
}
//connect to db
//get the responce of the query "SELECT `type` FROM `ads` WHERE `id` = $id"
//put it in a variable named $type
?>
<form method="POST" action="">
<select size='1' name='type'>
<option value="" <?=($type == '') ? 'selected="selected"' : ''?>></option>
<option value="1" <?=($type == 1) ? 'selected="selected"' : ''?>>Open</option>
<option value="0" <?=($type == 2) ? 'selected="selected"' : ''?>>Closed</option>
</select>
</form>
Edit: This is good ony if you have a select with not many options, otherwise you should use somethink like a foreach statement.
For many options you can use this:
<?php
$options = array('Open' => 1, 'Closed' => 0, 'Select an option' => ''); ?>
<form method="POST" action="">
<select size='1' name='type'>
<?php
foreach($options as $label => $option) {
if ($type == $option) {
$checked = 'selected="selected"';
}
else {
$checked = '';
}
?>
<option value="<?=$option?>" <?=$checked?>><?=$label?></option>
<?php
}
?>
</select>
</form>
Put this form in a string ($form) and do this
$form = str_replace(" value='".$id."'>"," value='".$id."' selected>", $form);
echo $form;
You can memorize the $id in a cookie.
when the user loads the page, you have to check the database for the current selection.
then you change the html based on the selection:
<OPTION value='1' selected='selected'>Open</OPTION>
<OPTION value='0'>Closed</OPTION>
or
<OPTION value='1'>Open</OPTION>
<OPTION value='0' selected='selected'>Closed</OPTION>
by the way, your ID has not been set in this form. you need to escape that as well
Not really the best solution, but it don't really know where this is going.
<select size="1" name="type">
<option value=""></option>
<option value="1"<?= $_POST['type']==1 ? " selected" : ""?>></option>
<option value="0"<?= $_POST['type']==0 ? " selected" : ""?>></option>
</select>
BTW: You might want to take a look at this.
This question was asked already, but my question is very simple.
In the my account page, I have the employee country in a dropdown.
How to select a value in the combo, when in edit mode?
Let's assume you have the user's country in $user_country and the list of all countries in $all_countries array:
<select id="country">
<?php
foreach ( $all_countries as $country ):
$selected = "";
if ( $country == $user_country )
$selected = "selected";
?>
<option value="<?php echo $country; ?>"
selected="<?php echo $selected; ?>">
<?php echo $country; ?>
</option>
<?php
endforeach; ?>
</select>
should work.
An option tag will be the default for a select list when the selected attribute is set. In the following code option 2 will show up as the current selected option when the page loads:
<select>
<option value="1">1</option>
<option value="2" selected="selected">2</option>
<option value="3">3</option>
</select>
To achieve this in your PHP code conditionally display the selected attribute on your options against what the current value is:
<option value="1"<?php if($user['country'] == '1') { ?> selected="selected"<?php } ?>>1</option>
<option value="2"<?php if($user['country'] == '2') { ?> selected="selected"<?php } ?>>2</option>
<option value="3"<?php if($user['country'] == '3') { ?> selected="selected"<?php } ?>>3</option>
function p_edit_combo($cCurstatus,$h_code_default,$h_name=NULL){
<select name="<?php echo $cCurstatus;?>" id="<?php echo $cCurstatus;?>" class="main_form_select">
<option value="">Select</option>
<?php
$sql_h = "SELECT h_code,h_name FROM med_hl WHERE status = 1";
$sql_h_result = mysql_query($sql_h);
while($row=mysql_fetch_array($sql_h_result)){
$h_code = $row['h_code'];
$h_name = $row['h_name'];
?>
<option <?php if($h_code_default==$h_code){ ?> selected="selected" <?php }?> value='<?php echo $h_code; ?>' >
<?php echo $h_code."|".$h_name; ?>
</option>
<?php } ?>
</select>
<?php
}
**i have two table
" users" colmns(fname,lname,...as on ohther_infomation,hobbies datatype(int))
"info" columns (id (primary_key),hobbies(varchar 200)); in which i stored for hobbies name
In my case i am storing values in from (1,2,3,4) in hobbies (int) filled of users table which i matached them through join after time of fetch them,
in my info table i stored hobbies by their name (reading, writing,playing,gyming)
$row has our users selected hobbies (int)
$rows has list of our hobbies(varchar)
edit.php i need Dropdown value selected :==== And i am Doing Like this :--- (100% Working)**
<div class="form-control">
<label for="hobbies">Hobbies</label>
<select name="hobbies">
<?php
$query = "SELECT * FROM info";
$results = mysqli_query($connect, $query);
while ($rows = mysqli_fetch_array($results)) {
?>
<option <?php if ($rows['id'] == $row['hobbies']) { ?> selected="selected" <?php } ?> value='<?php echo $rows['id']; ?>'>
<?php echo $rows['hobbies']; ?>
</option>
<?php
}
?>
</select>
<span class="text-danger"><?php if (isset($err_hobbies)) echo $err_hobbies; ?></span>
</div>