for each loop after QueryFetchArrayAll - php

Question

I have a question: I have used the following queries to get my arrays from Database:
$news = $db->QueryFetchArrayAll("SELECT login,id FROM `users` ORDER BY id DESC LIMIT 9");
$imgs = $db->QueryFetchArrayAll("SELECT usrpic,id FROM `users` ORDER BY id DESC LIMIT 9");
Now i need $news['login'] and $imgs['usrpic'] in one for each loop.
For example:
foreach($news as $new, $imgs as $img){
<img style="border: 1px solid #8C0E0E;"src="'.$img['usrpic'].'" width="20" height="20" border="0" />
<img style="border: 1px solid #8C0E0E;"src="'.$new['login'].'" width="20" height="20" border="0" />
}
Can anyone help me how i can do this ?

Answer 1

You can use next() function : http://php.net/manual/en/function.next.php
but don't forget to make sure news and img have same size :
if(count($news) == count($imgs)) {
foreach($news as $new) {
$img = next($imgs);
<img style="border: 1px solid #8C0E0E;"src="'.$img['usrpic'].'" width="20" height="20" border="0" />
<img style="border: 1px solid #8C0E0E;"src="'.$new['login'].'" width="20" height="20" border="0" />
}
}

Answer 2

If those are your actual queries, you should combine them into one:
$users = $db->QueryFetchArrayAll("SELECT id, login, usrpic FROM `users` ORDER BY id DESC LIMIT 9");
Then iterate the result array and output the images:
foreach ($users as $user) {
echo "<img src='{$user['usrpic']}' ... />";
echo "<img src='{$user['login']}' ... />";
}
Otherwise (keeping your original queries), you should make sure $news and $imgs have the same length, and then iterate one of them:
$size = count($imgs);
for ($i = 0; $i < $size; $i++) {
$img = $imgs[$i];
$new = $news[$i];
echo "<img src='{$img['usrpic']}' ... />";
echo "<img src='{$new['login']}' ... />";
}