php code not working inside html - php

Question

I am trying to display an image. I have fetched my URL from the db storage. And i have used the php variable inside the image tag. But the code does'nt display any image .
what is the problem? exactly!
this is my code below
<?php $db =& JFactory::getDBO();
$query88=$sql = "SELECT file_url_thumb FROM fs01_virtuemart_medias WHERE virtuemart_media_id=1 LIMIT 0, 30 ";
$result88 = mysql_query($query88) or die(mysql_error());
?><img src="<?php while($row = mysql_fetch_array($result88)){
echo $row['file_url_thumb'];
echo "<br />";
} ?>" border="0" style="border: 0; vertical-align: top;" />

Answer 1

You are looping over your results and putting them all (each followed by a <br /> inside the src attribute of an img tag. It seems highly unlikely that that won't 404.
You probably want something more like:
<ul>
<?php while($row = mysql_fetch_array($result88)){ ?>
<li><img src="<?php echo htmlspecialchars($row['file_url_thumb']); ?>" /></li>
<?php } ?>
</ul>
(With some CSS from an external stylesheet to apply your presentation).

Answer 2

<?php
$db = &JFactory::getDBO();
$query88 = "SELECT file_url_thumb FROM fs01_virtuemart_medias WHERE virtuemart_media_id=1 LIMIT 0, 30 ";
$result88 = mysql_query( $query88 ) or die( mysql_error() );
while( $row = mysql_fetch_array( $result88 ) ) {
echo '<img src="' . $row[ 'file_url_thumb' ] . '" border="0" style="border: 0; vertical-align: top;" /><br />';
}
?>

Answer 3

use this
<?php
$db = &JFactory::getDBO();
$query88 = "SELECT file_url_thumb FROM fs01_virtuemart_medias WHERE virtuemart_media_id=1 LIMIT 0, 30 ";
$result88 = mysql_query( $query88 ) or die( mysql_error() );
while($row = mysql_fetch_array($result88)){
echo '<img src="'.$row['file_url_thumb'].'" style=" border="0" style="border: 0; vertical-align: top;"/>';
echo '</br>';
}
?>