So, I've written a query which should grab 15 most recent results from the 'messages' table, but order results by date in descending direction. My current query is as follows:
SELECT * FROM messages
WHERE chatID = 1
ORDER BY ID DESC, timeSent ASC
LIMIT 15
As you can see, I am using the 'ID DESC' to get the 15 most recent results, but the 'timeSent ASC' isn't ordering the results in the order I wish.
How can I correct my query to achieve this?
First fetch the messages by ordering the ID then sort it according to timeSent. You can try this -
SELECT * FROM
(SELECT * FROM messages WHERE chatID = 1 ORDER BY ID DESC LIMIT 15) messages_ordered
ORDER BY timeSent ASC
Related
I have this line:
$query = mysql_query("SELECT * FROM livechat WHERE type='public' ORDER BY id ASC LIMIT 15") ;
And this is for chat, however ASC takes only first ID comments, so it shows only 15 old comments (id1, id2 and so on). If I use DESC instead of ASC, it shows new comments, but in a bad way - newest at the top, since this is a chat, newest comments must be at the bottom.
Try creating a temporary table that contains the last 15 results, and then ordering from that table.
select * from (
select * from livechat where type='public' order by id desc limit 15
) tmp order by tmp.id asc
try like this:
$query = mysql_query("SELECT *
FROM (
SELECT *
FROM livechat
WHERE type='public'
ORDER BY id DESC LIMIT 15
) t
order by t.id") ;
I have a basic write to and retrieve SQL database PHP "thing" and I want to have the output in descending order. How do I do that?
For example, the last entry is shown first, then the entry before that, then the entry before that, etc. The first entry ever is last.
Use:
SELECT field_name
FROM table_name
ORDER BY id DESC
By default, MySQL will show results in ascending order. If you want to show them in reverse order, use ORDER BY field_name DESC.
You can use id or date as the field name.
Change the ORDER BY statement
from ORDER BY col or ORDER BY col ASC or to ORDER BY col DESC
from ORDER BY col DESC to ORDER BY col ASC
Sort using DESC ORDER BY.
SELECT * FROM <TABLE> ORDER BY <COLUMN> DESC
If there's an auto increment field, you order by that field, descending.
SELECT "column_name"
FROM "table_name"
[WHERE "condition"]
ORDER BY "column_name" [ASC, DESC];
That's from ORDER BY Clause - Sort Data In SQL.
Write the below query to retrieve data:
SELECT * FROM `table_name` order by id desc
It will retrieve data from the table in descending order.
MySQL general query syntax for SELECT:
SELECT field1, field2,...fieldN FROM table_name
[WHERE Clause][GROUP BY]
[ORDER BY][LIMIT]
Example query 1:
SELECT id,first_name,last_name,email FROM users ORDER BY first_name desc // In this case you can only fetch data by = id,first_name,last_name,email
Example query 2:
SELECT * FROM users ORDER BY first_name desc // In this case all fields will be selected
Note: ORDER BY ASC = Data will sort by Ascending Order & ORDER BY DESC = Data will sort by descending Order
i have a MySql table that consists of 2 basic things:
The id and a value.
To show that on my page, i need to select, for example, the last 100 rows on reversed order.
So imagine that someone is putting data on it:
Id, value
1, 10
2, 9
3, 21
4, 15
i need, to select the last "3" rows (LIMIT + ORDER Clause), but not like this: 4,3,2 but like this: 2,3,4.
I know how to do that on code, but maybe there is a simple solution for that on Mysql and i don`t know.
Thanks
My SQL Query is like this right now:
SELECT `Data`.`id`, `Data`.`log_id`, `Data`.`value`, `Data`.`created` FROM `control_panel`.`datas` AS `Data` WHERE `Data`.`id` > 1000 AND `Data`.`log_id` = (2) ORDER BY `Data`.`id` DESC LIMIT 100
You need to wrap the first ORDER BY in a subselect which will return a limited selection ordered in descending order, then you can order that result in the outer query in ascending order:
SELECT
a.*
FROM
(
SELECT id, value
FROM tbl
ORDER BY id DESC
LIMIT 3
) a
ORDER BY
a.id
One way to do this would be with a sub-select.
SELECT *
FROM (SELECT * FROM table_name ORDER BY id DESC LIMIT 3) tmp
ORDER BY id ASC
simply
SELECT t.*
(SELECT * FROM table_name
ORDER BY column_name DESC
LIMIT 0,3) t
ORDER BY t.column_name ASC
use DESC to descending order, ASC to increasing order
I want to select the newest posts from users, I am looking for the most efficient way to do this.
Currently this selects the first post, not the last:
$query = mysql_query("
SELECT *
FROM posts
WHERE toID=fromID
GROUP BY fromID
ORDER BY date DESC LIMIT 3");
Table Structure:
Table: posts
id ToID FromID Post State Date
1 1 1 Hey 0 1325993600
2 1 6 okay yeah 0 1325993615
3 1 2 again 0 1325994600
4 6 6 yeah2 0 1325995615
so from this above example it would return id: 1 and 4.
toID=fromID is just to get the post that is a status message, meaning the user posted something on their own page, not someone elses.
I want to get the most recent status from the last 3 users that have updated their status.
The ID thing would still work theoretically, provided that the ID's never change...
I would recommend using a timestamp field in the table structure called "date" and use the "CURRENT_TIMESTAMP" as default value, this will auto-populate the date/time on the record upon insert...
Order by this field DESC, limit x
Also, I have experienced many cases of the wrong data appearing thanks to grouping... Make sure your data is correct before ORDER BY and LIMIT is applied
For getting posts from user1 to user1 there's no need to group by:
SELECT * FROM posts
WHERE toID=fromID
ORDER BY date DESC LIMIT 3
For getting posts from * to user1:
SELECT * FROM posts
WHERE toID="USER1_ID"
ORDER BY date DESC LIMIT 3
For getting posts from * to user1, only unique users:
SELECT * FROM posts
WHERE toID="USER1_ID"
GROUP BY FromID
ORDER BY date DESC LIMIT 3
Somtimes you will run into the problem where GROUPED records are not ordered by ORDER BY, because the ORDER BY is applied to the result AFTER the grouping is applied... To achieve a workaround:
SELECT * FROM (
SELECT * FROM posts
WHERE toID="USER1_ID"
ORDER BY date DESC
) as `derived` GROUP BY FromID LIMIT 3
To Get the last 3 users who have most recently sent themselves a post:
SELECT * FROM (
SELECT * FROM posts
WHERE toID=fromID
ORDER BY date DESC
) as `derived` GROUP BY FromID LIMIT 3
try this query.
$query = mysql_query("SELECT * FROM posts WHERE toID=fromID GROUP BY id ORDER BY date DESC LIMIT 3");
I have a set of players and I want to select the top 5 scores from the tables and print out the username and scores in descending order, what's the SQL statement for that?
and How to output the result?
SELECT * FROM yourtable ORDER BY score DESC LIMIT 5
Explanations:
SELECT * FROM yourtable: we select yourtable.
ORDER BY score DESC: We order the results based on the column score and in descending order.
LIMIT 5: we limit the number of results by 5.