How to fetch data from database using prepare statement in php? - php

Question

I have a database in which I have user_id & associated_id.There can be multiple associated_id for a single user_id. Now I want to fetch all the associated_ids into a single array. I have tried this method but don't know how to get them in array.
$stmt = $this->conn->prepare("SELECT * FROM my_contacts WHERE user_id = ?");
$stmt->bind_param("s", $user_id);
if ($stmt->execute())
{
while ($stmt->fetch())
{
//what to write here
}
//echo var_dump($user);
$stmt->close();
}

Answer 1

Try this:
$stmt = $mysqli->prepare("SELECT associated_id FROM my_contacts WHERE user_id = ?")) {
$stmt->bind_param('s', $user_id); // Bind "$user_id" to parameter.
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
// get variables from result.
$stmt->bind_result($associated_id);
$stmt->fetch();
The results will be stored in the $associated_id array.

Answer 2

You can bind parameters like this and use fetchall method to get all the results in a array
$stmt = $this->conn->prepare("SELECT * FROM my_contacts WHERE user_id = :user_id");
$stmt->bind_param(":user_id", $user_id, PDO::PARAM_INT);
if ($stmt->execute())
{
$result = $stmt->fetchall(PDO::FETCH_ASSOC);
//echo var_dump($user);
$stmt->close();
}

Answer 3

According to your code you used mysqli.
$stmt = $this->conn->prepare("SELECT * FROM my_contacts WHERE user_id = ?");
if($stmt->execute()){
$result = $stmt->get_result();
if($result->nom_rows > 0){
while($row = $result->fetch_assoc()){
var_dump($row)
}
}else{
echo "Sorry NO data found";
}
}else{
echo "Some thing is wrong";
}
here you can't used $stmt->bind_result(); instead of use $stmt->get_result()
$stmt->bind_result(); is only used when you define field in select query
with * you need to used $stmt->get_result()
refer this link for more information
Example of how to use bind_result vs get_result