Preparing SQL query with multiple parameters (mysqli) [duplicate] - php

Question

This is my simple query in php, using mysqli object oriented style:
$query = "SELECT name FROM usertable WHERE id = ?";
$stmt = $mysqli->prepare($query);
$stmt->bind_param('i', $id);
$id= $_GET['id'];
$stmt->execute();
$stmt->bind_result($name);
while($stmt->fetch()){
echo $name." ";
}
$stmt->free_result();
$stmt->close();
This works fine. I obtain the list of name retrieved from the select statement.
Now, inside the while I want use the $name variable as parameter for another query, but mysqli do not allow this, since I have to close the first query and then call the second query.
So I think I have to store the result of the first query and then iterate over the result calling a new query.
I have tried the following:
$query = "SELECT name FROM usertable WHERE id = ?";
$stmt = $mysqli->prepare($query);
$stmt->bind_param('i', $id);
$id= $_GET['id'];
$stmt->execute();
//$stmt->bind_result($name);
$result = $stmt->store_result();
$stmt->free_result();
$stmt->close();
while ($row = $result->fetch_row())
{
echo $row[0]." ";
}
But this does not work. The code inside while is never reached.
N.B.: I want avoid the use of multi_query().

Answer 1

mysqli_stmt::store_result return a boolean. According to the doc it should be something like:
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($name);
while($stmt->fetch()){
//echo $name." ";
// try another statement
$query = "INSERT INTO usertable ...";
$stmt2 = $mysqli->prepare($query);
...
}
$stmt->free_result();
$stmt->close();
If this doesn't work you can fetch all rows first into an array and then looping that array again:
$stmt->execute();
$stmt->bind_result($name);
$names = array();
while($stmt->fetch()){
$names[] = $name;
}
$stmt->free_result();
$stmt->close();
foreach($names as $name) {
$query = "INSERT INTO usertable ...";
$stmt = $mysqli->prepare($query);
...
}

Answer 2

I have solved the problem:
$query = "SELECT name FROM usertable WHERE id = ?";
$stmt = $mysqli->prepare($query);
$stmt->bind_param('i', $id);
$id= $_GET['id'];
$stmt->execute();
$result = $stmt->get_result();
$stmt->free_result();
$stmt->close();
while ($row = $result->fetch_array(MYSQLI_NUM))
{
echo $row[0]." ";
}
Simply using get_result() and fetch_array()