I just installed Slimerjs and no results on the web.
the slimerjs is found and commands like -help etc output like they should:
exec('/usr/bin/slimerjs -help'.' 2>&1',$out,$ret);
but this line does not work
exec('/usr/bin/slimerjs /var/www/html/capture.js'.' 2>&1',$out,$ret); var_dump($ret, $out);
outputs only int(1); and nothing more. no errors in logs, it does not work. I can write everything I like if the bath is correct the output is always int(1).
Thank you
Had same issue now, just a minute ago. But I am using a combination of Casperjs with Slimerjs engine (Casperjs is a great tool for working with your slimerjs and phantomjs scripts, in a friendlier enviroment programming).
The working php script:
<?php
putenv("PHANTOMJS_EXECUTABLE=/usr/local/bin/phantomjs");
putenv("CASPERJS_EXECUTABLE=/usr/local/bin/casperjs");
putenv("SLIMERJS_EXECUTABLE=/usr/local/bin/slimerjs");
putenv("DYLD_LIBRARY_PATH");
echo passthru('/usr/bin/xvfb-run /usr/local/bin/casperjs --ssl-protocol=any --proxy-type=auto --engine=slimerjs casperjsscript.js 2>&1');
?>
You could perhaps check to include some of the paths, as indicated seen in my script and make a few changes, or just install Casperjs :)
Related
Last night I spent 5.5 hours trying make PHP execute and receive the output of Virtualenv’ed Python script. Nothing worked; except for scripts that were not Virtualenv’ed.
What I am trying to do:
I am trying to make PHP call a virtualenv’d install of the Newspaper lib output text when I call it.
What I have now:
PHP: (updated)
<?php
$output = exec('newspaper2/bin/python3 /var/www/html/components/python/test.py 2>&1', $output2);
print_r(error_get_last());
echo $output2;
echo $output;
…this works when using a non-virtualenv script
Python: (updated)
from newspaper import Article
url = 'http://example.com/'
article = Article(url)
article.download()
article.html
article.parse()
article.authors
article.publish_date
string = article.text
print(string)
What the issue is:
I can run the script that PHP is running from the command line and it outputs just fine.
What I have tried:
With PHP, (I have tried all the “exec” calls for PHP) it cannot seem to open the virtual environment and returns nothing.
Before the script I have called “python3” and a few other things to no avail.
Yes, I have chmoded it to be executable…
I feel like this should be so simple.
I have tried suggestions on other posts and all over the web to no avail.
Questions:
Did I set up the virtualenv wrong?
At the top of the Python script, instead of the “#!/usr/bin/env python3” should I call something else?
If so, where do I find it? Should I start from scratch and will that
help?
Thank you for your help;
PS: I am running Ubuntu16, PHP7 and I need to use Python3
In the virtualenv'ed scripts (i.e. installed via the setuptools' entry-points), you should not touch the shebang (#!... first line). It is populated by the virtualenv & setuptools & related tools.
If you specify your own shebang, then it is not virtualenv'ed script. In that case, call python directly:
exec('/path/to/venv/bin/python3 /var/www/html/components/python/testing.py');
Alternatively, you can put the absolute path to the virtualenv's python binary to the py-script, but this does not look a good idea.
Also, remember that virtualenvs are non-relocatable. So they should stay in the path where they were created.
Also note that exec() returns only the last line of the output. You probably want shell_exec() or exec('...', $output) to get the whole output.
Also, it is unclear what happens with your script, and what is being printed on stderr. Try this command to see what is the error:
exec('/path/to/script 2>&1', $output)
#OR:
exec('/path/to/venv/bin/python3 /path/to/script 2>&1', $output)
OK, I finally figured it out and learned a lot in the process. The newspaper lib that I am using by default tries to write to the base of the users home directory. In this case, it was attempting to write to www-data, /var/www.
To fix this:
Go to the settings.py file in the newspaper library.
Edit the variable DATA_DIRECTORY = '.newspaper_scraper' and change it to DATA_DIRECTORY = '.path/to/writable/directory'
Save the file and you should be good to go.
I have no idea why it was not returning the errors that would have explained this sooner.
Hope this helps anyone else.
Thank you so much Sergey Vasilyev for your help. I appreciate it greatly.
I'm trying to execute a php script from a php file, but it seems that i can't get the correct bin path of the php.exe. Its not doing anything as far as i can tell. Lets assume service-oauth.php is a simple echo.
EDIT3:
I fixed it using php-cli instead of php or the php bin path, i must admit that i tried this before but it seems something else was off when i tried this (one of the first things i tried). The answer provided by Keith in Can't execute PHP script using PHP exec , so it ended being a duplicate :S, thanks for the help to those who commented.
EDIT2:
I tried calling the script directly from the server console as #Dagon suggested and it works, both using the php env variable and the php path to the bin, its clear that the path is correct, but something is preveting to get the output or to run the script using the php exec() function
service-oauth.php
<?php echo "Hello there"; ?>
And this is my script:
$basePath = plugin_dir_path( __FILE__ ); # Wordpress function, asume it works.
$fileToExc = $basePath . 'service-oauth.php';
# PHP_BINDIR: /usr/local/bin
# PHP_BINARY: /usr/bin/php
# exec("which php") /usr/bin/php
$phpPath = exec("which php");
$output = exec("$phpPath $fileToExc");
print_r($output);
There are a lot of answers on stackoverflow that recommend any of those 3 options i commenented in the code, but none of them seems to work, not sure if it is the path or something else that is not working. I've tested this script on my localmachine (windows) and it works (even though i had to use a hardcoded path to the bin since i wans't getting the correct path), but i'm testing on my production server (linux) and is not working.
Note: Let me be clear, that this is not a duplicate, i've tried the following answers in these posts and many others, and it didn't work for me:
How to get path of the php binary on server where it is located
Can't execute PHP script using PHP exec
PHP exec to run a file
How to call shell script from another shell script?
Execute a PHP script from another PHP script
I've also tried using .exe at the end of the binary(windows localmachine), using php-cli instead of php, and i've tested the excec function and it works, but not in this case. Also tried with a shebang in the called script.
It's propably something simple that i'm not aware of but i've been spending a lot of hours searching and testing and nothing so far. Any help is appreciated.
EDIT:
Using scandir on the bin folder shows
scandir("/usr/bin/")
Array(
...
[632] => php
[633] => php-cgi
[634] => php-cli
...
)
Tested if in safe mode using ini_get('safe_mode'), but it seems off.
I fixed it using php-cli instead of php or the php bin path, i must admit that i tried this before but it seems something else was off when i tried this (one of the first things i tried). The answer provided by Keith in Can't execute PHP script using PHP exec , so it ended being a duplicate :S, thanks for the help to those who commented. – Zagen
I'm setting up a big system relying on python 2.7 being run through php. The call is always something like:
exec('python test.py');
However no matter what I do PHP keeps using python 2.4 for executing my files. Because of the size of the system I can't change in the programming, but will have to make 'python' point directly to python2.7.
By searching around I have reached the conclusion that I should change the php env.
echo getenv("PYTHONPATH"); // NOTHING
echo getenv("PATH"); // /bin:/usr/bin
I can do so through putenv (for example: putenv("PATH=/usr/bin/python2.7:".$_ENV["PATH"]), but php keeps running python 2.4 no matter what I change it to.
Hope somebody out there got a simple solution :)
Could you not just do this instead:
exec('/usr/bin/python2.7/python test.py');
another option, you can set path to interpreter in 1st line of script test.py
#!/usr/local/bin/python2.7
but you need make test.py executable
chmod +x path_to_file/test.py
and run from php as
exec('path_to_file/test.py');
P.S. be attentive administrators sometimes disable exec function on servers for safety.
disable_functions="popen,exec,system,passthru,proc_open,shell_exec" ....
If you can't use full path, try an alias:
alias python='/usr/bin/python2.7'
python --version
Python 2.7.2
Goal:
Run a simple Rscript from a wordpress page.
I'm currently attempting to run an Rscript using exec() upon loading the page. The script creates a histogram of 100 random samples from integers 1 through 10, writes system time to title and saves figure to .png file.
Setup:
Running Wordpress install on Ubuntu EC2 micro instance
R has been successfully installed and tested through ssh
Using Exec-PHP Wordpress plugin so that PHP code can be written and executed (tested successfully)
PHP code (within wordpress Page)
<?php
echo "This is the Exec-PHP 'Hello World'\n";
echo exec("date");
?>
<?php
exec("Rscript <PATH>/test.R");
?>
<img src="<Image Location>/samplePlot.png" alt="" title="Sample R" />
Rscript - test.R
png( "<Image Location>/samplePlot.png")
hist( sample( 1:10, 100, replace = TRUE), main= Sys.time(), lwd = 5)
dev.off()
The image file loads but it is not updated, indicating the Rscript was never executed. I've isolated it down to that being the issue but unsure why that is.
How can I debug this? I don't really know any PHP but I tried the following:
<?php
exec("\usr\bin\Rscript <PATH>/test.R", $output, $result);
echo $output;
echo $result
?>
Which returns:
Array2
I was hoping to get the command line output to check for errors. Is this possible?
I would think that the problem is that you did not specify the full path to Rscript and the user running PHP/Apache just does not know where to search for it.
Update that exec command like (on Linux):
exec("/usr/bin/Rscript <PATH>/test.R");
Anyway, I would suggest installing littler for the task later and (based on that) runnning r instead of Rscript for letting things run a lot faster - if installing eg. rApache is not an option.
To get an idea of the problem try:
$e = exec("\usr\bin\Rscript <PATH>/test.R 2>&1");
var_dump($e);
If you get something like: Error in dyn.load(file, DLLpath = DLLpath, ...) ...
you probably need to update the servers dynamic libraries (try searching for libfreetype.dylib), or if your running MAMP (as I am) you need to comment (#) the two uncommented lines in: /Applications/MAMP/Library/bin/envvars
I know it is a long time since you posted the question, but I spend a lot of time with a similar problem - hopefully somebody can save some time ;)
I am attempting to create a php script that can connect thru ssh to my Qnap TS219 server and run a command on it.
My script so far connects fine to the server but when I run the command I get an error message and I can't figure it out.
exec.sh
#!/bin/bash
cp /share/MD0_DATA/Qdownload/rapidshare/admin/script.txt /share/MD0_DATA/Qdownload/rapidshare/admin/script.sh
chmod 755 /share/MD0_DATA/Qdownload/rapidshare/admin/script.sh
nohup sh /share/MD0_DATA/Qdownload/rapidshare/admin/script.sh &
exit 0
script.sh
#!/bin/bash
/opt/bin/plowdown -o /share/MD0_DATA/Qdownload/rapidshare /share/MD0_DATA/Qdownload/rapidshare/admin/down.txt 2>/share/MD0_DATA/Qdownload/rapidshare/admin/output.txt
the command that I am currently running thru ssh after I submit the form:
echo $ssh->exec('sh /share/MD0_DATA/Qdownload/rapidshare/admin/exec.sh');
Right now generates the code below but only after I kill 2 bash processes (the page keeps loading indefinetly and the processor activity is at 100% if I don't kill the 2 bash processes):
/share/MD0_DATA/.qpkg/Optware/share/plowshare/lib.sh: line 261: getopt: command not found start download (rapidshare): http://rapidshare.com/files/312885386/Free_Stuff-Your_Internet_eBay_Business_Free_Startup_Resources.rar /share/MD0_DATA/.qpkg/Optware/share/plowshare/lib.sh: line 261: getopt: command not found /share/MD0_DATA/.qpkg/Optware/share/plowshare/lib.sh: line 46: --insecure: command not found Error: failed inside rapidshare_download()
This script will be used in my local network, no access from outside, so I am not worry about security, I know the code looks very basic, primitive but I have no experience with php, shell script, so if someone can make any sense on this and help me out will be greatly appreciated.
Edit1. I also tried the shell_exec command still no joy and if I run the script thru putty works beautifully.
Edit2. I think we are on to something.
I added the code you suggested and I got the following message.
sh: /share/MD0_DATA/.qpkg/Optware/share/plowshare: is a directory /usr/bin:/bin:/usr/sbin:/sbin
I think at the moment the PATH is usr/bin:/bin:usr/sbin:/sbin and I think it should be /opt/bin /opt/sbin because there are the "executables". Any ideeas?
Thanks,
Chris.
Run this
echo $ssh->exec('pwd');
Does it list your path correctly? If so then your problem is NOT PHP, if it doesn't list or still gives an error then PHP is your problem and we can continue from there.
From the error you've listed, my first guess would be that PATH isn't set, so lib.sh can't find what it's looking for.
Remember you're logging in with a custom shell (PHP ssh), quite often things aren't set as they should be, so your scripts might not find requirements like paths and variables.
Edit:
Since it's giving /root, we at least know it's going through, why not also set the PATH etc...
echo $ssh->exec('PATH=$PATH;/share/MD0_DATA/.qpkg/Optware/share/plowshare; sh /share/MD0_DATA/Qdownload/rapidshare/admin/exec.sh');
Remember you can also use this to see what is and isn't being set.
echo $ssh->exec('ECHO $PATH');
I think I got it:
Following viper_sb logic, I changed the code to:
echo $ssh->exec('PATH=$PATH:/share/MD0_DATA/.qpkg/Optware/bin; sh /share/MD0_DATA/Qdownload/rapidshare/admin/exec.sh');
echo $ssh->exec('echo $PATH');
and magic, it worked ... I'll test it further, when I get home, but I think it worked, a file was downloaded in the /Qdownload/rapidshare folder ... hooray.