Execute a php script within a running php script - php

I'm trying to execute a php script from a php file, but it seems that i can't get the correct bin path of the php.exe. Its not doing anything as far as i can tell. Lets assume service-oauth.php is a simple echo.
EDIT3:
I fixed it using php-cli instead of php or the php bin path, i must admit that i tried this before but it seems something else was off when i tried this (one of the first things i tried). The answer provided by Keith in Can't execute PHP script using PHP exec , so it ended being a duplicate :S, thanks for the help to those who commented.
EDIT2:
I tried calling the script directly from the server console as #Dagon suggested and it works, both using the php env variable and the php path to the bin, its clear that the path is correct, but something is preveting to get the output or to run the script using the php exec() function
service-oauth.php
<?php echo "Hello there"; ?>
And this is my script:
$basePath = plugin_dir_path( __FILE__ ); # Wordpress function, asume it works.
$fileToExc = $basePath . 'service-oauth.php';
# PHP_BINDIR: /usr/local/bin
# PHP_BINARY: /usr/bin/php
# exec("which php") /usr/bin/php
$phpPath = exec("which php");
$output = exec("$phpPath $fileToExc");
print_r($output);
There are a lot of answers on stackoverflow that recommend any of those 3 options i commenented in the code, but none of them seems to work, not sure if it is the path or something else that is not working. I've tested this script on my localmachine (windows) and it works (even though i had to use a hardcoded path to the bin since i wans't getting the correct path), but i'm testing on my production server (linux) and is not working.
Note: Let me be clear, that this is not a duplicate, i've tried the following answers in these posts and many others, and it didn't work for me:
How to get path of the php binary on server where it is located
Can't execute PHP script using PHP exec
PHP exec to run a file
How to call shell script from another shell script?
Execute a PHP script from another PHP script
I've also tried using .exe at the end of the binary(windows localmachine), using php-cli instead of php, and i've tested the excec function and it works, but not in this case. Also tried with a shebang in the called script.
It's propably something simple that i'm not aware of but i've been spending a lot of hours searching and testing and nothing so far. Any help is appreciated.
EDIT:
Using scandir on the bin folder shows
scandir("/usr/bin/")
Array(
...
[632] => php
[633] => php-cgi
[634] => php-cli
...
)
Tested if in safe mode using ini_get('safe_mode'), but it seems off.

I fixed it using php-cli instead of php or the php bin path, i must admit that i tried this before but it seems something else was off when i tried this (one of the first things i tried). The answer provided by Keith in Can't execute PHP script using PHP exec , so it ended being a duplicate :S, thanks for the help to those who commented. – Zagen

Related

Using PHP to call Virtualenv’ed Python Script

Last night I spent 5.5 hours trying make PHP execute and receive the output of Virtualenv’ed Python script. Nothing worked; except for scripts that were not Virtualenv’ed.
What I am trying to do:
I am trying to make PHP call a virtualenv’d install of the Newspaper lib output text when I call it.
What I have now:
PHP: (updated)
<?php
$output = exec('newspaper2/bin/python3 /var/www/html/components/python/test.py 2>&1', $output2);
print_r(error_get_last());
echo $output2;
echo $output;
…this works when using a non-virtualenv script
Python: (updated)
from newspaper import Article
url = 'http://example.com/'
article = Article(url)
article.download()
article.html
article.parse()
article.authors
article.publish_date
string = article.text
print(string)
What the issue is:
I can run the script that PHP is running from the command line and it outputs just fine.
What I have tried:
With PHP, (I have tried all the “exec” calls for PHP) it cannot seem to open the virtual environment and returns nothing.
Before the script I have called “python3” and a few other things to no avail.
Yes, I have chmoded it to be executable…
I feel like this should be so simple.
I have tried suggestions on other posts and all over the web to no avail.
Questions:
Did I set up the virtualenv wrong?
At the top of the Python script, instead of the “#!/usr/bin/env python3” should I call something else?
If so, where do I find it? Should I start from scratch and will that
help?
Thank you for your help;
PS: I am running Ubuntu16, PHP7 and I need to use Python3
In the virtualenv'ed scripts (i.e. installed via the setuptools' entry-points), you should not touch the shebang (#!... first line). It is populated by the virtualenv & setuptools & related tools.
If you specify your own shebang, then it is not virtualenv'ed script. In that case, call python directly:
exec('/path/to/venv/bin/python3 /var/www/html/components/python/testing.py');
Alternatively, you can put the absolute path to the virtualenv's python binary to the py-script, but this does not look a good idea.
Also, remember that virtualenvs are non-relocatable. So they should stay in the path where they were created.
Also note that exec() returns only the last line of the output. You probably want shell_exec() or exec('...', $output) to get the whole output.
Also, it is unclear what happens with your script, and what is being printed on stderr. Try this command to see what is the error:
exec('/path/to/script 2>&1', $output)
#OR:
exec('/path/to/venv/bin/python3 /path/to/script 2>&1', $output)
OK, I finally figured it out and learned a lot in the process. The newspaper lib that I am using by default tries to write to the base of the users home directory. In this case, it was attempting to write to www-data, /var/www.
To fix this:
Go to the settings.py file in the newspaper library.
Edit the variable DATA_DIRECTORY = '.newspaper_scraper' and change it to DATA_DIRECTORY = '.path/to/writable/directory'
Save the file and you should be good to go.
I have no idea why it was not returning the errors that would have explained this sooner.
Hope this helps anyone else.
Thank you so much Sergey Vasilyev for your help. I appreciate it greatly.

How to run a php file from bash script?

I am working in a Windows machine. I need to run a script that will execute a php file. When I run where php to find my php executable location I get the following:
c:\xampp\php\phpe.exe
After that I tried something like this:
#!/bin/bash
#!/c:/xampp/php c:/xampp/htdocs/Bash/testingphp.php
I don't get any error, but I don't know if the script is doing something. Just for reference I am using cygwing to run the scripts. How do I know if my script is really working??
Thank you in advanced
As stated by #Etan, your second line is a comment, but your paths are also incorrect. You need to use /cygdrive/c/, not /c:/. Here is the corrected script:
#!/bin/bash
/cygdrive/c/xampp/php /cygdrive/c/xampp/htdocs/Bash/testingphp.php

php exec() is not executing the command

I have tried to use exec() with 'whoami' to check if it works and I got the result of
nt authority\system
Now I need to run a .exe file with parameters from php via exec() function.
I tried this in command prompt and it actually runs the program with given parameters. This is the example command.
NOTE the exe file gets 3 inputs (folder, file_name, report_file_nmae)
> ..\..\some_file.exe folder="C:\path_to_folder" param=1.xml report=2.xml
But when I run this command from php file:
exec('..\..\some_file.exe folder="C:\path_to_folder" param=1.xml report=2.xml');
nothing is happening. This is the first time I am using exec() function, so I am not familiar with its details. What is wrong?
I tried using:
\\ instead of \
escapeshellarg() on the directory
added "" around directory folder names
No luck
Addendum:
echo exec($command) // echos < .... why?
or
exec($command, $output);
print_r($output); // Array()
I even changed the permission on the file to full control to all users.
If I call the program from command prompt, I can see the icon appearing next to clock for a second.
But the same call from php will not even call the program.
Edit
Even exec('notepad.exe'); is not working. Something has to be done with php configurations maybe?
I already said that I was new to exec() function. After doing some more digging, I came upon 2>&1 which needs to be added at the end of command in exec().
Thanks #mattosmat for pointing it out in the comments too. I did not try this at once because you said it is a Linux command, I am on Windows.
So, what I have discovered, the command is actually executing in the back-end. That is why I could not see it actually running, which I was expecting to happen.
For all of you, who had similar problem, my advise is to use that command. It will point out all the errors and also tell you info/details about execution.
exec('some_command 2>&1', $output);
print_r($output); // to see the response to your command
Thanks for all the help guys, I appreciate it ;)
You might also try giving the full path to the binary you're trying to run. That solved my problem when trying to use ImageMagick.

php exec with vboxmanage to start virtual server.

I am trying to do a simple project to start a VirtualBox VM using a PHP script. My server is win 7 ultimate and running php5.3 I am using the vboxmanage.exe to start the server. cmd works great in a batch file or typed right into cmd line.
When I use:
exec("path to vboxmange.exe" startvm "vm name");
it doesnt work. If I change the code to:
exec(dir);
it works fine. I did some searching and everyone seemed to mention permissions for IIS_IUSRS. I set it to have read and execute on the vboxmanage.exe and tried to do it for cmd.exe but cant seem to get it to allow me to do this, though it doesnt seem necessary as it can run other cmds like dir.
another theory I have is that exec wraps the entire cmd in "" and this doesnt work when I try to type it in to cmd line manually. I have tried to trim it off but that doesnt work cause exec adds it on so nothing I do before can stop this.
any suggestions for another way to do this or what it might be?
From exec in the PHP Manual:
Note: When safe mode is enabled, you can only execute files within the
safe_mode_exec_dir. For practical reasons, it is currently not allowed
to have .. components in the path to the executable.
Check the value of your safe_mode_exec_dir in your php.ini. I would guess that it would be fairly restrictive by default.
If that doesn't work, take a look in the comments. Particularly, this comment might be of help to you.

Problem with passthru on server

I have a problem trying to run passthru function in my php code (Joomla module). the code is following (this is only a snippet)
ob_start();
passthru("/usr/bin/whois 85.70.231.130 | /usr/bin/grep 'address:'",$code);
$whoisData = ob_get_contents();
ob_end_clean();
$whoisData = str_replace("address:", "", $whoisData);
$whoisArray = split("\n",$whoisData);
echo trim($whoisArray[1]);
when I run this on my localhost, it echoes what it should, but when I run this code on the production server, it echoes nothing and the $code variable contains 127 (command not found). I tryied add absolute paths to these commands into the passthru function, but it didn't helped. Interesting is, that when I run the code right from terminal via ssh and php command, it runs well, but when it's called from application context it doesn't. Does anybody know what I should to do?thanks
SOME EDITS..
safe_mode is on
webserver does not see into /usr/bin and /bin/ folders so what is the best way how to run these commands from php?
usr/bin/grep doesn't look like a valid path to a command.
The missing / at the beginning of the path to the second command might explain the command not found error... even if the first whois command is found.
Have you looked to see if your webserver / php is running chrooted?
print_r(glob('/*'));
if (file_exists('/usr/bin/grep') && file_exists('/usr/bin/whois')) {
print "maybe its a permissions thing?\n";
} else {
print "can't see executables required\n";
}
should give you a clue.
So I have already solved my problem with phpwhois library. I seems like with my server configuration is it unlikely that these functions will be working well. So thanks for your help:)

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