I am making a php script which I will schedule to run every day at 9 AM.
I need to loop through all stored details in a cards table in my DB. Within each row I have an expirationDate column and i need to check if that value is within 3 months of the current date and if so send out an email to remind the user that their card will expire soon. They also want a second reminder sent if the expirationDate is within a month.
The bit I'm having trouble with is the comparison logic for checking if the expiration date is within 3 months of the current date. Code below:
...
if ($Cards = mysqli_stmt_get_result($stmt)){
while($row=mysqli_fetch_array($Cards))
{
$email = $row['email'];
$name = $row['Name'];
$expDate = $row['expDate'];
$reminderSent = $row['reminderSent'];
$timeDiff = (intVal(time()) - intVal($expDate));
echo "curDate is ". time() . " and expDate is ".$expDate. ". Difference is ".(intval(time()) - intVal($expDate));
echo "<br>";
//if ($timeDiff within3months){
// if ($reminderSent == 0) {
// //php code to send email
// }
// else if ($reminderSent == 1 && $timeDiff within1month){
// //php code to send email
// }
//}
}
}
...
I had a thought, I could maybe find the epoch value for 3 months and add that to my expiration date val and check if the curDate is greater than this. Would something like that work?
E.G: $expDate + 5097600 > intVal(time())
Any advice appreciated on if there is a better approach to solving this.
You get the unix timestamp for the date three months ago with strtotime('-3 months'); and can compare it to the timestamp you have in $row['expDate'].
Another solution would be to compare it in SQL:
DATEDIFF(FROM_UNIXTIME(expDate), DATE_SUB(CURDATE(), INTERVAL 3 MONTH))
will give you a positive value if expDate is within that range and a negative value else.
There's no need to intVal() the time() function. But if you want to switch your best bet is DateTime diff
$now = new DateTime();
$then = new DateTime($expDate);
$diff = $then->diff($now);
echo 'Difference is ' . $diff->format('%a days');
Related
I am working on email link expire after some X minutes where X denotes some random date_time. so my motive is to expire the the link after some time what ever I set the date_time in side the $expire_date.
So I just created dummy code myself just in order to sure my code works or not.
$currentDateTime = new \DateTime();
$currentDateTime-> setTimezone(new \DateTimeZone('Asia/kolkata'));
$now = $currentDateTime-> format(' h:iA j-M-Y ');
$expire_date = "02:59PM 26-Mar-2019";
if($now > $expire_date)
{
echo " link is expired";
}
else{
echo " link still alive ";
}
I guess I am missing something in the above code, somehow the above code isn't working if anyone would point out the right direction or some better implementation it would be great.
You are comparing the times as strings. This does not work, as your first formatted string has a leading space.
Instead, try either removing the whitespace, or better, compare the times as DateTime objects:
$timezone = new \DateTimeZone('Asia/kolkata');
// Create the current DateTime object
$currentDateTime = new \DateTime();
$currentDateTime-> setTimezone($timezone);
// Create the given DateTime object
$expire_date = "02:59PM 26-Mar-2019";
$expireDateTime = \DateTime::createFromFormat($expire_date, 'h:iA j-M-Y');
// Compare the objects
if($currentDateTime > $expireDateTime)
{
echo " link is expired";
}
else{
echo " link still alive ";
}
If you want to compare dates in PHP, your best bet is to use UNIX time stamps. A UNIX time stamp is the number of seconds since the UNIX epoch (00:00:00 Thursday, 1 January 1970).
time() will return the current UNIX time stamp.
strtotime() will convert a date string into a UNIX time stamp.
So replacing these two lines:
$now = $currentDateTime-> format(' h:iA j-M-Y ');
$expire_date = "02:59PM 26-Mar-2019";
With these:
$now = time();
$expire_date = strtotime("02:59PM 26-Mar-2019");
Should solve your problem.
You are comparing date strings which will not work. You have to parse the string to a datetime object or timestamp before you can compare these values.
For example, using timestamps:
$expire_date = "02:59PM 26-Mar-2019";
if (time() > strtotime($expire_date)) {
echo "link is expired";
} else {
echo "link still alive ";
}
All you have to do is use strtotime function and add inside date function and here you can specify day, hour, minutes, seconds as a perimeter. This way you can set time manually by adding +5 minutes or so on..
date_default_timezone_set("Asia/Kolkata"); // set time_zone according to your location
$created = "2020-08-14 17:52"; // time when link is created
$expire_date = date('Y-m-d H:i',strtotime('+1 minutes',strtotime($created)));
//+1 day = adds 1 day
//+1 hour = adds 1 hour
//+10 minutes = adds 10 minutes
//+10 seconds = adds 10 seconds
//To sub-tract time its the same except a - is used instead of a +
$now = date("Y-m-d H:i:s"); //current time
if ($now>$expire_date) { //if current time is greater then created time
echo " Your link is expired";
}
else //still has a time
{
echo " link is still alive";
}
In the application that I'm working on, the user must choose a date/time which is at least 5 minutes into the future. For this, I'm trying to implement a check. Below is the code which checks the time difference between the current time and chosen time.
$cur_date = new DateTime();
$cur_date = $cur_date->modify("+1 hours"); //fix the time since its an hour behind
$cur_date = $cur_date->format('m/d/Y g:i A');
$to_time = strtotime($chosen_date);
$from_time = strtotime($cur_date);
echo round(abs($from_time - $to_time) / 60,2). " minute"; //check the time difference
This tells me the time difference from the chosen time and the current time in minutes. So let's say the current time is 09/22/2015 5:53 PM and the chosen time is 09/22/2015 5:41 PM - it will tell me the difference which is 12 minutes.
What I want to know is how I can tell if those 12 minutes are into the future or in the past. I want my application to only proceed if the chosen time is at least 5 minutes into the future.
You're doing too much work. Just use DateTime() to do the date math for you:
// Wrong way to do this. Work with timezones instead
$cur_date = (new DateTime()->modify("+1 hours"));
// Assuming acceptable format for $chosen_date
$to_time = new DateTime($chosen_date);
$diff = $cur_date->diff($to_time);
if ($diff->format('%R') === '-') {
// in the past
}
echo $diff->format('%i') . ' minutes';
Demo
$enteredDate = new DateTime($chosen_date)->getTimestamp();
$now = new DateTime()->getTimestamp();
if(($enteredDate-$now)/60 >=5)echo 'ok';
Basically, the code takes the two dates converted in seconds since 1/1/1970. We calculate the difference between the two dates and divide the result by 60 as we want minutes. If there is a difference of at least 5 minutes, we're ok. If the number is negative, then we are in the past.
If anyone is looking to do something similar, I found the Carbon library which is included by default with the framework I am using (Laravel 5), it was much easier to do this calculation.
$chosen_date = new Carbon($chosen_date, 'Europe/London');
$whitelist_date = Carbon::now('Europe/London');
$whitelist_date->addMinutes(10);
echo "Chosen date must be after this date: ".$whitelist_date ."</br>";
echo "Chosen Date: ".$chosen_date ."</br>";
if ($chosen_date->gt($whitelist_date)) {
echo "proceed";
} else {
echo "dont proceed";
}
I have a database with different workdates, and I have to make a calculation that generates more dates based on a weekinterval (stored in the database) and the (in the database stored) days on which the workdays occur.
What my code does now is the following:
Read the first two workdates -> Calculate the weeks inbetween and save the week interval
Read all the workdates -> fill in the days on which a workdate occurs and save it in a contract.
Generate workdates for the next year, based on the week interval.
The point is: for each week with a week interval of 1, more days of the week should be saved as a workdate. I've used this code to do this, but it doesn't work.
// Get the last workdate's actdate.
$workdate_date = $linked_workdate['Workdate']['workdate_actdate'];
// Calculate the new workdate's date
$date = date("Y-m-d", strtotime($workdate_date . "+" . $interval . " week"));
// If 'Monday' is filled in for this contract, calculate on which day the
// Monday after the last interval is. Same for each day, obviously.
// The days are boolean.
if ($contract['Contract']['contract_maandag'] = 1){
$date = date("Y-m-d", strtotime($date, "next Monday"));
}
if ($contract['Contract']['contract_dinsdag'] = 1){
$date = date("Y-m-d", strtotime($date, "next Tuesday"));
}
// After this, save $date in the database, but that works.
Here is the error that i get:
strtotime() expects parameter 2 to be long, string given
I'm quite stuck right now, so help is appreciated!
if ($contract['Contract']['contract_maandag'] = 1){
if ($contract['Contract']['contract_dinsdag'] = 1){
This won't work. You're doing an assignment (=), so it's always true. But you want a comparison (===). It is recommended to do always (except required otherwise) to use strict (===) comparison.
Well, the = doesn't seem to be the problem, since the error is about the part that's after the comparison. Try
strtotime("$date next Monday");
I am using the following code to attempt to compare the current date with a date entry in a mySql database. It's code that I have found online and adapted as all the examples I have found hard-code the date to compare the current date with.
The trouble is even dates in the future are being marked as expired and I can't understand why this would be.
I am afraid that I am still new to PHP, so I may be making a schoolboy error!
$exp_date = KT_formatDate($row_issue_whatson1['dateToShow']);
$todays_date = date("d-m-Y");
$today = strtotime($todays_date);
$expiration_date = strtotime($exp_date);
if ($expiration_date > $today) { echo "Not expired"; } else { echo "expired"; }
Any help would be most appreciated.
I should add that the date time format used in the database entries is dd/mm/yyyy
Instead of making a string then converting it to a timestamp, simply use mktime:
<?php
$today = mktime(
0, // hour
0, // minute
0 // seconds
);
?>
The rest of the values will be filled according to today's date. If this still gives problems, put in some echo's for the values of $exp_date and $expiration_date.
Edit
Since this solved the problem, the discrepancy you were seeing was because you were doing the opposite with date('d-m-Y'). You were asking for the current date and the time values are then filled in with the current time. The expiration date in the database is likely set at midnight. With both dates being equal, and it being say 11am now, you are comparing if (00:00:00 > 11:00:00) which fails.
$exp_date = 14/05/2011 // todays date, int
$server_date = server.date() // servers date, int
// check exp_date against server date
if ( $server > $exp_date)
{ echo "Sorry your 'service' has expired"; }
else
{ echo "Welcome 'members_name' to StackOverflow"; }
Try that. However you need the right date format, as server.date() is probably different in PHP.
If problem still persists I would check whether your dates are strings or integers or both. That could possibly be the issue.
Hope that helps.
DL.
Your function does not seem to be valid.
function KT_formatDate( $exp_date){
$exp_date = strtotime($exp_date);
$now = time();
if ($now > $exp_date)
return 'expired';
else
return ' Not expired';
}
$response = KT_formatDate($row_issue_whatson1['dateToShow']);
I am pulling a datetime from a mysql db and i would like to add X hours to it then compare it to the current time. So far i got
$dateNow = strtotime(date('Y-m-d H:i:s'));
$dbTime = strtotime($row[0]);
then i tried $dbTime + strtotime("4 hours"); but 4 hours seem to add 4hrs to the current time instead of raw 4hours. How do i add X hours to dbTime?
NOTE: I am using php 5.1.2 so date_add doesnt work (5.3.0)
You have quite a few options here:
1.
$result = mysql_query("SELECT myDate FROM table");
$myDate = mysql_result($result, 0);
$fourHoursAhead = strtotime("+4 hours", strtotime($myDate));
2.
// same first two lines from above
$fourHoursAhead = strtotime($myDate) + 4 * 60 * 60;
3.
$result = mysql_query("SELECT UNIX_TIMESTAMP(myDate) FROM table");
$myDate = mysql_result($result, 0);
$fourHoursAhead = $myDate + 4 * 60 * 60;
4.
$fourHoursAhead = strtotime("+4 hours", $myDate);
5.
$result = mysql_query("SELECT UNIX_TIMESTAMP(DATE_ADD(myDate, INTERVAL 4 HOUR))");
$fourHoursAhead = mysql_result($result, 0);
then i tried $dbTime + strtotime("4 hours"); but 4 hours seem to add 4hrs to the current time instead of raw 4hours. How do i add X hours to dbTime?
strtotime has an optional second argument. Provide a Unix timestamp there and the output will be relative to that date instead of the current date.
$newTime = strtotime('+4 hours', $dbTime);
You can also use the fact that Unix timestamps are seconds-based - if you know what four hours are in seconds, you can just add that to the time integer value.
time() and strtotime() result in unix timestamps in seconds, so you can do something like the following, provided your db and do your comparison:
$fourHours = 60 * 60 * 4;
$futureTime = time() + $fourHours;
strtotime("+4 hours", $dbTime);
The second argument is the timestamp which is used as a base for the calculation of relative dates; it defaults to the current time. Check out the documentation.
Edit:
For short periods of time, max 1 week, adding seconds to a timestamp is perfectly acceptable. There is always (7 * 24 * 3600) seconds in a week; the same cannot be said for a month or year. Furthermore, a unix timestamp is just the number of seconds that have elapsed since the Unix Epoch (January 1 1970 00:00:00 GMT). That is not effected by timezones or daylight-savings. Timezones and daylight-savings are only important when converting a unix timestamp to an actual calendar day and time.
I tend to use the time() function, and this page from the manual shows them displaying the date a week in the future:
http://us3.php.net/manual/en/function.time.php
Here's how I'd do it:
Pull the time from the database using the UNIX_TIMESTAMP() function.
The UNIX timestamp is in seconds, so add 4*60*60 to it.
Convert the modified UNIX timestamp to a date using PHP's localtime() or strftime() function.
query("SELECT UNIX_TIMESTAMP(someDatetimeColumn) ...");
. . .
$dbTimeAdjusted = localtime($row[0] + 4*60*60);
Probably the safest way to do the compare is right in the SQL
SELECT * FROM my_table WHERE someDateTimeColumn < DATE_ADD(NOW(), INTERVAL 4 hour)
And since you're assembling it in PHP, you can dynamically replace the "4 hour" bit with whatever your code needs to compare.
(Note: putting the entire calculation on the other side of the comparison to the column allows MySQL to do the calculation once per query, rather than once per row, and also use the table's index, if that column has one.)
Assuming that the timestamp returned by the DB is in SQL format, the following should work fine:
$dbTime = strtotime($row[0]);
$nowTime = time();
$future_dbTime = strtotime("+4 hours", $dbTime);
$diff_time_seconds = $nowTime - $dbTime;
if ($diff_time_seconds > 0) {
echo "The current time is greater than the database time by:\n";
$not_equal = true;
}
if ($diff_time_seconds == 0) {
echo "The current time is equal to the database time!";
}
if ($diff_time_seconds < 0) {
echo "The current time is less than the database time by:\n";
$not_equal = true;
}
if ($not_equal) {
$diff_time_abs_seconds = abs($diff_time_seconds);
echo date('h:m:s', $diff_time_abs_seconds);
}