PHP show custom result from serialize data - php

Question

I insert data to database using serialize method like this :
a:1:{i:0;a:3:{
i:0;s:14:"docs/name.docx";
i:1;s:39:"docs/php-advanced-master.zip";
i:2;s:39:"docs/php-master.zip";
}}
Now with this function, show/print list of file name:
function _file_list_($id,$type){
$files = DataAccess::fetch("SELECT * FROM " . NEWS_FILES . " WHERE news_id = ? AND type = ? ",$id , $type );
if (count($files) > 0) {
$list_files = unserialize($files[0]['url']);
$count = count($list_files[0]);
for($i=0; $i<$count; $i++){
$files_show[] = array($list_files[0][$i]);
}
return $files_show;
}
else
{
return FALSE;
}
}
This worked for me and result is :
docs/name.docx
docs/php-advanced-master.zip
docs/php-master.zip
But, I need to show/print only docs/php-advanced-master.zip from list.
how do i print/show this ?

Answer 1

You can use array_walk and use whatever logic you need to only show the file you require. The following code will call your function and process the result. It will check if there is a filename with "php-advanced-master.zip" in the list and output it.
$files = array_unique(_file_list_($id,$type), SORT_REGULAR);
array_walk_recursive($files, function ($value) {
if (false !== stripos($value, "php-advanced-master.zip")) {
echo $value;
}
});
However, if you want to filter the serialized data directly from your SQL query. Assuming your serialized data is stored in the "url" field, you can modify your function like this:
function _file_list_($id,$type, $filenameFilter){
$files = DataAccess::fetch("SELECT * FROM " . NEWS_FILES . " WHERE news_id = ? AND type = ? AND url like '%?%'",$id , $type, $filenameFilter);
if (count($files) > 0) {
$list_files = unserialize($files[0]['url']);
$count = count($list_files[0]);
for($i=0; $i<$count; $i++){
$files_show[] = array($list_files[0][$i]);
}
return $files_show;
}
else
{
return FALSE;
}
}