Echo Out Interger Differently If More Than Value PHP - php

So I'm creating a points system for my website which I want to change to an echo instead of the actual integer when shown on the users profile.
For example: When the integer is lower than 1000 it displays as the actual number (lets say: 645). But when it is between 1000 and 1100, it will display as '1k' and so on. What I've got so far does work, but displays incorrectly and does seem a bit of a waste of space.. Is there any way to do this in a much simpler; faster way?
Thanks!
code:
<?php
$points_disp = $user_data['points'];
if($points_disp < 1000){
echo $points_disp;
} else if ($points_disp >= 1000){
echo '1k';
} else if ($points_disp >= 1200){
echo '1.2k';
} else if ($points_disp >= 1400){
echo '1.4k';
} else if ($points_disp >= 1600){
echo '1.6k';
} else if ($points_disp >= 1800){
echo '1.8k';
} else if ($points_disp >= 2000){
echo '2k';
}
?>
Edit: I figured out an easier way to do this;
code (for anyone else who needs to do this):
<?php
$points_disp = $user_data['points'];
$fdigit = substr($points_disp, 0, 1);
$sdigit = substr($points_disp, 1, 1);
if ($points_disp < 1000){
echo $points_disp;
} else if ($points_disp >= 1000){
echo $fdigit . "." . $sdigit . "k";
}
echo $num;
?>

You can use switch case:
$points_disp = $user_data['points'];
switch(true)
{
case ($points_disp < 1000):
$num = $points_disp;
break;
case ($points_disp > 1000 && $points_disp < 1100 ):
$num = '1.2k';
break;
//...so on
}
echo $num;

Try this,
if($points_disp < 1000){
echo $points_disp;
} else if($points_disp >= 1000) {
echo round($points_disp/1000,1) . "K";
}

Related

How to print one message from a loop within a condition?

Let's say I have this loop:
for($i = 1; $i <= 10; $i++){
if($i > 4){
echo 'Greater Than 4.' . '<br/>';
}
}
The previous loop will output the following:
Greater Than 4.
Greater Than 4.
Greater Than 4.
Greater Than 4.
Greater Than 4.
Greater Than 4.
As the condition is true 6 times.
What I want to do is to print this message only once so the output from the same loop and condition will be :
Greater Than 4.
I think this could be achieved by using a variable and give it this value at a specific point , But I don't know how to do it.
Well, it will be like your code expect that you print the message once:
$msg = 'There is no greater than 4';
for($i = 1; $i <= 10; $i++){
if($i > 4){
$msg = 'Greater Than 4.' . '<br/>';
// Make any additional required code here...
}
}
echo $msg;
;
Have you tried this :)
for($i=1;$i<=10;$i++){
echo ($i>4 && !isset($rslt))?$rslt='Greater Than 4.':'';
}
Or, you can loop first
then print the result
like this
$bucket = '';
for($i=1;$i<=10;$i++){
$bucket = ($i>4)?'Greater Than 4.':$bucket;
}
echo $bucket;
Hmmmm, I guess you case like this :D
$bucket = $condition = '';
$flag = 1;
for($i=1;$i<=10;$i++){
if($i>4){
$bucket = 'Greater Than 4. <br>';
$condition .= "Proses :{$flag}<br>";
$flag++;
//more condition process 6 times
}
}
echo $condition;
echo $bucket;
Or like this :D
$j=1;
for($i=1;$i<=10;$i++){
if($i>4){
if($i<=5){
echo 'Greater Than 4. <br>';
}
echo 'Proses '.($j++).'<br>';
//more condition process 6 times
}
}
Or, using the short hand
for($i= $j =0;$i<=10;$i++){
if($i>4){
echo ($i<=5)?'TheGreater Than 4. <br>':false;
$j++;
echo "Process number : {$j} <br>";
}
}
$run_once = true;
for($i = 1; $i <= 10; $i++){
if($i > 4 AND $run_once){
echo 'Greater Than 4.' . '<br/>';
$run_once = false;
}
}
you could also use if ($i == 4)
EDIT:
for($i = 1; $i <= 10; $i++){
if($i > 4){
if($i == 4){
echo 'this runs only once';
}
echo 'this runs every time';
}
}

Why doesn't subtraction sign work on while loop in php?

<?php
$hp = 0;
while($hp < 50) {
$flip = rand(0,2);
if ($flip == 1) {
echo "<p>X-Ray</p>";
$hp += 15;
} elseif ($flip == 2) {
echo "<p>Special Move</p>";
$hp += 10;
} else {
echo "<p>Punch</p>";
$hp += 5;
}
echo "<p>Total so far: $hp</p>";
echo "</br>";
}
?>
This is a PHP code. When I run it, it works fine. However, when I change it to this code below it doesn't.
<?php
$hp = 50;
while($hp > 1) {
$flip = rand(0,2);
if ($flip == 1) {
echo "<p>X-Ray</p>";
$hp -= 15;
} elseif ($flip == 2) {
echo "<p>Special Move</p>";
$hp -= 10;
} else {
echo "<p>Punch</p>";
$hp -= 5;
}
echo "<p>Total so far: $hp</p>";
echo "</br>";
}
?>
Please help. tHE CHANGES I MADE ARE THE HIGHLIGHTED ONES.
You never created $hp properly in the second version:
50;
doesn't do anything. It just tells php "here, have a 50", and php goes "gee, thanks, ok, whatever" and moves onwards. Then you have
while($hp > 1) {
Since $hp is undefined, it's null, and the code parses/executes as:
while($hp > 1) {
while(null > 1) {
while(0 > 1) {
FALSE -> exit loop
You never created $hp properly in the second version:
50;
If you do change it to $hp = 50;

If value is greater/lesser than xyz

I have a value as a number. For instance, 502.
I want to write a php if statement that will display some text if the value is lesser or greater than certain numbers, or between a range.
E.g.
number is 502, text will say: "Between 500-600"
number is 56, text will say: "Between 0-60"
etc.
So far I have this:
<?php $count=0;?>
<?php $board = getUserBoard($userDetails['userId']);?>
<?php if(is_array($board)):?>
<?php $boardCount = count($board);?>
<?php foreach($board as $key=>$value):?>
<?php
$boardPin = getEachBoardPins($value->id);
$count = $count + count($boardPin);
?>
<?php endforeach?>
<?php endif?>
And that gives me a number:
<?php echo $count;?>
I have tried writing...
<?php if(($count)): => 500 ?>
Over 500
<?php endif ?>
But I keep running into errors.
I'd like to create a list if possible with elseif statements denoting various number ranges.
E.g.
0-50, 51-250, 251-500 etc.
Can anyone help me?
Thanks.
The sanest, neatest and most widely used syntax for if conditions in PHP is:
if($value >=500 && $value <=600 )
{
echo "value is between 500 and 600";
}
if ($count >= 0 && $count < 100) {
echo 'between 0 et 99';
} elseif ($count < 199) {
echo 'between 100 and 199';
} elseif { ...
}elseif ($count < 599) {
echo 'between 500 and 599';
} else {
echo 'greater or equal than 600';
}
I wrote something like this a few years back (might be a better way to do it):
function create_range($p_num, $p_group = 1000) {
$i = 0;
while($p_num >= $i) {
$i += $p_group;
}
$i -= $p_group;
return $i . '-' . ($i + $p_group - 1);
}
print 'The number is between ' . create_range(502, 100) . '.';
It'll say 500-599, but you can adjust it to your needs.
I'm not sure what you need, but here is what I understand you ask:
function getRange($n, $limit = array(50, 250, 500)) { // Will create the ranges 0-50, 51-250, 251-500 and 500-infinity
$previousLimit = 0;
foreach ($limits as $limit) {
if ($n < $limit) {
return 'Between ' . ($previousLimit + 1) . ' and ' . $limit; //Return whatever you need.
}
$previousLimit = $limit;
}
return 'Greater than ' . $previousLimit; // Return whatever you need.
}
echo getRange(56); // Prints "Between 51 and 250"
echo getRange(501); // Prints "Greater than 500"
echo getRange(12, array(5, 10, 15, 20)); // Prints "Between 11 and 15"
function getRange($number){
$length=strlen($number);
$length--;
$r1=round($number,-$length);
if ($r1>$number){
$r2=$r1-pow(10,$length);
return ''.$number.' value is between '.$r2.'-'.$r1;
}
else {
$r2=$r1+pow(10,$length);
return ''.$number.' value is between '.$r1.'-'.$r2;
}
}
Try this.

PHP Echo a number using else if and greater than or less than

I have a script which is like a whois database. This function returns site views and I want to echo between value.
How can I echo and return one result? If the number is say 4000, it should return only 1k-10k
Rows are like
1550330
1000000
The code:
$siteTotalViews=1000000;
if($siteTotalViews <= 100){
echo '0-100';
}
if($siteTotalViews <= 1000){
echo '100-1k';
}
if($siteTotalViews <= 10000){
echo '1k-10k';
}
if($siteTotalViews <= 100000){
echo '10k-100k';
}
if($siteTotalViews <= 1000000){
echo '100k-1 mil';
}
if($siteTotalViews <= 2000000){
echo '1 mil-2 mil';
}
if($siteTotalViews <= 5000000){
echo '2 mil-5 mil';
}
if($siteTotalViews <= 10000000){
echo '5 mil-10 mil';
}
if($siteTotalViews >= 10000000){
echo '10 mil +';
}
Quick fix:
$siteTotalViews=1000000;
if($siteTotalViews <= 100){
echo '0-100';
}
//next else is new
else if($siteTotalViews <= 1000){
echo '100-1k';
}
//next else is new
else if($siteTotalViews <= 10000){
echo '1k-10k';
}
//next else is new
else if($siteTotalViews <= 100000){
echo '10k-100k';
}
Better fix:
$names=array(
100 => '0-100',
1000 => '100-1k',
10000 => '1k-10k',
...
}
foreach ($names as $count=>$name)
if ($siteTotalViews<$count) break;
echo $name;
You could create a function that return the interval. When the function hit the return statement it stops executing, so you will only get one value back. Then you can call the function and echo the result:
function getInterval($siteTotalViews) {
if($siteTotalViews <= 100){
return '0-100';
}
if($siteTotalViews <= 1000){
return '100-1k';
}
...
}
echo getInterval(1000);
You could put all the limits and their corresponding text into an array and then loop over the reverse array to find the appropriate output. (breaking the loop when a limit has been hit)
$siteTotalViews=1000000;
$outputs = array(
0 => '0-100',
100 => '100-1k',
1000 => '1k-10k',
10000 => '10k-100k',
100000 => '100k-1 mil',
1000000 => '1 mil-2 mil',
2000000 => '2 mil-5 mil',
5000000 => '5 mil-10 mil',
10000000 => '10 mil +' );
$outputs = array_reverse($outputs);
foreach ($outputs as $limit => $text) {
if ($siteTotalViews >= $limit) {
echo $text;
break;
}
}
$siteTotalViews=1000000;
if($siteTotalViews >= 0 && $siteTotalViews <=100 ){
echo '0-100'; }
if($siteTotalViews >=101 && $siteTotalViews <= 1000){
echo '100-1k'; }
.....
if($siteTotalViews >= 10000000){
echo '10 mil +'; }

error in php program

I am just a beginner in PHP. I have tried to write a program for prime numbers, but the result is not correct. I couldn't find the error. How can I correct this? Here is my code:
<?php
$n=15;
for($i=2; $i<=$n; $i++)
{
echo "<br />";
for($j=2; $j<=$i-1; $j++)
{
$k=$i%$j;
if($k==0)
{
break;
}
else echo $i."is prime";
break;
}
}
?>
Try this:
<?php
$n=15;
for($i=2; $i<=$n; $i++)
{
$k = 1; //assume that it is prime
for($j=2; $j<$i; $j++) //if $i is 2, then it won't enter the loop as it will not match the condition ($j<$i)
{
$k=$i%$j;
if($k==0)
break; //if not prime, $k will be set as 0. So, break.
}
if($k!=0) // if $k <> 0, then it is prime
echo "<br />" . $i." is prime";
}
?>
Edit
Updated the code to take care of the "2"
Try this:(whitout using loop)
function is_prime($p) {
return ($p > 1) && (($p%2 >= 1) && ($p%3 >= 1) && ($p%5 >= 1)) || in_array($p, [2,3,5]);
}
echo is_prime(15);
You are breaking the loop the first time it's run by calling this basically:
if (something) {
break;
} else {
break;
}
it will break no matter what. you need to take out the last break.
Well, your code is kind of confusing to understand; at first glance it seems as if it's trying to determine primality by checking every divisor up to N, but you've got that outer-loop going on which I didn't see at first... Oh boy.
If you're just trying to figure out if some number N is prime, the following should work:
$n = 15
$prime = true;
for ($i = 2; $i < sqrt($n); $i++) {
if ($n % $i == 0) {
$prime = false;
break;
}
}
echo $n . " is " . ($prime ? "" : "not") . " prime.";
<?php
echo "TEST\r\n";
$n=15;
for($i=2; $i<=$n; $i++)
{
echo "I= $i \r\n";
for($j=2; $j<=$i-1; $j++)
{
$k = $i%$j;
if($k==0)
{
break;
} else {
echo $i."is prime \r\n";
}
break;
}
}
I think your secod for loop is incorrect.
for($i=2; $i<=$n; $i++) {
echo "<br />";
for($j=2; $j<=$i-1; $j++) {
...
The first value for $j is 2. And for the first time, the first value for $i is 2 again. Now, look at your second for loop code.
It will be like this at the first time:
for($j=2; $j<=2-1; $j++) ... // for($j=2; $j<=1; $j++)
And this condition is not valid at all: 2<=1

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