PHP - String Replace SyntaxError: illegal character - php

Question

Output for $status
Array
(
[1] => 1
[2] => 0
[3] => 0
[4] => 4
[5] => 4
)
$color_code_string = implode(",",$status);
Ouput
1,0,0,4,4
$color_code_string = str_replace("0","'#F00'",$color_code_string);
$color_code_string = str_replace("1","'#00bcd4'",$color_code_string);
$color_code_string = str_replace("2","'#4caf50'",$color_code_string);
$color_code_string = str_replace("3","'#bdbdbd'",$color_code_string);
$color_code_string = str_replace("4","'#ff9900'",$color_code_string);
Exception
SyntaxError: illegal character
colors: ['#00bcd'#ff9900'','#F00','#F00','#ff9900','#ff9900']
//prints '#00bcd'#ff9900'','#F00','#F00','#ff9900','#ff9900'
How do I achieve expected output as below
'#00bcd','#ff9900','#F00','#F00','#ff9900','#ff9900'

Answer 1

That happens because you are also replacing numbers inside the color codes you replaced before.
Solution: traverse the array to do the replacement before imploding the array of colors:
// Translation table, saves you separate lines of stringreplace calls.
$colorCodes = array(
0 => "#F00",
1 => "#00bcd4",
2 => "#4caf50",
3 => "#bdbdbd",
4 => "#ff9900",
);
// Build an array of colors based on the array of status codes and the translation table.
// I'm adding the quotes here too, but that's up to you.
$statusColors = array();
foreach($status as $colorCode) {
$statusColors[] = "'{$colorCodes[$colorCode]}'";
}
// Last step: implode the array of colors.
$colors = implode(','$statusColors);

Answer 2

$status = [1,0,0,4,4,];
$color_code_string = implode(",",$status);
$replacements = ["0" => "'#F00'","1" => "'#00bcd4'","2" => "'#4caf50'","3" => "'#bdbdbd'","4" => "'#ff9900'",];
$color_code_string = strtr($color_code_string, $replacements);
echo $color_code_string;

Answer 3

There is a big Caution notice about your problem in the str_replace() documentation:
Caution
Replacement order gotcha
Because str_replace() replaces left to right, it might replace a previously inserted value when doing multiple replacements. See also the examples in this document.
Use strtr() instead, because str_replace() will overwrite previous replacements
$status = [
1,
0,
0,
4,
4,
];
$color_code_string = implode(",",$status);
$replacements = [
"0" => "'#F00'",
"1" => "'#00bcd4'",
"2" => "'#4caf50'",
"3" => "'#bdbdbd'",
"4" => "'#ff9900'",
];
$color_code_string = strtr($color_code_string, $replacements);
echo $color_code_string;

Answer 4

<?php
$color_code = array(1, 0, 0, 4, 4);
array_walk($color_code, 'color_code_replace');
$color_code_string = implode(",",$color_code);
function color_code_replace(&$cell) {
switch ($cell) {
case 0 : {
$cell = '#F00';
break;
}
case 1 : {
$cell = '#00bcd4';
break;
}
case 2 : {
$cell = '#4caf50';
break;
}
case 3 : {
$cell = '#bdbdbd';
break;
}
case 4 : {
$cell = '#ff9900';
break;
}
default : {
throw new Exception("Unhandled Color Code");
}
}
}
var_dump($color_code);