I am using the code below to return value from sql but the value is displayed 2 times.
$cc=mysqli_connect($server,$user,$pass);
mysqli_select_db($cc,$database);
$sql = "SELECT b_id FROM ``ub_per`` WHERE ``b_email`` = '$mail'";
$res = mysqli_query($cc,$sql);
$row = mysqli_fetch_array($res);
foreach($row as $value){
echo($value);
}
I think the answer is a little more complex than that.
So the row $row = mysqli_fetch_array($res); will return an array, I think if you check there will be 2 items in it.
Looking like this
$row[0] = id;
$row['b_id'] = id;
now you do
foreach($row as $value){
echo($value);
}
So will echo id out twice.
Use
$row = mysqli_fetch_array($res,MYSQLI_ASSOC);
To get you what you want.
It is because query gives you 2 results(rows).
Try:
echo '<pre>';
print_r($row);
And you will see if there are more than 1 rows in results.
Related
I would like to check if a given value exists in a mysql table. If yes; I would like to get the value of another column of that row.
Now I have:
$teinsertengetal=$_GET['getal'];
// start
$i = 0;
$ikhadingezetArray = array();
$result = $conn->query("SELECT getal, hoevaakingezet FROM ingezettegetallen");
while ($row = mysqli_fetch_assoc($result))
{
$ikhadingezetArray[$i]['getallen'] = $row['getal'];
$ikhadingezetArray[$i]['hoevaakingezets'] = $row['hoevaakingezet'];
$i++;
}
foreach($ikhadingezetArray as $value)
{
echo $value . "<br>";
}
My problem is that the foreach only echos "Array", not the values within the array.
And then I have to check if $teinsertengetal is in the array (the field "getal" in $ikhadingezetArray). If yes; I want the value of "hoevaakingezet" from the same row number of the array.
I hope you understand what I mean. Maybe it's not the best way I could do this?
Thank you in advance!
edit: the echo is just to check if the right values were inserted in the array.
For example:
Table "ingezettegetallen"
getal
hoevaakingezet
6
2
48
4
$teinsertengetal = 48
Now I would like check if 48 is in the column "getal". If yes (and it is in this example) I would like to store the value "4" in a variable (like $hoevaakingezetdus).
Put the check in the query, rather than fetching the entire table.
$stmt = $conn->prepare("
SELECT hoevaakingezet
FROM ingezettegetallen
WHERE getal = ?");
$stmt->bind_param("s", $teinsertengetal);
$stmt->execute();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
echo $row['hoevaakingezet'] . "<br>";
}
I am trying to query a db for an entire column of data, but can't seem to get back more than the first row.
What I have so far is:
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_fetch_array($medicationItemObj, MYSQLI_NUM)){
echo count($row);
}
It's not my intention to just get the number of rows, I just have that there to see how many it was returning and it kept spitting out 1.
When I run the sql at cmd line I get back the full result. 6 items from 6 individual rows. Is mysqli_fetch_array() not designed to do this?
Well, I had a hard time understanding your question but i guess you are looking for this.
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_num_rows($medicationItemObj))
{
echo $row;
}
Or
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
$i = 0;
while ($row = mysqli_fetch_array($medicationItemObj))
{
$medicationItem[] = $row[0];
$i++;
}
echo "Number of Rows: " . $i;
If you just want the number of rows i would suggest using the first method.
http://php.net/manual/en/mysqli-result.num-rows.php
You can wrote your code like below
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
while ($row = mysqli_fetch_assoc($medicationItemObj))
{
echo $row['medication'];
}
I think this you want
You could give this a try:
$results = mysqli_fetch_all($medicationItemObj, MYSQLI_NUM);
First, I would use the object oriented version of this and always use prepared statements!
//prepare SELECT statement
$medicationItemSQL=$connection->prepare("SELECT medication FROM medication");
// execute statement
$medicationItemSQL->execute();
//bind results to a variable
$medicationItemSQL->bind_result($medication);
//fetch data
$medicationItemSQL->fetch();
//close statement
$medicationItemSQL->close();
You can use mysqli_fetch_assoc() as below.
while ($row = mysqli_fetch_assoc($medicationItemObj)) {
echo $row['medication'];
}
I am trying to get the matched rows from a table and save it in a Global Array so that I can use it in different functions.
But when I do print_r of that array it shows only last row.
Here is my code
function setCampoFeed()
{
echo $sql = "SELECT campofeed.tag,campofeed.registro,campofeed.valor FROM campofeed ".
"INNER JOIN registrofeed ON registrofeed.id = campofeed.registro ".
"WHERE registrofeed.feed='".$this->idFeed."'";
$result= $this->localDb->execute($sql);
$this->campoFeed= mysql_fetch_array($result))
}
So here campoFeed is the array that should have all the rows of the match, but now its just having the last row.
Thanks in advance
Use
$this->campoFeed[] = mysql_fetch_array($result);"
insted of
$this->campoFeed= mysql_fetch_array($result);
You will get all data in array
Try this one if it works for you..
$resultArray = array();
$campoFeed = array();
$resultArray = mysql_fetch_array($result);
foreach($resultArray as $key => $value){
$campoFeed[$key] = $value;
}
print_r($campoFeed);
Use this
$mergedArray=array();
while($data= mysql_fetch_array($result)) {
$final_array = unserialize($data['data']);
$mergedArray=array_merge($mergedArray,$final_array);
}
array_unique($mergedArray, SORT_REGULAR);
I know this may sound like a stupid question from a programming-newbie, but I just want to make sure I understand correctly.
After a query, what does $row[0] stand for/ result in?
Is my understanding correct that $row[0] shows ALL results?
HERE ARE EXAMPLES:
$query = "SELECT count(commentid) from comments where jokeid = $jokeid";
$result = mysql_query($query);
$row=mysql_fetch_array($result);
if ($row[0] == 0)
{
echo "No comments posted yet. \n";
} else
{
echo $row[0] . "\n";
echo " comments posted. \n";
AND THIS ONE
$query = "Select count(prodid) from products where catid = $catid";
$result = mysql_query($query);
$row = mysql_fetch_array($result);
if ($row[0] == 0)
{
echo "<h2><br>Sorry, there are no products in this category</h2>\n";
}
else
{
$totrecords = $row[0];
Thanks in advance.
$row[0] will simply echo the first column in your database.
0 is the first because all arrays in PHP (and in most programming languages) are zero-based - they simply start with zero.
$row[0] will be the value of the first column in your results. If you use mysql_fetch_assoc($result) you will have an array in the form:
array(column_name => column_value);
e.g.
$row = mysql_fetch_asssoc($result);
$value_column_1 = $row['column_1'];
You can also use mysql_fetch_object($result) to get an object with column names as the parameters.
$row = mysql_fetch_object($result);
$value = $row->column_name
mysql_fetch_array() takes the next (in your examples first) row out of the resultset and stores the data in an array $row.
$row[0] now represents the first value of that row.
So in total in your examples the variable holds the first value of the first row of your resultset.
I have a problem iterating through an sql query:
$result = mysql_query("SELECT * FROM transactions");
while($row = mysql_fetch_array($result)) {
// this returns 3 rows
foreach ($row as $values)
{
//fputcsv($a_csv, $values;
echo $values;
}
}
The script iterates fine but it appears to be going through each row twice. So what I receive in output is the following:
value1value1value2value2value3value3
I'm not sure why this is - could anyone explain please?
Thankyou
mysql_fetch_array fetches both the named & the numerical keys. Use either mysql_fetch_assoc or mysql_fetch_row.
$result = mysql_query("SELECT * FROM transactions");
//return an associative array
while($row = mysql_fetch_assoc($result)) {
// this returns 3 rows
$values = "{$row["name_of_column1"]}, {$row["name_of_column2"]}, {$row["name_of_column3"]}";
//fputcsv($a_csv, $values;
//print the whole row array
print_r($row);
//echo value in format value1, value2, value3
echo $values;
}
You need to access $row like this $row[0] And $row shouldn't be in a foreach() itself unless it too is some kind of array you need to iterate through.
$result = mysql_query("SELECT * FROM transactions");
while($row = mysql_fetch_row($result))
{
echo $row[0];
echo $row[1];
// ... etc.
}