Check if given value exists in array or mysql table - php

Question

I would like to check if a given value exists in a mysql table. If yes; I would like to get the value of another column of that row.
Now I have:
$teinsertengetal=$_GET['getal'];
// start
$i = 0;
$ikhadingezetArray = array();
$result = $conn->query("SELECT getal, hoevaakingezet FROM ingezettegetallen");
while ($row = mysqli_fetch_assoc($result))
{
$ikhadingezetArray[$i]['getallen'] = $row['getal'];
$ikhadingezetArray[$i]['hoevaakingezets'] = $row['hoevaakingezet'];
$i++;
}
foreach($ikhadingezetArray as $value)
{
echo $value . "<br>";
}
My problem is that the foreach only echos "Array", not the values within the array.
And then I have to check if $teinsertengetal is in the array (the field "getal" in $ikhadingezetArray). If yes; I want the value of "hoevaakingezet" from the same row number of the array.
I hope you understand what I mean. Maybe it's not the best way I could do this?
Thank you in advance!
edit: the echo is just to check if the right values were inserted in the array.
For example:
Table "ingezettegetallen"
getal
hoevaakingezet
6
2
48
4
$teinsertengetal = 48
Now I would like check if 48 is in the column "getal". If yes (and it is in this example) I would like to store the value "4" in a variable (like $hoevaakingezetdus).

Answer 1

Put the check in the query, rather than fetching the entire table.
$stmt = $conn->prepare("
SELECT hoevaakingezet
FROM ingezettegetallen
WHERE getal = ?");
$stmt->bind_param("s", $teinsertengetal);
$stmt->execute();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
echo $row['hoevaakingezet'] . "<br>";
}