I'm struggling to figure out how I can use this SQL with eloquent methods.
SELECT * FROM artists WHERE artists.id NOT IN
(SELECT artist_id FROM artist_issues WHERE issue = 'update_images')
I see that the "whereNotIn" method takes a column, and then an array as the second parameter, so it's not possible to pass a subquery.
Any ideas how I could do this?
Thanks.
Assuming you have the correct relationships set, it should be something like this:
$artists = Artist::whereHas('artist_issues', function(q) {
$q->where('issue', '<>', 'update_images');
});
I guess you have something like this in your Artist model:
public function artist_issues()
{
return $this->belongsTo('App\ArtistIssue');
}
Related
Problem
I've spent the last few hours looking for a solution for this and can't seem to find anything that works. I'm trying to load all Routes that have at least one assigned Aircraft that is currently at the departure airport of the route, like this:
Route::has('availableAircraft');
The availableAircraft relationship on Route currently looks like this, with the issue stemming from not being able to find a way to inject the Route into the final where clause (see ROUTE_ID_HERE).
// Route.php
/**
* This returns all assigned aircraft that are not allocated to jobs and are at the departure airport of the route
*/
public function availableAircraft()
{
return $this->belongsToMany(
Aircraft::class, 'aircraft_route_assignments', 'route_id', 'aircraft_id')
->whereNull('current_job_id')
->where('current_airport_id', 'ROUTE_ID_HERE');
}
Raw SQL
I can perform this query using raw SQL, but I can't find a way to replicate this in Eloquent:
select
count(*) as aggregate
from
`routes`
where (
select
count(*)
from
`aircraft`
inner join `aircraft_route_assignments` on `aircraft`.`id` = `aircraft_route_assignments`.`aircraft_id`
where
`routes`.`id` = `aircraft_route_assignments`.`route_id`
and `current_job_id` is null
and `current_airport_id` = `routes`.`departure_airport_id`
) > 0
and `routes`.`deleted_at` is null
The crucial part here is the final and 'current_airport_id' = 'routes'.'departure_airport_id', which I can't seem to find a way to replicate in the query builder.
What I've Tried
I've tried to manually specify the field, like in the SQL query as so, but the actual SQL generated by this uses 'routes.departure_airport_id' as a literal string and so returns no results:
// Route.php
/**
* This returns all assigned aircraft that are not allocated to jobs and are at the departure airport of the route
*/
public function availableAircraft()
{
return $this->belongsToMany(
Aircraft::class, 'aircraft_route_assignments', 'route_id', 'aircraft_id')
->whereNull('current_job_id')
->where('current_airport_id', '`routes`.`departure_airport_id`');
}
Am I vastly over-thinking this?
Try this as your eloquent query:
Route::whereHas('availableAircraft', function (Builder $query) {
$query->whereNull('current_job_id')
->whereRaw('current_airport_id = `routes`.`departure_airport_id`');
})->get();
And change your model to this:
public function availableAircraft()
{
return $this->belongsToMany(
Aircraft::class, 'aircraft_route_assignments', 'route_id', 'aircraft_id');
}
I solved this by adapting Mahdi's answer to use whereRaw instead of where in the whereHas subquery. So the final Eloquent query looks like:
Route::whereHas('availableAircraft', function (Builder $query) {
$query->whereNull('current_job_id')
->whereRaw('current_airport_id = `routes`.`departure_airport_id`');
})->get()
I have two tables website_link and website_links_type. website_link is related website_links_type with hasmany relationship.
$this->website_links->where('id',1)->Paginate(10);
and relationship
public function broken()
{
return $this->hasMany('App\Website_links_type')->where('status_code','!=',"200");
}
Now I want to get result from website_link table but Orderby that result on count of broken relationship result.
There are many ways to solve this problem. In my answer I'll use two I know.
You can eagerload your relationship and use the function sortBy(). However I don't think you can use the paginate() functionality with this solution.
Example:
$results = Website_link::with('website_links_type')->get()->sortBy(function ($website_link) {
return $website_link->website_links_type->count();
});
See this answer
You can also use raw queries to solve this problem. With this solution you can still use the pagination functionality (I think).
Example:
$results = Website_link
::select([
'*',
'(
SELECT COUNT(*)
FROM website_links_type
WHERE
website_links_type.website_link_id = website_link.id
AND
status_code <> 200
) as broken_count'
])
->orderBy('broken_count')
->paginate(10);
You may have to change the column names to match your database.
You can not put WHERE condition in model file.
You just give relationship hasMany in model file.
And use where condition in controller side.
Refer this document.
Try this
Model file:
public function broken()
{
return $this->hasMany('App\Website_links_type');
}
Controller file:
$model_name->website_links->where('id',1)
->where('status_code','!=',"200")
->orderBy('name', 'desc')
->Paginate(10);
I got this query:
$users = DB::table('users')->whereExists(function($query)
{
$query->select(DB::raw(1))
->from('galleries')
->whereRaw('galleries.user_id = users.id');
})->get();
This query selects all users who have gallery. Problem is that I can't use eloquent releationships now. Whenever i try to loop like this:
#foreach ($user->gallery as $gallery)
{{$gallery->name}}
#endforeach
I get error:
Undefined property: stdClass::$gallery
It happens with all other tables. What am I doing wrong here? My realationships are defined and they work just fine, i got problems only in this query. Thanks.
EDIT
Since it's not eloquent query, could you show me example how to write query, into few tables with eloquent. For example, I need all users who have their status approved in example table
First, determine a relationship in the User class, like this:
class User {
// Determine relation to Example table
public function examples() {
return $this->hasMany('Example', 'user_id', 'id'); // second parameter is the foreign key
}
}
Then the query:
User::whereHas('examples', function( $query ) {
$query->where('status','approved');
})->get();
In my Database, I have:
tops Table
posts Table
tops_has_posts Table.
When I retrieve a top on my tops table I also retrieve the posts in relation with the top.
But what if I want to retrieve these posts in a certain order ?
So I add a range field in my pivot table tops_has_posts and I my trying to order by the result using Eloquent but it doesn't work.
I try this :
$top->articles()->whereHas('articles', function($q) {
$q->orderBy('range', 'ASC');
})->get()->toArray();
And this :
$top->articles()->orderBy('range', 'ASC')->get()->toArray();
Both were desperate attempts.
Thank you in advance.
There are 2 ways - one with specifying the table.field, other using Eloquent alias pivot_field if you use withPivot('field'):
// if you use withPivot
public function articles()
{
return $this->belongsToMany('Article', 'tops_has_posts')->withPivot('range');
}
// then: (with not whereHas)
$top = Top::with(['articles' => function ($q) {
$q->orderBy('pivot_range', 'asc');
}])->first(); // or get() or whatever
This will work, because Eloquent aliases all fields provided in withPivot as pivot_field_name.
Now, generic solution:
$top = Top::with(['articles' => function ($q) {
$q->orderBy('tops_has_posts.range', 'asc');
}])->first(); // or get() or whatever
// or:
$top = Top::first();
$articles = $top->articles()->orderBy('tops_has_posts.range', 'asc')->get();
This will order the related query.
Note: Don't make your life hard with naming things this way. posts are not necessarily articles, I would use either one or the other name, unless there is really need for this.
For Laravel 8.17.2+ you can use ::orderByPivot().
https://github.com/laravel/framework/releases/tag/v8.17.2
In Laravel 5.6+ (not sure about older versions) it's convenient to use this:
public function articles()
{
return $this->belongsToMany('Article', 'tops_has_posts')->withPivot('range')->orderBy('tops_has_posts.range');
}
In this case, whenever you will call articles, they will be sorted automaticaly by range property.
In Laravel 5.4 I have the following relation that works fine in Set model which belongsToMany of Job model:
public function jobs()
{
return $this->belongsToMany(Job::class, 'eqtype_jobs')
->withPivot(['created_at','updated_at','id'])
->orderBy('pivot_created_at','desc');
}
The above relation returns all jobs that the specified Set has been joined ordered by the pivot table's (eqtype_jobs) field created_at DESC.
The SQL printout of $set->jobs()->paginate(20) Looks like the following:
select
`jobs`.*, `eqtype_jobs`.`set_id` as `pivot_set_id`,
`eqtype_jobs`.`job_id` as `pivot_job_id`,
`eqtype_jobs`.`created_at` as `pivot_created_at`,
`eqtype_jobs`.`updated_at` as `pivot_updated_at`,
`eqtype_jobs`.`id` as `pivot_id`
from `jobs`
inner join `eqtype_jobs` on `jobs`.`id` = `eqtype_jobs`.`job_id`
where `eqtype_jobs`.`set_id` = 56
order by `pivot_created_at` desc
limit 20
offset 0
in your blade try this:
$top->articles()->orderBy('pivot_range','asc')->get();
If you print out the SQL query of belongsToMany relationship, you will find that the column names of pivot tables are using the pivot_ prefix as a new alias.
For example, created_at, updated_at in pivot table have got pivot_created_at, pivot_updated_at aliases. So the orderBy method should use these aliases instead.
Here is an example of how you can do that.
class User {
...
public function posts(): BelongsToMany {
return $this->belongsToMany(
Post::class,
'post_user',
'user_id',
'post_id')
->withTimestamps()
->latest('pivot_created_at');
}
...
}
You can use orderBy instead of using latest method if you prefer. In the above example, post_user is pivot table, and you can see that the column name for ordering is now pivot_created_at or pivot_updated_at.
you can use this:
public function keywords() {
return $this->morphToMany(\App\Models\Keyword::class, "keywordable")->withPivot('order');
}
public function getKeywordOrderAttribute() {
return $this->keywords()->first()->pivot->order;
}
and append keyword attribiute to model after geting and use sortby
$courses->get()->append('keyword_order')->sortBy('keyword_order');
I have a problem with the toArray() method in Doctrine. Its doesn't get my relations:
First query :
$q = Doctrine::getTable('posts')->find(1);
debug($q->toArray(true));
Print the postid=1 with out the relations
$q = Doctrine::getTable('posts')->find(1);
$q->Tags->toArray();
debug($q->toArray(true));
...prints the results with tag relation.
But i want to do:
Doctrine::getTable('posts')->findAll()->toArray(true);
...and get all of relations of posts , instead I got an array of post row.
Any idea about how to make it work with the relations?
(notice i added toArray(true) for deep property.
thanks for any help
You could create named query for this table with all relations attached:
Doctrine::getTable('posts')->addNamedQuery('get.by.id.with.relations', 'DQL here...');
And then just use something like this:
Doctrine::getTable('posts')->find('get.by.id.with.relations', array(123));
I beleive you need to do a Join with the query. Otherwise it doesnt hydrate the realated data.
$q = Doctrine_Query::create()
->from('Post p')
->leftJoin('p.RelatedModel1 rm1')
->leftJoin('p.RelatedModel2 rm2');
$q->findAll()->toArray(true);
$q = Doctrine_Query::create()
->from('Post p')
->leftJoin('p.RelatedModel1 rm1')
->leftJoin('p.RelatedModel2 rm2');
$q->findAll()->toArray(true);
Can i Add ->limit()->offset()
to the query ?
I guss that if i first create the query then findAll will act the same as execute right ?