Hello I have a simple script
This is my script, and try this script
<?php
$user_id = $_REQUEST['user_id'];
$pid = $_REQUEST['pid'];
$nopr = $_REQUEST['nopr'];
$tglpr = $_REQUEST['tglpr'];
$uraianpr = $_REQUEST['uraianpr'];
$jenispr = $_REQUEST['jenispr'];
$nilaipr = $_REQUEST['nilaipr'];
$costproject = $_REQUEST['costproject'];
$remarkpr = $_REQUEST['remarkpr'];
$tmpattachid = $_REQUEST['tmpattachid'];
if ($user_id==NULL)
{
$error "User Id Not Complete";
}
else if ($pid==NULL)
{
$error= "PID Not Complete";
}
echo $error;
?>
I want if $user_id or other variables is empty/null
i confused when other variable have empty/null data
i must typing code many if statement :(
example : 5 variables ($pid,$nopr,$tglpr,$jenispr,$costproject) is empty/null
this show error like this
PID Not Complete
NoPR Not Complete
Tgl Pr Not Complete
Jenis Pr Not Complete
Cost Project Not Complete
Help Me, Thank's.
I won't give you the full answer, as stated in comments, this is a basic basic concept you need to learn, but I will show you the template.
You want to use a FOREACH loop to check each value in the array. See http://php.net/manual/en/control-structures.foreach.php
And Set it out like this:
foreach($_REQUEST as $key=>$row){
if (is_null($row) || empty($row)){
$errorText .= "You have no data in your ".$key."<br>";
}
}
unset($key,$row);
Then you can output the $errorText value telling people which rows should be fixed. Easy.
Loop through the $_REQUEST and find the empty or null key.
CODE :
foreach ($_REQUEST as $key => $value) {
if(trim($value) ==='' || is_null($value))
{
echo $key . " is not complete" . "<br/>";
}
}
Related
I need to check the words received from the database with the user's entered word and if there is a match, then output its value from the database, and if not, then output what the user entered.
The code below works fine if there is a match.
function d_typeplace_morf($d_typeplace)
{
global $wpdb;
$typeplace_results = $wpdb->get_results('SELECT vozmozhnyi_variant_mesta, ego_slovoforma_v_predlozhnom_padezhe FROM dEzpra_jet_cct_tip_mest_obrabotki');
if ($typeplace_results) {
foreach ($typeplace_results as $typeplace_result) {
$d_typeplace_raw = mb_strtolower($typeplace_result->vozmozhnyi_variant_mesta);
$d_typeplace_morf = mb_strtolower($typeplace_result->ego_slovoforma_v_predlozhnom_padezhe);
$d_typeplace = mb_strtolower($d_typeplace);
if (stripos($d_typeplace, $d_typeplace_raw) !== false) {
echo $d_typeplace_morf;
}
}
}
}
I'm an amateur in PHP, just learning. And I can't figure out how to output $d_typeplace if no match is found.
I tried to add
else {
echo $d_typeplace;
}
, but I get an array of words from the user entered.
I will be grateful for any help. Also for any suggestions for improving this code.
---Addition---
I apologize for my English. This is a problem in the Russian language, I need to take into account the morphology. To do this, the database has a list of words and their analog, for example, X = Y. I get these words and compare what the user entered. If he entered X, then we output Y. If he led Z, which is not in the database, then we output Z.
Thus, we check $d_typeplace with $d_typeplace_raw and if there is a match, we output $d_typeplace_morf, which is equal to $d_typeplace_raw. And if not, then $d_typeplace (it contains the value that the user entered).
Oh, I'm sorry, I understand myself that I'm explaining stupidly)
I cannot quite understand what you are asking: you need to output the string entered by the user, but you can only print an array?
If this is the case, I think you parsed the string before, in order to therefore you need to do join again the values contained in the array.
Try with:
else {
echo implode(" ", $d_typeplace);
}
--- EDITED ---
Try with:
function d_typeplace_morf($d_typeplace)
{
global $wpdb;
$typeplace_results = $wpdb->get_results('SELECT vozmozhnyi_variant_mesta, ego_slovoforma_v_predlozhnom_padezhe FROM dEzpra_jet_cct_tip_mest_obrabotki');
if ($typeplace_results) {
$found = false;
foreach ($typeplace_results as $typeplace_result) {
$d_typeplace_raw = mb_strtolower($typeplace_result->vozmozhnyi_variant_mesta);
$d_typeplace_morf = mb_strtolower($typeplace_result->ego_slovoforma_v_predlozhnom_padezhe);
$d_typeplace = mb_strtolower($d_typeplace);
if (stripos($d_typeplace, $d_typeplace_raw) !== false) {
echo $d_typeplace_morf;
$found = true;
break;
}
}
if (!$found) {
echo $d_typeplace;
}
}
}
But I think it would be more efficient, if you implemented the second code snippet written by #Luke.T
I'm presuming you were trying to add the else like this?
function d_typeplace_morf($d_typeplace)
{
global $wpdb;
$typeplace_results = $wpdb->get_results('SELECT vozmozhnyi_variant_mesta, ego_slovoforma_v_predlozhnom_padezhe FROM dEzpra_jet_cct_tip_mest_obrabotki');
if ($typeplace_results) {
foreach ($typeplace_results as $typeplace_result) {
$d_typeplace_raw = mb_strtolower($typeplace_result->vozmozhnyi_variant_mesta);
$d_typeplace_morf = mb_strtolower($typeplace_result->ego_slovoforma_v_predlozhnom_padezhe);
$d_typeplace = mb_strtolower($d_typeplace);
if (stripos($d_typeplace, $d_typeplace_raw) !== false) {
echo $d_typeplace_morf;
} else {
echo $d_typeplace;
}
}
}
}
Which was outputting an array because the for loop was continuing, if you add a break like so...
echo $d_typeplace;
break;
It should stop outputting an array. Depending on your use case you could however perform similar functionality directly in your sql query using LIKE ...
function d_typeplace_morf($d_typeplace)
{
global $wpdb;
$typeplace_results = $wpdb->get_results('
SELECT ego_slovoforma_v_predlozhnom_padezhe
FROM dEzpra_jet_cct_tip_mest_obrabotki
WHERE vozmozhnyi_variant_mesta LIKE %' . $d_typeplace . '%');
if ($typeplace_results) {
//Echo result
} else {
echo $d_typeplace;
}
}
Im writing a page in HTML/PHP that connects to a Marina Database(boats,owners etc...) that takes a boat name chosen from a drop down list and then displays all the service that boat has had done on it.
here is my relevant code...
if(isset($_POST['form1'])){//if there was input data submitted
$form1 = $_POST['form1'];
$sql1 = 'select Status from ServiceRequest,MarinaSlip where MarinaSlip.SlipID = ServiceRequest.SlipID and BoatName = "'.$form1.'"';
$form1 = null;
$result1 = $conn->query($sql1);
$test = 0;
while ($row = mysqli_fetch_array($result1, MYSQLI_ASSOC)) {
$values1[] = array(
'Status' => $row['Status']
);
$test = 1;
}
echo '<p>Service Done:</p><ol>';
if($test = 1){
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
echo '</ol>';
}else{
echo 'No service Done';
}
the issue im having is that some of the descriptions of sevice are simply Open which i do not want displayed as service done, or there is no service completed at all, which throws undefined variable: values1
how would I stop my script from adding Open to the values1 array and display a message that no work has been completed if values1 is empty?
Try this
$arr = array();
if (empty($arr))
{
echo'empty array';
}
We often use empty($array_name) to check whether it is empty or not
<?php
if(!empty($array_name))
{
//not empty
}
else
{
//empty
}
there is also another way we can double sure about is using count() function
if(count($array_name) > 0)
{
//not empty
}
else
{
//empty
}
?>
To make sure an array is empty you can use count() and empty() both. but count() is slightly slower than empty().count() returns the number of element present in an array.
$arr=array();
if(count($arr)==0){
//your code here
}
try this
if(isset($array_name) && !empty($array_name))
{
//not empty
}
You can try this-
if (empty($somelist)) {
// list is empty.
}
I often use empty（$arr) to do it.
Try this instead:
if (!$values1) {
echo "No work has been completed";
} else {
//Do staffs here
}
I think what you need is to check if $values1 exists so try using isset() to do that and there is no need to use the $test var:
if(isset($values1))
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
Or try to define $values1 before the while:
$values1 = array();
then check if it's not empty:
if($values1 != '')
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
All you have to do is get the boolean value of
empty($array). It will return false if the array is empty.
You could use empty($varName) for multiple uses.
For more reference : http://php.net/manual/en/function.empty.php
First of all, I know this question already exists and already has answers, but I would like to stress in which way my question is different. I have code like this:
$ognjen=array();
foreach($_POST as $key=>$value){
if($key!='prenos'&& $key!='submit'){
if (strrpos($key, '1', -1)){
if(!empty($_POST[$key])){
$uslov=true;//kontrolna promjenljiva
}else{
$uslov=false;
}
if($uslov==true){
$ognjen[]=$value;
}else{
$_SESSION['message']='You must fill out all fields';
unset($_SESSION['message']);
}
}//ovdje ide elseif
}
}
This code doesn't do what's expected.What I want to achieve is if all values of $_POST are set to put them in $ognjen array,if even one misses, none of them should become part of $ognjen array, but all that inside this foreach loop, because there are some other checkings that need to fulfill. And while searching for answers I couldn't find any that fits to my situation. Please help, I feel that this is pretty simple task to do, but I don't know way to do it.
<?php
function is_blank($data)
{
$error_message="";
foreach ($data as $key => $value)
{
if($value=="" or $value==null)
{
$error_message.=$key.",";
}
}
if($error_message!="")
{
$error_message=substr($error_message, 0,-1);
return $error_message." is cannot be null or empty.";
}
else
{
return "";
}
}
echo is_blank($_POST);
i need help again.
I have to code a function that gets me the cookie. but i only knows part of the cookie name. I got a JavaScript-Function that's working very well:
function readCookie(cookiePart){
var results = document.cookie.match(cookiePart + '(.*)=(.*?)(;|$)');
if(results){
var result = results[0].replace(cookiePart,'');
var cookie= result.split("=");
return(cookie[0])
}else{
return null
}
}
alert(readCookie("cookie_"));
I try to code the same for PHP. But still stuck:
$cookie_name = "cookie_";
if(!isset($_COOKIE["$cookie_name" . "/^*$/"])) {
echo "Cookie named '" . $cookie_name . "' is not set!";
} else {
echo "Cookie '" . $cookie_name . "' is set!<br>";
}
i think i do the regex part wrong. maybe you can help me where to add it? i tried on the varaiablename when define or match, but nothing works.
thx for any hint my friends!
Problem
The thing is, that in JavaScript you used a method .match() for regexp, but you didn't use anything for regexp in PHP.
And you cannot that easily match keys, you can only do this when iterating over entire array.
But you don't have to use regexp to achieve what you need.
Solution
I recommend this:
$set = false;
$cookie_name = 'cookie_';
foreach ($_COOKIE as $name => $value) {
if (stripos($name,$cookie_name) === 0) {
echo "Cookie named '$name' is set with value '$value'!";
$set = true;
}
}
if (!$set) {
echo 'No cookie found :(';
}
Will list all valid cookies (having names beginning with "cookie_"), or display sad message.
And I think that if you can achieve something relatively easy without regex, you should.
If you need to use cookie names afterwards
Use this modified code:
$cookie_name = 'cookie_';
foreach ($_COOKIE as $name => $value) {
if (stripos($name,$cookie_name) === 0) {
$cookies[] = $name;
}
}
And you have now table $cookies that contains names of every valid cookie set. If you need only part that's after _ then use this line instead:
$cookies[] = str_replace('cookie_','',$name);
function keyLike(array $arr, $like)
{
foreach (array_keys($arr) as $k) {
if (preg_match($like, $k)) {
return true;
}
}
return false;
}
...
if (keyLike($_COOKIE, '/^cookie_.+/')) { ...
How do i validate $_GET thats the number coming from correct source.
My url look like : index.php?page=items&catID=5
When users put something like 3 which is doesn't exist on catID. I want it to display error message.
$catID = intval($_GET["catID"]);
if($catID) {
$checkSQL = mysql_query("SELECT * FROM category WHERE category_type='2'");
while($checkROW = mysql_fetch_array($checkSQL)) {
$checkCAT != $checkROW["categoryID"];
echo "err msg";
}
This i can come up so far but it doesn't working as it fire error msg even in correct page.
Thank you
wallk makes a good point, there is a missing if. but if i read this correctly, wouldn't something along the lines of this be more what you are going for? Right now the line:
if($catID) {
is actually only checking if catID (or, catID from the $_GET) is non-zero (not false). My guess if you are looking to check if catID is the categoryID returned from SQL?
$catID = intval($_GET["catID"]);
checkcat($catID);
function checkcat($check_category) {
$checkSQL = mysql_query("SELECT * FROM category WHERE category_type='2'");
while($checkROW = mysql_fetch_array($checkSQL)) {
if ( $check_category != $checkROW["categoryID"] ) {
echo "err msg";
} else {
echo "not an error message";
}
}
}
Expounding on what you are looking for, how about something like this then?
$catID = ($_GET["catID");
if ( !is_numeric($catID) ) {
echo "Not a numeric category!"
} else {
$checkSQLQuery = "SELECT * FROM category WHERE categoryID = '{$catID}' AND category_type='2'"
$resultSQL = mysql_query($checkSQLQuery, $db);
/* NOTE!: Guessing on what your database resouce
pointer is - it isn't included in the origin snippet.
Although, the last opened should be used by default if
this is left out. */
if ( mysql_num_rows($resultSQL) < 1 ) {
echo "Error message, category ID not found"
} else {
echo "Found it!"
}
}
Oh, I see. The first line inside the while loop should have an "if":
while ($checkROW = mysql_fetch_array($checkSQL)) {
if ($checkCAT != $checkROW["categoryID"])
echo "err msg";
It looks like you'll be wanting to use mysql_fetch_assoc(), rather than mysql_fetch_array().