convert number of months to the number of years and months - php

Question

I am using a for loop to display numbers 1-60:
for($i=0; $i<=60; $i++)
within the loop, i want to be able to show the number of years and months. for example:
1 month
2 months
3 month
...
1 year
1 year 1 month
1 year 2 month
and so on...
i tried this:
if(!is_float($i/12)) {
$years = $i/12;
} else {
$years = 'no';
}
this shows 1 on the 12 month, 2 on 24 months but not the in between

Answer 1

You can use % and / for the integer part and the rest of division
try this loop for show the result
for($i=1; $i<=60; $i++){
echo 'year = ' . floor($i/12) . ' month = ' .$i%12 . '<br />';
}

Answer 2

I have used the following solution to complete my code with help from #scaisEdge
for($i=0; $i<=60; $i++) {
if(!is_float($i/12)) {
$years = floor($i / 12).' Year';
$years = $years.($years > 1 ? 's' : '');
if($years == 0) {
$years = '';
}
}
$months = ' '.($i % 12).' Month';
if($months == 0 or $months > 1) {
$months = $months.'s';
}
$display = $years.''.$months;
echo '<option value="'.$i.'"';
if($result["warrenty"] == $i) {
echo 'selected="selected"';
}
echo '>'.$display.'</option>';
}

Answer 3

function yearfm($months)
{
$str = '';
if(($y = round(bcdiv($months, 12))))
{
$str .= "$y Year".($y-1 ? 's' : null);
}
if(($m = round($months % 12)))
{
$str .= ($y ? ' ' : null)."$m Month".($m-1 ? 's' : null);
}
return empty($str) ? false : $str;
}
for($x = 0; $x < 100; $x++)
{
var_dump(yearfm($x));
}

Answer 4

another solution 1:
for ($i=0; $i<=60; $i++) {
$output = [];
if ($i >= 12) {
$years = ($i - $i % 12) / 12;
$output[] = $years > 1 ? $years . ' years' : $years . ' year';
}
if ($i % 12 > 0) {
$monthsRest = $i % 12;
$output[] = $monthsRest > 1 ? $monthsRest . ' months' : $monthsRest . ' month';
}
echo implode(' ', $output);
}
another solution 2:
for ($i=0; $i<=60; $i++) {
$output = [];
$startDate = new DateTime();
$endDate = new DateTime('+' . $i . ' months');
$interval = $startDate->diff($endDate);
$years = $interval->format('%y');
$months = $interval->format('%m');
if ($years > 0) {
$output[] = $years > 1 ? $years . ' years' : $years . ' year';
}
if ($months > 0) {
$output[] = $months > 1 ? $months . ' months' : $months . ' month';
}
echo implode(' ', $output);
}