PHP Calendar Issues - php

Question

I have the following code that I created to generate a Calendar, but it has some issues:
//Labels
$dayLabels = array("Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday");
$monthLables = array("January","February","March","April","May","June","July","August","September","October","November","December");
//max values
$maxDays = 7;
$maxMonths = 12;
//stats
$forceMonth = $_GET['m'];
$forceYear = $_GET['y'];
$todayDate = date("d-m-Y");
$todayDate = date("d-m-Y", strtotime($todayDate));
$explodeToday = explode("-", $todayDate);
$currentDay = $explodeToday[0];
if(isset($forceMonth)) {
$currentMonth = $forceMonth;
} else {
$currentMonth = $explodeToday[1];
};
if(isset($forceYear)) {
$currentYear = $forceYear;
} else {
$currentYear = $explodeToday[2];
};
$daysInMonth = cal_days_in_month(CAL_GREGORIAN, $currentMonth, $currentYear);
//database values
$startDate = array("01-06-2015","25-06-2015");
$endDate = array("05-06-2015","05-07-2015");
$bookedUser = array("Dexter","James");
//counters
$daysIntoMonth = 0;
$dayCounter = 0;
//debug
echo '<p>Current Month: ' .$monthLables[$currentMonth-1]. ' / ' .$currentMonth. '</p>';
echo '<p>Current Year: ' .$currentYear. '</p>';
//start of Calendar
echo '<table>';
//print days of week
echo '<tr>';
foreach($dayLabels as $day) {
echo '<td style="border-bottom:dashed 1px #DDD;">' .$day. '</td>';
};
echo '</tr>';
while($daysIntoMonth < $daysInMonth) {
//days into month
$daysIntoMonth++;
$temp_inMonth = sprintf("%02d", $daysIntoMonth);
$daysIntoMonth = $temp_inMonth;
//days into week
$dayCounter++;
$temp_dayCounter = sprintf("%02d", $dayCounter);
$dayCounter = $temp_dayCounter;
//current calendar date
$calDate = date('d-m-Y', strtotime($daysIntoMonth. '-' .$currentMonth. '-' .$currentYear));
$timeCal = strtotime($calDate);
if($dayCounter == 1) {
echo '<tr>';
};
if($startKey = array_search($calDate, $startDate) !== FALSE) {
$booked = true;
};
if($endKey = array_search($calDate, $endDate) !== FALSE) {
$booked = false;
};
if($booked == true) {
echo '<td style="background-color:red;">' .$calDate. ' / ' .$daysIntoMonth. ' ' .$dayCounter. '</td>';
} else if($booked == true && array_search($calDate, $startDate) !== FALSE) {
echo '<td style="background-color:red;">' .$calDate. ' / ' .$daysIntoMonth. ' ' .$dayCounter. '</td>';
} else if($booked == false && array_search($calDate, $endDate) !== FALSE) {
echo '<td style="background-color:red;">' .$calDate. ' / ' .$daysIntoMonth. ' ' .$dayCounter. '</td>';
} else {
echo '<td>' .$calDate. ' / ' .$daysIntoMonth. ' ' .$dayCounter. '</td>';
}
if($dayCounter == $maxDays) {
echo '</tr>';
$dayCounter = 0;
};
};
//table is kill
echo '</table>';
The issues I have noticed:
Unable to put a $bookedUser for respective $startDate,$endDate.
When a booking laps over to another month, it skips all the dates until the $endDate.
All Months start on Monday, how would I go about making them start of correct days of the week.
Possible code examples to help me solve my issues would be great, thanks in advance.
Edit:
I have solved problem 3 by using the following code:
$firstDayofMonth = strtotime("01-$currentMonth-$currentYear");
$firstDayofMonth = date("D", $firstDayofMonth);
$firstDayofMonth = array_search($firstDayofMonth, $dayMiniLabels);
$firstDayofMonth = $firstDayofMonth + 1;
$startMonth = 0;
if($firstDayofMonth != 7) {
while($startMonth < $firstDayofMonth) {
echo '<td></td>';
$startMonth++;
$dayCounter++;
$temp_dayCounter = sprintf("%02d", $dayCounter);
$dayCounter = $temp_dayCounter;
};
};

Answer 1

For the days and months (problem 3), I would do this:
$todaysNumber = date('w');
$currentDayInText = $dayLabels[$todaysNumber];
And the same for the monhts.
Mostly, in my MySQL-tables, dates are placed like 2015-06-05 and not in European time notation. Maybe that could solve problem 1?