This is my first php program. Im trying to compare the result of adding two randomly generated numbers (visually displayed before text field) to the answer i give in the submit. But it just wont work. I pass the result at $value3 and try to compare it to the result of the submit. Any ideas guys?
<head>
<title>
</title>
</head>
<?php
$displayForm=True;
if(isset($_GET['result'])){
$displayForm=False;
}
if($displayForm){
?>
<body>
<form method="GET">
result
<?php
$value1=rand(1,10);
$value2=rand(1,10);
$value3=$value1 + $value2;
echo($value1);
echo("+");
echo($value2);
?>
<input type="text" name="number">
<input type="hidden" name="val3" value="$value3">
<input type="submit" name="result" value="submit">
</form>
<?php
}
if(isset($_GET['result'])){
if(isset($_GET['result'])){
$result = $_GET['result'];
}
if($result==$_GET['val3']){
echo "result right: you re human";
}
else{
echo "lol you are a retarded cat";
}
}
?>
</body>
Try this
<body>
<form method="GET">
result
<?php
$value1=rand(1,10);
$value2=rand(1,10);
$value3=$value1 + $value2;
echo($value1);
echo("+");
echo($value2);
?>
<input type="text" name="number">
<input type="hidden" name="val3" value="<?php echo $value3; ?>">
<input type="submit" name="result" value="submit">
</form>
<?php
}
if(isset($_GET['result'])){
if(isset($_GET['result'])){
$result = $_GET['number'];
}
if($result==$_GET['val3']){
echo "result right: you re human";
}
else{
echo "lol you are a retarded cat";
}
}
?>
</body>
Related
I'm a student doing a challenge where I would have to make a Calculator-type form where you can input two values and click an operation. It's a simple concept using only 4 operations.
I was able to make the format of the form: title, input text and buttons. But I can't find a way to take the input information and manipulating the information. My initial goal was to take the two values and adding/subtracting/multiplying/dividing the values and printing the statement above.
For example:
1 + 2 = 3 //statement printed above
First Value: 1
Second Value: 2 //insert values
+ - * / //click operation buttons
Any suggestions?
<!DOCTYPE HTML>
<?php
print_r($_POST);
if ( isset($_POST["+"]) ) {
$sum = $var1 + $var2;
echo "$var1 + $var2 = $sum";
}
elseif( isset($_POST["-"]) ) {
$sum = $var1 - $var2;
echo "$var1 - $var2 = $sum";
}
elseif ( isset($_POST["*"]) ) {
$sum = $var1 * $var2;
echo "$var1 * $var2 = $sum";
}
elseif ( isset($_POST["/"]) ) {
$sum = $var1 / $var2;
echo "$var1 / $var2 = $sum";
}
?>
<html>
<body>
<form action="" method="POST">
First Value: <input type="text" name="First Value"><br><br>
Second Value: <input type="text" name="Second Value"><br><br>
Operations: <button type="submit" name "+">+</button>
<button type="submit" name "-">-</button>
<button type="submit" name "*">*</button>
<button type="submit" name "/">/</button>
</form>
</body>
</html>
This seems to fix the errors I mentioned in comments
<!DOCTYPE HTML>
<html>
<body>
<?php
if ( $_SERVER['REQUEST_METHOD'] == 'POST'){
if ( isset($_POST["+"]) ) {
$sum = $_POST['var1'] + $_POST['var2'];
echo "$_POST[var1] + $_POST[var2] = $sum";
}
elseif( isset($_POST["-"]) ) {
$sum = $_POST['var1'] - $_POST['var2'];
echo "$_POST[var1] - $_POST[var2] = $sum";
}
elseif ( isset($_POST["*"]) ) {
$sum = $_POST['var1'] * $_POST['var2'];
echo "$_POST[var1] * $_POST[var2] = $sum";
}
elseif ( isset($_POST["/"]) ) {
$sum = $_POST['var1'] / $_POST['var2'];
echo "$_POST[var1] / $_POST[var2] = $sum";
}
}
?>
<form action="" method="POST">
First Value: <input type="text" name="var1"><br><br>
Second Value: <input type="text" name="var2"><br><br>
Operations: <button type="submit" name="+">+</button>
<button type="submit" name="-">-</button>
<button type="submit" name="*">*</button>
<button type="submit" name="/">/</button>
</form>
</body>
</html>
I don't know if it's the right way to do things but you can use jquery in the script section to do so, let's say you have this form
<form id="target" action="destination.html">
<input type="text" value="Hello there">
<input type="submit" value="Go">
</form>
so on the submit you do the math
$( "#target" ).submit(function( event ) {
//do the math//
document.write(//your answer//);
event.preventDefault();
});
<?php
$first_num = $_POST['first_num'];
$second_num = $_POST['second_num'];
$operator = $_POST['operator'];
$result = '';
if (is_numeric($first_num) && is_numeric($second_num)) {
switch ($operator) {
case "Add":
$result = $first_num + $second_num;
break;
case "Subtract":
$result = $first_num - $second_num;
break;
case "Multiply":
$result = $first_num * $second_num;
break;
case "Divide":
$result = $first_num / $second_num;
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<div id="page-wrap">
<h1>Simple Calculator Program</h1>
<form action="" method="post" id="quiz-form">
<p>
<label>First Number</label>
<input type="number" name="first_num" id="first_num" required="required" value="<?php echo $first_num; ?>" />
</p>
<p>
<label>Second Number</label>
<input type="number" name="second_num" id="second_num" required="required" value="<?php echo $second_num; ?>" />
</p>
<p>
<label>Result</label>
<input readonly="readonly" name="result" value="<?php echo $result; ?>">
</p>
<input type="submit" name="operator" value="Add" />
<input type="submit" name="operator" value="Subtract" />
<input type="submit" name="operator" value="Multiply" />
<input type="submit" name="operator" value="Divide" />
</form>
</div>
</body>
</html>
I write a conversion from celsius to fahrenheit and vice versa. The problem is that in the form fields now random values are displayed to me. How to convert this code so that after entering the value, the converted value in the second field appears in the first field?
Is it possible to use only php at all?
if(isset($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
}
if(isset($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $fah; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $cel; ?>" name="cel">
<input type="submit" value="Calc">
</form>
I want the value entered in the first field to be shown in the second transformed.
You can do all php if you post back to itself. If the page with the input is calc.php
Add an else to set the value to empty string.
if(isset($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
} else {
$cel = '';
}
if(isset($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
} else {
$fah = '';
}
Try something like this
$cel="";
$fah="";
if(isset($_POST['fah']) && !empty($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
}
if(isset($_POST['cel']) && !empty($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
}
You can try this example:
$celValue = $_POST['cel'];
$fahValue = $_POST['fah'];
if( ! empty($fahValue)){
$celValue = fahrenheitToCelcius($_POST['fah']);
}
if( ! empty($celValue)){
$fahValue = celciusToFahrenheit($_POST['cel']);
}
function celciusToFahrenheit($cel) {
return ($cel - 32) * 1.8;
}
function fahrenheitToCelcius($fah) {
return ($fah + 32) / 1.8;
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $celValue; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $fahValue; ?>" name="cel">
<input type="submit" value="Calc">
</form>
Since both the variables give isset() true so we can have something like this
if(isset($_POST['fah']) && isset($_POST['cel'])) {
//if cel is not empty
if(!empty($_POST['cel'])) {
$cel = $_POST['cel'];
$fah=($cel-32)*1.8;
} else if(!empty($_POST['fah']){
$fah = $_POST['fah'];
$cel = ($fah+32)/1.8;
}
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $fah; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $cel; ?>" name="cel">
<input type="submit" value="Calc">
</form>
You just missing set default values that will overwrite if other post value exist, and else if to load only one parameter so other will be empty
<?php
$cel = "";
$fah = "";
if(isset($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
}elseif(isset($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $fah; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $cel; ?>" name="cel">
<input type="submit" value="Calc">
</form>
I want to output the values of the checkbox in the same way I'm outputting the values from the text fields. Since the checkbox can have multiple inputs I'm using an array for that but trying to cycle through the array for values hasn't worked for me.
tried foreach($type as $item) and echoing $item within the HTML like it says in the PHP book I have but that hasn't worked.
How should I do and where should the code be? I'm also unable to use PHP within the HTML for some reason, I'm not sure why that is or if its something to do with the echo<<<_END or not. Help appreciated.
<?php // formtest.php
if (isset($_POST['game'])) $game = $_POST['game'];
else $game = "(Not entered)";
if (isset($_POST['genre'])) $genre = $_POST['genre'];
else $genre = "(Not entered)";
if (isset($_POST['type'])) $type = $_POST['type'];
else $type = "(Not entered)";
echo <<<_END
<html>
<head>
<title>Form Test</title>
</head>
<body>
Your game is: $game in the $genre genre and of the type<br />
<form method="post" action="formtest.php">
What is your game?
<input type="text" name="game" />
<br />
What is your genre?
<input type="text" name="genre" />
<br />
Type?
Retail <input type="checkbox" name="type[]" value="Retail" />
Downloadable <input type="checkbox" name="type[]" value="Downloadable" />
Free <input type="checkbox" name="type[]" value="Free" />
<br />
<input type="submit" />
</form>
</body>
</html>
_END;
?>
With the form as it is now, $_POST['type'] will be an array since it's using checkboxes (and named appropriately), not radios. Here I just implode it for display, but you can loop through it like any array. It should be worth noting that any time you're wondering what a form is giving you, you can var_dump($_POST) or var_dump($_GET) depending on where the data is coming from. It helps a lot with debugging.
Here's what I got, I switched from heredoc, but your heredoc should work fine if you add $type back in somewhere, I didn't notice it in the original code:
<?php // formtest.php
if (isset($_POST['game'])) $game = $_POST['game'];
else $game = "(Not entered)";
if (isset($_POST['genre'])) $genre = $_POST['genre']; //Edit: Fixed line, oops
else $genre = "(Not entered)";
if (isset($_POST['type'])) $type = implode(', ',$_POST['type']);
else $type = "(Not entered)";
//Normally I'd specify a charset, but for simplicity's sake I won't here.
$type = htmlspecialchars($type);
$game = htmlspecialchars($game);
$genre = htmlspecialchars($genre);
?>
<html>
<head>
<title>Form Test</title>
</head>
<body>
Your game is: <?php echo $game; ?> in
the <?php echo $genre; ?> genre and of the type <?php echo $type; ?><br />
<form method="post" action="">
What is your game?
<input type="text" name="game" />
<br />
What is your genre?
<input type="text" name="genre" />
<br />
Type?
Retail <input type="checkbox" name="type[]" value="Retail" />
Downloadable <input type="checkbox" name="type[]" value="Downloadable" />
Free <input type="checkbox" name="type[]" value="Free" />
<br />
<input type="submit" />
</form>
</body>
</html>
Addendum:
If you switched and used radios like
<input type="radio" name="type" value="Downloadable" />
$_POST['type'] would be a simple string since you can only select one of the set.
To the file you post it the type[] will be saved as an array. For example
$a=$_POST['type'];
Although I don't find any point in doing this to radio-buttons, because their purpose is to pass only 1 value(unless you want specifically to).
Ok, first you don't need to echo the entire html output. Second your questions says radio buttons, but the html shows checkboxes. A radio field will only produce one result so you don't need [] after then name. Checkboxes will return an array when named with a []. So if you are using checkboxes you will need to process the result as an array. If you change the field to radio it should work fine.
<?php // formtest.php
if (isset($_POST['game'])) {
$game = $_POST['game'];
}
else { $game = "(Not entered)"; }
if (isset($_POST['genre'])) {
$genre = $_POST['genre'];
}
else { $genre = "(Not entered)"; }
if (isset($_POST['type'])) {
$type = $_POST['type'];
}
else { $type = "(Not entered)"; }
?>
<html>
<head>
<title>Form Test</title>
</head>
<body>
Your game is: <?php echo $game; ?> in the <?php echo $genre; ?> genre and of the type <?php echo $type; ?><br />
<form method="post" action="test.php">
What is your game?
<input type="text" name="game" <?php if ($game != "(Not entered)") { echo "value='" . $game . "'"; } ?> />
<br />
What is your genre?
<input type="text" name="genre" <?php if ($genre != "(Not entered)") { echo "value='" . $genre . "'"; } ?> />
<br />
Type?
Retail <input type="radio" name="type" value="Retail" <?php if ($type == "Retail") { echo "checked"; } ?> />
Downloadable <input type="radio" name="type" value="Downloadable" <?php if ($type == "Downloadable") { echo "checked"; } ?> />
Free <input type="radio" name="type" value="Free" <?php if ($type == "Free") { echo "checked"; } ?> />
<br />
<input type="submit" />
</form>
</body>
</html>
i wrote a piece of code to do multiple row deletions based on ticked check boxes.
Now i need to mordify it to do multiple row updates.
i have been failing to access the textbox values for each row.
here's my code, in general.
<?php
if (isset($_POST["SaveComments"]) && isset($_POST["SaveEachComment"]))
{
while(list($key, $val) = each($_POST["SaveEachComment"]))
{
if($val == 'commentbox')
{
// do the update here. $val contains the ID
}
}
}
?>
<form id="form1" name="form1" method="post" action="test.php">
<input type="checkbox" <?php echo 'name="SaveEachComment['.$row["comment"].']" ';?> value="commentbox" id="commentbox" />
<input type="text" name="rowcomment" size="55" value="<?php echo $comment;?>" />
<input type="submit" name="SaveComments" value="submit" />
</form>
I just added a for loop to print multiple form fields. Obviously your iteration would be as many as number of rows, so you can change that part of the code. But try this:
<?php
if (isset($_POST["SaveComments"]) && isset($_POST["SaveEachComment"]))
{
while(list($key, $val) = each($_POST["SaveEachComment"]))
{
if($val == 'commentbox')
{
echo $_POST['rowcomment'][$key] . "<br />\n";
// do the update here. $val contains the ID
}
}
}
?>
<form id="form1" name="form1" method="post" action="test.php">
<?php for ($i=0; $i<11; $i++) { ?>
<input type="checkbox" <?php echo 'name="SaveEachComment['.$i.']" ';?> value="commentbox" id="commentbox" />
<input type="text" name="rowcomment[<? echo $i?>]" size="55" value="<?php echo $comment;?>" />
<br />
<?php } ?>
<input type="submit" name="SaveComments" value="submit" />
</form>
Can you tell me why when I click call my data is not posting to my action?
<body>
<?php
$login = '1236567';
$password = '10152930';
$officeNumber = array('0212177899','027899899','09111');
?>
<div id="wrapper">
<form method="POST" action="https://live.domain.co.nz/call.php?login=<?php echo $login; ?>&password=<?php echo $password; ?>&aparty=<?php echo $number; ?>phone&bparty=<?php echo $number;?>">
<?php
echo '<label for="officeNumbers">Office Number: </label>';
echo '<select name="officeNumbers">';
foreach($officeNumber as $number)
{
echo '<option value="'.$number.'">'.$number.'</option>';
}
echo '</select>';
?>
<label for="callTo">Call: </label><input type="text" id="callTo">
<input type="submit" value="Call">
</form>
</div>
</body>
</html>
Your text input:
<input type="text" id="callTo">
… has no name attribute, so it cannot be a successful control (and thus submit any data).
Give it a name attribute.