I write a conversion from celsius to fahrenheit and vice versa. The problem is that in the form fields now random values are displayed to me. How to convert this code so that after entering the value, the converted value in the second field appears in the first field?
Is it possible to use only php at all?
if(isset($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
}
if(isset($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $fah; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $cel; ?>" name="cel">
<input type="submit" value="Calc">
</form>
I want the value entered in the first field to be shown in the second transformed.
You can do all php if you post back to itself. If the page with the input is calc.php
Add an else to set the value to empty string.
if(isset($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
} else {
$cel = '';
}
if(isset($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
} else {
$fah = '';
}
Try something like this
$cel="";
$fah="";
if(isset($_POST['fah']) && !empty($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
}
if(isset($_POST['cel']) && !empty($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
}
You can try this example:
$celValue = $_POST['cel'];
$fahValue = $_POST['fah'];
if( ! empty($fahValue)){
$celValue = fahrenheitToCelcius($_POST['fah']);
}
if( ! empty($celValue)){
$fahValue = celciusToFahrenheit($_POST['cel']);
}
function celciusToFahrenheit($cel) {
return ($cel - 32) * 1.8;
}
function fahrenheitToCelcius($fah) {
return ($fah + 32) / 1.8;
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $celValue; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $fahValue; ?>" name="cel">
<input type="submit" value="Calc">
</form>
Since both the variables give isset() true so we can have something like this
if(isset($_POST['fah']) && isset($_POST['cel'])) {
//if cel is not empty
if(!empty($_POST['cel'])) {
$cel = $_POST['cel'];
$fah=($cel-32)*1.8;
} else if(!empty($_POST['fah']){
$fah = $_POST['fah'];
$cel = ($fah+32)/1.8;
}
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $fah; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $cel; ?>" name="cel">
<input type="submit" value="Calc">
</form>
You just missing set default values that will overwrite if other post value exist, and else if to load only one parameter so other will be empty
<?php
$cel = "";
$fah = "";
if(isset($_POST['fah'])){
$cel=($_POST['fah']+32)/1.8;
}elseif(isset($_POST['cel'])){
$fah=($_POST['cel']-32)*1.8;
}
?>
<html>
<body>
<form method="post" action="calc.php">
Fahrenheit: <input id="inFah" type="text" placeholder="Fahrenheit" value="<?php echo $fah; ?>" name="fah">
Celcius: <input id="inCel" type="text" placeholder="Celcius" value="<?php echo $cel; ?>" name="cel">
<input type="submit" value="Calc">
</form>
Related
I would like to create an input box that is only readable and have the title of the book, is it possible that the input box can store a variable?
P.S The one I want to change is the id, now I successfully disabled the input box, but the output is $id instead of the variable that I use the $_GET method.
My code is as follow
<?php
include_once 'header.php';
$id = mysqli_real_escape_string($conn, $_GET['bookid']);
$title = mysqli_real_escape_string($conn, $_GET['title']);
?>
<section class="signup-form">
<h2>Pre-order</h2>
<div class="signup-form-form">
<form action="preorder.inc.php" method="post">
<input type="text" disabled="disabled" name="id" value= $id >
<input type="text" name="uid" placeholder="Username...">
<input type="text" name="BRO" placeholder="BookRegistrationCode...">
<button type="submit" name="submit">Pre-order</button>
</form>
</div>
<?php
// Error messages
if (isset($_GET["error"])) {
if ($_GET["error"] == "emptyinput") {
echo "<p>Fill in all fields!</p>";
}
else if ($_GET["error"] == "wronginfo") {
echo "<p>Wrong information!</p>";
}
else if ($_GET["error"] == "stmtfailed") {
echo "<p>Something went wrong!</p>";
}
else if ($_GET["error"] == "none") {
echo "<p>Success!</p>";
}
}
?>
</section>
Put <?php echo $var; ?> inside the value attribute.
<input type="text" value="<?php echo $var; ?>" />
EDIT
As per #arkascha's comment, you can use alternative php short tags:
<input type="text" value="<?= $var; ?>" />
As per the docs: https://www.php.net/manual/en/language.basic-syntax.phptags.php
$va_fields = array();
$c = 0;
$field_num = 'field-'.$c;
settype($c,"integer");
while (isset($_POST[$field_num])){
$posted_field = $_POST[$field_num];
$va_fields = array( $c => $posted_field);
echo $c.': ';
echo '$posted_field: '.$posted_field;
$c+=1;
$field_num = 'field-'.$c;
echo ' <br /> va_fields - c:'.$va_fields[$c];
echo ' <br /> ';
}
For some reason, I cannot for the life of me get the variable $posted_fields into an array.
The values of $posted_field are what I need them to be, so I'm getting the data from the post. Then I try to store them in an array, and check the array and they aren't there. What am I doing wrong?
Edit: here's my form:
<form method="post" action="<?php echo get_site_url(); ?>/wp-admin/admin-post.php">
<input type="hidden" name="action" value="cpt_field_opts" />
<!-- some inputs here ... -->
<?php wp_nonce_field( 'cpt_field_opts', '_wp_nonce' ); ?>
<input type="hidden" name="post_type" value="<?php echo $post_type; ?>">
<input type="hidden" name="origin" value="<?php echo "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]"; ?>" />
<?php
$c = 0;
foreach ($fields as $field){
?>
<input type="textarea" id="field-<?php echo $c; ?>" name="field-<?php echo $c; ?>" value="<?php echo $field; ?>" size="25" /></br>
<?php
$c += 1;
}
?>
<input type="submit" value="Submit" >
</form>
<form method="post" action="<?php echo get_site_url(); ?>/wp-admin/admin-post.php">
<?php wp_nonce_field( 'cpt_field_opts_new', '_wp_nonce_2' ); ?>
<input type="hidden" name="post_type" value="<?php echo $post_type; ?>" />
<input type="hidden" name="action" value="cpt_field_opts_new" />
<input type="hidden" name="origin" value="<?php echo "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]"; ?>" />
<input type="submit" value="New" />
</form>
Many people are telling me to rewrite the array as this line:
$va_fields[$c] = $posted_field;
Which I have done, but I also started out with that and it still wasn't working
If you have a bunch of values in $_POST with names like "field-0", "field-1", etc, and you're trying to get them into an array:
$c = 0;
while (isset($_POST["field-$c"])){
// This creates a new element in $va_fields with key=$c and value=$_POST["field-$c"]
$va_fields[$c] = $_POST["field-$c"];
}
var_dump($va_fields); // should show you the array you want
But really, it would be easier to just modify your form to use inputs with name=field[] instead of numbering them. Then you would already have the array in $_POST['fields'] without having to do anything.
It is simple just iterate the $_POST array
<?php
$va_fields = array();
$c=0;
foreach($_POST as $val){
echo '$posted_field: '. $val;
$va_fields[$c] = $val;
}
var_dump($va_fields);
?>
how to display the result after submit the form
i want a display result after submit the form for print
example 1st im filling the form submit the result after the submit i want a screen to display same result
http://www.tizag.com/phpT/examples/formexample.php
how can i do this
please help me to fix this issue.
php form code
<?php
function renderForm($grn, $name, $rollno, $class, $fees, $date, $reference, $error)
{
?>
<?php
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>';
}
?>
<form action="" method="post">
<div>
<p><span class="style9"><strong>G.R.N No:</strong></span><strong> *</strong>
<input name="grn" type="text" id="grn" value="<?php echo $grn; ?>" size="50" />
</p>
<p><span class="style9"><strong>Name:</strong></span><strong> *</strong>
<input name="name" type="text" id="name" value="<?php echo $name; ?>" size="50" />
</p>
<p><span class="style9"><strong>Roll No :</strong></span><strong> *</strong>
<input name="rollno" type="text" id="rollno" value="<?php echo $rollno; ?>" size="50" />
</p>
<p><span class="style9"><strong>Class:</strong></span><strong> *</strong>
<input name="class" type="text" id="class" value="<?php echo $class; ?>" size="50" />
</p>
<p><span class="style9"><strong>Fees Date :</strong></span><strong> *</strong>
<input id="fullDate" name="date" type="text" value="<?php echo $date; ?>" size="50" />
</p>
<p><span class="style9"><strong>Fees :</strong></span><strong> *</strong>
<input name="fees" type="text" value="<?php echo $fees; ?>" size="50" />
</p>
<span class="style9"><strong>Reference</strong></span><strong> *</strong>
<input name="reference" type="text" value="<?php echo $reference; ?>" size="50">
<br/>
<p class="style1">* required</p>
<input type="submit" name="submit" value="Submit">
</div>
</form>
<?php
}
include('connect-db.php');
if (isset($_POST['submit']))
{
// get form data, making sure it is valid
$grn = mysql_real_escape_string(htmlspecialchars($_POST['grn']));
$name = mysql_real_escape_string(htmlspecialchars($_POST['name']));
$rollno = mysql_real_escape_string(htmlspecialchars($_POST['rollno']));
$class = mysql_real_escape_string(htmlspecialchars($_POST['class']));
$fees = mysql_real_escape_string(htmlspecialchars($_POST['fees']));
$date = mysql_real_escape_string(htmlspecialchars($_POST['date']));
$reference = mysql_real_escape_string(htmlspecialchars($_POST['reference']));
// check to make sure both fields are entered
if ($grn == '' || $name == '' || $rollno == '')
{
// generate error message
$error = 'ERROR: Please fill in all required fields!';
// if either field is blank, display the form again
renderForm($grn, $name, $rollno, $class, $fees, $date, $reference, $error);
}
else
{
// save the data to the database
mysql_query("INSERT fees SET grn='$grn', name='$name', rollno='$rollno', class='$class', fees='$fees', date='$date', reference='$reference'")
or die(mysql_error());
echo "<center>KeyWord Submitted!</center>";
// once saved, redirect back to the view page
}
}
else
// if the form hasn't been submitted, display the form
{
renderForm('','','','','','','','');
}
?>
Not quite shure what you are asking.
do you need help displaying the submited form data? or more spesific display for print?
to display it you would just need to make a html page that displays it.
like:
echo '<table><tr>';
echo '<td>';
echo '<Strong>Name:</strong><br/>';
echo $name;
echo '</td>';
echo '</tr></table>';
To display just the result and not the form, when you post to the same page you need to encapsulate the for code with an if statement.
if(isset($_POST['submit'])) {
//code for the php form
}else {
//code to display form
}
Use a new page for the "action" part in the form. On that new page, simply echo the $_POST of values you want to display. If you plan on making some sort of page so that people can check their entries, you could store these $_POST-data in sessions.
Simply call function on the bottom to disply posted values :
function showFormValues()
{
?>
<div>
<p><span class="style9"><strong>G.R.N No:</strong></span><strong> *</strong>
<?php echo $_POST['grn']; ?>
</p>
<p><span class="style9"><strong>Name:</strong></span><strong> *</strong>
<?php echo $_POST['name'];
</p>
and so on.
.
.
.
.
</div>
<?php
}
?>
i wrote a piece of code to do multiple row deletions based on ticked check boxes.
Now i need to mordify it to do multiple row updates.
i have been failing to access the textbox values for each row.
here's my code, in general.
<?php
if (isset($_POST["SaveComments"]) && isset($_POST["SaveEachComment"]))
{
while(list($key, $val) = each($_POST["SaveEachComment"]))
{
if($val == 'commentbox')
{
// do the update here. $val contains the ID
}
}
}
?>
<form id="form1" name="form1" method="post" action="test.php">
<input type="checkbox" <?php echo 'name="SaveEachComment['.$row["comment"].']" ';?> value="commentbox" id="commentbox" />
<input type="text" name="rowcomment" size="55" value="<?php echo $comment;?>" />
<input type="submit" name="SaveComments" value="submit" />
</form>
I just added a for loop to print multiple form fields. Obviously your iteration would be as many as number of rows, so you can change that part of the code. But try this:
<?php
if (isset($_POST["SaveComments"]) && isset($_POST["SaveEachComment"]))
{
while(list($key, $val) = each($_POST["SaveEachComment"]))
{
if($val == 'commentbox')
{
echo $_POST['rowcomment'][$key] . "<br />\n";
// do the update here. $val contains the ID
}
}
}
?>
<form id="form1" name="form1" method="post" action="test.php">
<?php for ($i=0; $i<11; $i++) { ?>
<input type="checkbox" <?php echo 'name="SaveEachComment['.$i.']" ';?> value="commentbox" id="commentbox" />
<input type="text" name="rowcomment[<? echo $i?>]" size="55" value="<?php echo $comment;?>" />
<br />
<?php } ?>
<input type="submit" name="SaveComments" value="submit" />
</form>
Can you tell me why when I click call my data is not posting to my action?
<body>
<?php
$login = '1236567';
$password = '10152930';
$officeNumber = array('0212177899','027899899','09111');
?>
<div id="wrapper">
<form method="POST" action="https://live.domain.co.nz/call.php?login=<?php echo $login; ?>&password=<?php echo $password; ?>&aparty=<?php echo $number; ?>phone&bparty=<?php echo $number;?>">
<?php
echo '<label for="officeNumbers">Office Number: </label>';
echo '<select name="officeNumbers">';
foreach($officeNumber as $number)
{
echo '<option value="'.$number.'">'.$number.'</option>';
}
echo '</select>';
?>
<label for="callTo">Call: </label><input type="text" id="callTo">
<input type="submit" value="Call">
</form>
</div>
</body>
</html>
Your text input:
<input type="text" id="callTo">
… has no name attribute, so it cannot be a successful control (and thus submit any data).
Give it a name attribute.