I have a bunch of text and i want to highlight some words on that text. I've search the stackoverflow website and came up with something that almost work.
PHP
function highlighter($str, $arr_word)
{
foreach($arr_word as $vword) {
$text = preg_replace("|($vword)|Ui", "<span class=highlight>$1</span>", $str);
}
return $text;
}
$lyrics = 'hello looking for';
$arr_accepted_keyword = array('hello', 'for');
echo highlighter($lyrics, $arr_accepted_keyword);
For some reason, it always highligths the last word, and not all the words. Why?
The problem is that you're highlighting each word in the original string, not the updated string.
function highlighter($str, $arr_word)
{
foreach($arr_word as $vword) {
$str = preg_replace("/($vword)/Ui", "<span class=highlight>$1</span>", $str);
}
return $str;
}
$lyrics = "hello, is it me you're looking for?";
$arr_accepted_keyword = array('hello', 'for');
echo highlighter($lyrics, $arr_accepted_keyword);
// "<span class=highlight>hello</span>, is it me you're looking <span class=highlight>for</span>?"
Related
I have a search String: $str (Something like "test"), a wrap string: $wrap (Something like "|") and a text string: $text (Something like "This is a test Text").
$str is 1 Time in $text. What i want now is a function that will wrap $str with the wrap defined in $wrap and output the modified text (even if $str is more than one time in $text).
But it shall not output the whole text but just 1-2 of the words before $str and then 1-2 of the words after $str and "..." (Only if it isn`t the first or last word). Also it should be case insensitive.
Example:
$str = "Text"
$wrap = "<span>|</span>"
$text = "This is a really long Text where the word Text appears about 3 times Text"
Output would be:
"...long <span>Text</span> where...word <span>Text</span> appears...times <span>Text</span>"
My Code (Obviusly doesnt works):
$tempar = preg_split("/$str/i", $text);
if (count($tempar) <= 2) {
$result = "... ".substr($tempar[0], -7).$wrap.substr($tempar[1], 7)." ...";
} else {
$amount = substr_count($text, $str);
for ($i = 0; $i < $amount; $i++) {
$result = $result.".. ".substr($tempar[$i], -7).$wrap.substr($tempar[$i+1], 0, 7)." ..";
}
}
If you have a tipp or a solution dont hesitate to let me know.
I have taken your approach and made it more flexible. If $str or $wrap changes you could have escaping issues within the regex pattern so I have used preg_quote.
Note that I added $placeholder to make it clearer, but you can use $placeholder = "|" if you don't like [placeholder].
function wrapInString($str, $text, $element = 'span') {
$placeholder = "[placeholder]"; // The string that will be replaced by $str
$wrap = "<{$element}>{$placeholder}</{$element}>"; // Dynamic string that can handle more than just span
$strExp = preg_quote($str, '/');
$matches = [];
$matchCount = preg_match_all("/(\w+\s+)?(\w+\s+)?({$strExp})(\s+\w+)?(\s+\w+)?/i", $text, $matches);
$response = '';
for ($i = 0; $i < $matchCount; $i++) {
if (strlen($matches[1][$i])) {
$response .= '...';
}
if (strlen($matches[2][$i])) {
$response .= $matches[2][$i];
}
$response .= str_replace($placeholder, $matches[3][$i], $wrap);
if (strlen($matches[4][$i])) {
$response .= $matches[4][$i];
}
if (strlen($matches[5][$i]) && $i == $matchCount - 1) {
$response .= '...';
}
}
return $response;
}
$text = "text This is a really long Text where the word Text appears about 3 times Text";
string(107) "<span>text</span> This...long <span>text</span> where...<span>text</span> appears...times <span>text</span>"
To make the replacement case insensitive you can use the i regex option.
If I understand your question correct, just a little bit of implode and explode magic needed
$text = "This is a really long Text where the word Text appears about 3 times Text";
$arr = explode("Text", $text);
print_r(implode('<span>Text</span>', $arr));
If you specifically need to render the span tags using HTML, just write it that way
$arr = explode("Text", $text);
print_r(implode('<span>Text</span>', $arr));
Use patern below to get your word and 1-2 words before and after
/((\w+\s+){1,2}|^)text((\s+\w+){1,2}|$)/i
demo
In PHP code it can be:
$str = "Text";
$wrap = "<span>|</span>";
$text = "This is a really long Text where the word Text appears about 3 times Text";
$temp = str_replace('|', $str, $wrap); // <span>Text</span>
// find patern and 1-2 words before and after
// (to make it casesensitive, delete 'i' from patern)
if(preg_match_all('/((\w+\s+){1,2}|^)text((\s+\w+){1,2}|$)/i', $text, $match)) {
$res = array_map(function($x) use($str, $temp) { return '... '.str_replace($str, $temp, $x) . ' ...';}, $match[0]);
echo implode(' ', $res);
}
I want write a simple code that convert special words to special link (for wiki plugin), if it's not a link!
For example suppose we have a text "Hello! How are you?!" and
we want convert are to are, but if we have Hello! How are you?! or Hello! How are you?! does not change. Because it's a link.
How can I do it in PHP?! With preg_replace?! How to?
Thanks.
It's easy.
<?php
$string = "Hello! How are you?!";
$stringTwo = "Hello! how are you?!";
function turnTheWordIntoALink($string, $word, $link) {
if(isLink($string)) {
return $string;
} else {
$string = str_replace($word, "" . $word . "", $string);
return $string;
}
}
function isLink($string) {
return preg_match("/(<a href=\".\">)/", $string);
}
echo turnTheWordIntoALink($string, 'are', 'http://google.com');
echo turnTheWordIntoALink($stringTwo, 'are', 'http://google.com');
Output:
First function output: Hello! How are you?!
Second function output: Hello! how are you?!
Alternative:
If you want to not detect <a> tags which were closed, you can use this alternative code:
$stringThree = "Hello! how <a href=\"#\">are you?!";
function turnTheWordIntoALink($string, $word, $link) {
if(isLink($string)) {
return $string;
} else {
$string = str_replace($word, "" . $word . "", $string);
return $string;
}
}
function isLink($string) {
return preg_match("/(<a href=\".\">)+(.)+(<\/a>)/", $string);
}
echo turnTheWordIntoALink($stringThree, 'are', 'http://google.com') . "\n";
This gives the output: Hello! how <a href="http://google.com">are you?!
this code is about : if there is a some URL in some phrase it will convert to a link
$word = 'hello how are you google.com, wish you good time';
$prg = "/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";
if(preg_match($prg, $word, $url))
{
echo preg_replace($prg, "<a href=http://$url[0]>{$url[0]}</a>", $word);
}
else
{
echo $word;
}
To better clarify the issue:
I have a HTML code that have some tags. I want some words in that, converted to some links. But if it is a another link does not convert. See below advanced example for special word you that we want linked to the google:
This is a sample text.
Hello?! How are you?!
Are you ready?!
should be convert to:
This is a sample text.
Hello?! How are you?!
Are you ready ?!
Note that the first you changed, but that second you was not changed, because it's in the another <a> tag.
Answer:
Because of this work has issue with regular expression, this problem can solve without regular expression. Here a simple solution is given:
$data = 'Hello! This is a sample text. <br/>'.
'Hello! This is a sample text. <br/>'.
'Hello! This is a sample text. <br/>'.
'Hello! This is a sample text. <br/>'.
'Hello! This is a sample text.';
$from = " is ";
$to = '<a href="http://www.google.com" > '.$from.' </a>';
echo $data;
$data = explode($from, $data);
echo "<br><br>";
echo $data[0];
$diff = 0;
for($i=1; $i<count($data); $i++){
$n = substr_count($data[$i-1], '<a ') + substr_count($data[$i-1], '<A ');
$m = substr_count($data[$i-1], '</a>') + substr_count($data[$i-1], '</A>');
$diff += $n-$m;
if($diff==0)
echo $to.$data[$i];
else
echo $from.$data[$i];
}
Lets say I have an array of bad words:
$badwords = array("one", "two", "three");
And random string:
$string = "some variable text";
How to create this cycle:
if (one or more items from the $badwords array is found in $string)
echo "sorry bad word found";
else
echo "string contains no bad words";
Example:
if $string = "one fine day" or "one fine day two of us did something", user should see sorry bad word found message.
If $string = "fine day", user should see string contains no bad words message.
As I know, you can't preg_match from array. Any advices?
How about this:
$badWords = array('one', 'two', 'three');
$stringToCheck = 'some stringy thing';
// $stringToCheck = 'one stringy thing';
$noBadWordsFound = true;
foreach ($badWords as $badWord) {
if (preg_match("/\b$badWord\b/", $stringToCheck)) {
$noBadWordsFound = false;
break;
}
}
if ($noBadWordsFound) { ... } else { ... }
Why do you want to use preg_match() here?
What about this:
foreach($badwords as $badword)
{
if (strpos($string, $badword) !== false)
echo "sorry bad word found";
else
echo "string contains no bad words";
}
If you need preg_match() for some reasons, you can generate regex pattern dynamically. Something like this:
$pattern = '/(' . implode('|', $badwords) . ')/'; // $pattern = /(one|two|three)/
$result = preg_match($pattern, $string);
HTH
If you want to check each word by exploding the string into words, you can use this:
$badwordsfound = count(array_filter(
explode(" ",$string),
function ($element) use ($badwords) {
if(in_array($element,$badwords))
return true;
}
})) > 0;
if($badwordsfound){
echo "Bad words found";
}else{
echo "String clean";
}
Now, something better came to my mind, how about replacing all the bad words from the array and check if the string stays the same?
$badwords_replace = array_fill(0,count($badwords),"");
$string_clean = str_replace($badwords,$badwords_replace,$string);
if($string_clean == $string) {
echo "no bad words found";
}else{
echo "bad words found";
}
Here is the bad word filter I use and it works great:
private static $bad_name = array("word1", "word2", "word3");
// This will check for exact words only. so "ass" will be found and flagged
// but not "classic"
$badFound = preg_match("/\b(" . implode(self::$bad_name,"|") . ")\b/i", $name_in);
Then I have another variable with select strings to match:
// This will match "ass" as well as "classic" and flag it
private static $forbidden_name = array("word1", "word2", "word3");
$forbiddenFound = preg_match("/(" . implode(self::$forbidden_name,"|") . ")/i", $name_in);
Then I run an if on it:
if ($badFound) {
return FALSE;
} elseif ($forbiddenFound) {
return FALSE;
} else {
return TRUE;
}
Hope this helps. Ask if you need me to clarify anything.
Lets say I have an array of bad words:
$badwords = array("one", "two", "three");
And random string:
$string = "some variable text";
How to create this cycle:
if (one or more items from the $badwords array is found in $string)
echo "sorry bad word found";
else
echo "string contains no bad words";
Example:
if $string = "one fine day" or "one fine day two of us did something", user should see sorry bad word found message.
If $string = "fine day", user should see string contains no bad words message.
As I know, you can't preg_match from array. Any advices?
How about this:
$badWords = array('one', 'two', 'three');
$stringToCheck = 'some stringy thing';
// $stringToCheck = 'one stringy thing';
$noBadWordsFound = true;
foreach ($badWords as $badWord) {
if (preg_match("/\b$badWord\b/", $stringToCheck)) {
$noBadWordsFound = false;
break;
}
}
if ($noBadWordsFound) { ... } else { ... }
Why do you want to use preg_match() here?
What about this:
foreach($badwords as $badword)
{
if (strpos($string, $badword) !== false)
echo "sorry bad word found";
else
echo "string contains no bad words";
}
If you need preg_match() for some reasons, you can generate regex pattern dynamically. Something like this:
$pattern = '/(' . implode('|', $badwords) . ')/'; // $pattern = /(one|two|three)/
$result = preg_match($pattern, $string);
HTH
If you want to check each word by exploding the string into words, you can use this:
$badwordsfound = count(array_filter(
explode(" ",$string),
function ($element) use ($badwords) {
if(in_array($element,$badwords))
return true;
}
})) > 0;
if($badwordsfound){
echo "Bad words found";
}else{
echo "String clean";
}
Now, something better came to my mind, how about replacing all the bad words from the array and check if the string stays the same?
$badwords_replace = array_fill(0,count($badwords),"");
$string_clean = str_replace($badwords,$badwords_replace,$string);
if($string_clean == $string) {
echo "no bad words found";
}else{
echo "bad words found";
}
Here is the bad word filter I use and it works great:
private static $bad_name = array("word1", "word2", "word3");
// This will check for exact words only. so "ass" will be found and flagged
// but not "classic"
$badFound = preg_match("/\b(" . implode(self::$bad_name,"|") . ")\b/i", $name_in);
Then I have another variable with select strings to match:
// This will match "ass" as well as "classic" and flag it
private static $forbidden_name = array("word1", "word2", "word3");
$forbiddenFound = preg_match("/(" . implode(self::$forbidden_name,"|") . ")/i", $name_in);
Then I run an if on it:
if ($badFound) {
return FALSE;
} elseif ($forbiddenFound) {
return FALSE;
} else {
return TRUE;
}
Hope this helps. Ask if you need me to clarify anything.
how write the script, which menchion the whole word, if it contain the keyword? example: keyword "fun", string - the bird is funny, result - the bird is * funny*. i do the following
$str = "my bird is funny";
$keyword = "fun";
$str = preg_replace("/($keyword)/i","<b>$1</b>",$str);
but it menshions only keyword. my bird is funny
Try this:
preg_replace("/\w*?$keyword\w*/i", "<b>$0</b>", $str)
\w*? matches any word characters before the keyword (as least as possible) and \w* any word characters after the keyword.
And I recommend you to use preg_quote to escape the keyword:
preg_replace("/\w*?".preg_quote($keyword)."\w*/i", "<b>$0</b>", $str)
For Unicode support, use the u flag and \p{L} instead of \w:
preg_replace("/\p{L}*?".preg_quote($keyword)."\p{L}*/ui", "<b>$0</b>", $str)
You can do the following:
$str = preg_replace("/\b([a-z]*${keyword}[a-z]*)\b/i","<b>$1</b>",$str);
Example:
$str = "Its fun to be funny and unfunny";
$keyword = 'fun';
$str = preg_replace("/\b([a-z]*${keyword}[a-z]*)\b/i","<b>$1</b>",$str);
echo "$str"; // prints 'Its <b>fun</b> to be <b>funny</b> and <b>unfunny</b>'
<?php
$str = "my bird is funny";
$keyword = "fun";
$look = explode(' ',$str);
foreach($look as $find){
if(strpos($find, $keyword) !== false) {
if(!isset($highlight)){
$highlight[] = $find;
} else {
if(!in_array($find,$highlight)){
$highlight[] = $find;
}
}
}
}
if(isset($highlight)){
foreach($highlight as $replace){
$str = str_replace($replace,'<b>'.$replace.'</b>',$str);
}
}
echo $str;
?>
Here by am added multi search in a string for your reference
$keyword = ".in#.com#dot.com#1#2#3#4#5#6#7#8#9#one#two#three#four#five#Six#seven#eight#nine#ten#dot.in#dot in#";
$keyword = implode('|',explode('#',preg_quote($keyword)));
$str = "PHP is dot .com the amazon.in 123455454546 dot in scripting language of choice.";
$str = preg_replace("/($keyword)/i","<b>$0</b>",$str);
echo $str;
Basically, since this is HTML, what you have to do is iterate over text nodes and split those containing the search string into up to three nodes (before match, after match and the highlighted match). If "after match" node exist, it must be processed too. Here is a PHP7 example using PHP DOM extension. The following function accepts preg_quoted UTF-8 search string (or regex-conpatible expression like apple|orange). It will enclose every match in a given tag with a given class.
function highlightTextInHTML($regex_compatible_text, $html, $replacement_tag = 'span', $replacement_class = 'highlight') {
$d = new DOMDocument('1.0','utf-8');
$d->loadHTML('<head><meta http-equiv="Content-Type" content="text/html; charset=utf-8"/></head>' . $html);
$xpath = new DOMXPath($d);
$process_node = function(&$node) use($regex_compatible_text, $replacement_tag, $replacement_class, &$d, &$process_node) {
$i = preg_match("~(?<before>.*?)(?<search>($regex_compatible_text)+)(?<after>.*)~ui", $node->textContent, $m);
if($i) {
$x = $d->createElement($replacement_tag);
$x->setAttribute('class', $replacement_class);
$x->textContent = $m['search'];
$parent_node = $node->parentNode;
$before = null;
$after = null;
if(!empty($m['after'])) {
$after = $d->createTextNode($m['after']);
$parent_node->replaceChild($after, $node);
$parent_node->insertBefore($x, $after);
} else {
$parent_node->replaceChild($x, $node);
}
if(!empty($m['before'])) {
$before = $d->createTextNode($m['before']);
$parent_node->insertBefore($before, $x);
}
if($after) {
$process_node($after);
}
}
};
$node_list = $xpath->query('//text()');
foreach ($node_list as $node) {
$process_node($node);
}
return preg_replace('~(^.*<body>)|(</body>.*$)~mis', '', $d->saveHTML());
}
Search and highlight the word in your string, text, body and paragraph:
<?php $body_text='This is simple code for highligh the word in a given body or text'; //this is the body of your page
$searh_letter = 'this'; //this is the string you want to search for
$result_body = do_Highlight($body_text,$searh_letter); // this is the result with highlight of your search word
echo $result_body; //for displaying the result
function do_Highlight($body_text,$searh_letter){ //function for highlight the word in body of your page or paragraph or string
$length= strlen($body_text); //this is length of your body
$pos = strpos($body_text, $searh_letter); // this will find the first occurance of your search text and give the position so that you can split text and highlight it
$lword = strlen($searh_letter); // this is the length of your search string so that you can add it to $pos and start with rest of your string
$split_search = $pos+$lword;
$string0 = substr($body_text, 0, $pos);
$string1 = substr($body_text,$pos,$lword);
$string2 = substr($body_text,$split_search,$length);
$body = $string0."<font style='color:#FF0000; background-color:white;'>".$string1." </font> ".$string2;
return $body;
} ?>